NCERT Solutions for Class 9 Maths Chapter 6 Exercise 6.3 Solutions

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CBSE X Related Questions

  • 1.

    Directions: In Question Numbers 19 and 20, a statement of Assertion (A) is followed by a statement of Reason (R).
    Choose the correct option from the following:
    (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
    (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
    (C) Assertion (A) is true, but Reason (R) is false.
    (D) Assertion (A) is false, but Reason (R) is true.

    Assertion (A): For any two prime numbers $p$ and $q$, their HCF is 1 and LCM is $p + q$.
    Reason (R): For any two natural numbers, HCF × LCM = product of numbers.

      • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
      • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
      • Assertion (A) is true, but Reason (R) is false.
      • Assertion (A) is false, but Reason (R) is true.

    • 2.
      Find the zeroes of the polynomial \(2x^2 + 7x + 5\) and verify the relationship between its zeroes and coefficients.


        • 3.
          In a right triangle ABC, right-angled at A, if $\sin B = \dfrac{1}{4}$, then the value of $\sec B$ is

            • 4
            • $\dfrac{\sqrt{15}}{4}$
            • $\sqrt{15}$
            • $\dfrac{4}{\sqrt{15}}$

          • 4.
            Prove that \(\dfrac{\sin \theta}{1 + \cos \theta} + \dfrac{1 + \cos \theta}{\sin \theta} = 2\csc \theta\)


              • 5.
                If the zeroes of the polynomial $ax^2 + bx + \dfrac{2a}{b}$ are reciprocal of each other, then the value of $b$ is

                  • $\dfrac{1}{2}$
                  • 2
                  • -2
                  • $-\dfrac{1}{2}$

                • 6.

                  From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
                  Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$

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