Difference Between Area and Perimeter: Definitions & Formulas

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Area and perimeter are the fundamental concepts in geometry used for measurement. Area is the extent of a two-dimensional figure whereas Perimeter is the measurement of the outer boundary of the two-dimensional figure. These parameters are extensively used to calculate the dimensions and properties of a given geometry. It is also used in many real-life applications like land surveying, aerial and urban planning.

Keyterms: Area, Perimeter, Geometry, Measurement, Dimension, Meter, Triangle, Square

Read More: Surface areas


Area

Area is the range of a specific region occupied by a two-dimensional geometric figure. Usually, in the SI system, the area is measured in meter square(m²). To understand the concept of an area, think about a stadium. Here, the area is the entire space where the players can play. Now to calculate the area, determine the shape of the area and use the appropriate formula.

Area

Area

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Area Formula

The area formula for different geometric figures is tabulated below.

Geometric figures Formula of area
Triangle ½ x b x h [b=base, h=height]
Square [a=side of a square]
Rectangular l x b [l=length, b=width]
Circle x (r)² [r=radius]
Semicircle ½ x x (r)² 
Rhombus a x h [a=side, h=height]
Parallelogram b x h [b=base, h=height]
Trapezium ½ x (a+b) x h [a=upper base of parallel side, b=lower base of parallel side, h=height]

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Perimeter

Perimeter is the boundary of two-dimensional closed path shapes. Perimeter mainly is the enclosed boundary or the sum of all the sides of a geometric figure. The unit used for Perimeter is meter(m). 

Perimeter

Perimeter

Bringing the previous example, if the question is about the perimeter of the circled cricket ground, you only need to calculate the value of the outline of the ground.

Also Read: Section Formula


Perimeter Formula 

The perimeter formula for different geometric figures are tabulated below.

Geometric figures Formula of Perimeter
Triangle 3a [a=side]
Square 4a [a=side]
Rectangular 2(l+b)  [l=length, b=width]
Circle 2 x x r [r=radius]
Semicircle x r + 2 x r [r=radius]
Rhombus 4a [a=side of a rhombus]
Parallelogram 2(b+a)  [b=parallel base, a=side of parallelogram]
Trapezium 4a [a=side]

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Difference between Area and Perimeter

The key differences between area and perimeter are tabulated below.

Parameters Area Perimeter
Definition Area is the range of space occupied by an enclosed two-dimensional geometric figure. Perimeter is the length of the outline that encloses any two-dimensional geometric figure.
Unit The area is measured in square units. ( Square meter - m²) Perimeter is measured in linear units. (Meter - m)
Space Area is the internal space of a geometric figure or shape.  Perimeter is the outline or boundary of a shape.
Example Area of a circular cricket ground in stadium The fence of farming land.

Also Read: Nature of Roots of Quadratic Equation


Things to Remember

  • Area is the region that is occupied under any kind of two-dimensional geometric shape. 
  • The units of area are expressed in terms of meter square or centimetre square.
  • Perimeter is the outer boundary of any geometric shape.
  • The unit of the perimeter is linear.

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Sample Questions

Ques: Find out the area and perimeter of a rectangle whose length is 24 meters and width is 7 meters. [2 marks]

Ans: Given, the length of the rectangular= 24 meter

The width of the rectangular= 7 meter

∴ The area of the rectangle= length width= 24 7 = 168 m²

Ques: Write down the difference between Area and Perimeter. [3 marks]

Ans: 

Area Perimeter
Area is the range of space occupied by an enclosed two-dimensional geometric figure. Perimeter is the length of the outline that encloses any two-dimensional geometric figure.
The area is measured in square units. ( Square meter - m²) Perimeter is measured in linear units. (Meter - m)
Area is the internal space of a geometric figure or shape.  Perimeter is the outline or boundary of a shape.
Area of a circular cricket ground in stadium The fence of farming land.

Ques: What is an area in geometry? Write down the formula of area for circle and parallelogram. [3 marks]

Ans: Area is the range of a specific region occupied by two-dimensional geometric figures.

The area of circle= x (radius)²

The area of parallelogram= base x height 

Ques: What is Perimeter in geometry? Write down the perimeter of the semicircle and square. [3 marks]

Ans: Perimeter is the outline which encloses the boundary or the sum of all the sides of a one or two-dimensional geometric figure.

The perimeter of the semicircle is x radius + 2 x radius.

The perimeter of the square is 4 x side.

Ques: What is the perimeter or circumference of a circle of diameter of 20 meter. Calculate the area of the circle. [2 marks]

Ans: The diameter of the circle= 20 meter

∴ The radius(r) = 20/2 = 10 meter

∴ The perimeter of the circle = 2r= 210 meter = 62.83 m

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Ques: A circle is formed using a ribbon which has a radius of 28 cm. Let’s say Rohan wants to form a square using the same ribbon, determine the length of the side of the square formed by Rohan using the ribbon. [4 marks]

Ans: The radius of the circle= 28 cm

Now, since the circle is formed using ribbon,

 ∴ length of the ribbon = the perimeter of the circle

 ∴ The length of the ribbon = 2r=(2x 28) cm

And again the ribbon will form the square of 4 sides.

Hence, 4side=(2x 28)

∴ The side of the square=2284= 43.98 cm

Ques: A rectangle ground has a width that is thrice of its length. If the length is 128 cm, what will be the cost of fencing the rectangle at a cost of 20 rupees per square meter. [3 marks]

Ans: The length of the rectangular place= 128 cm

Given, Width = 3length= 3128 cm = 384 cm

∴The area of the rectangular place = 384128 = 49152 cm² = 49152/100 meter² = 491.52 meter square

Now, 1 square meter costs 20 rupees to fence.

∴491.52 square meter will cost= 491.52 20= 9830.4 rupees to fence.

Ques: A lawn that has 400 cm length and 138 cm width needs to be covered with tiles. How many tiles with dimensions 5 cm X 12 cm will be needed to cover the lawn. [3 marks]

Ans: The length of the lawn= 400 cm

The width of lawn= 138 cm

 ∴The area of the lawn= 400 x 138 = 55200 cm²

A tile of dimension 5 cm x 12 cm can cover= 5 x 12 = 60 cm² of area.

∴The lawn needs = 55200/60 = 920 tiles to cover it.

Also Read: Triangles Important Questions Class 10

Ques: Find the perimeter and area of the semi-circle below. [3 marks]
Find the perimeter and area of the semi-circle below

Ans: The diameter of the semi circle= 14 cm

∴The radius = 14/2 = 7 cm

∴The perimeter of the semi circle= r+2r= 22/7 x 7 + 2 x 7 = 36 cm

∴The area of the semi circle= ½ x x r² = ½ x 22/7 x 7 x 7=77 cm²

Ques: Find out the area and perimeter of a rectangle whose length is 56 meters and width is 30 meters. [2 marks]

Ans: Given, the length of the rectangular= 56 meter

The width of the rectangular= 30 meter

∴ The area of the rectangle= length width= 5630 = 1680 m²

Perimeter = 2(l+b)

Perimeter = 2 (56 + 30)

Perimeter = 172 m

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CBSE X Related Questions

1.
Which of the following are APs? If they form an AP, find the common difference d and write three more terms.
(i) 2, 4, 8, 16, . . . .
(ii) \(2, \frac{5}{2},3,\frac{7}{2}\), . . . .
(iii) – 1.2, – 3.2, – 5.2, – 7.2, . . . .
(iv) – 10, – 6, – 2, 2, . . .
(v) 3, \(3 + \sqrt{2} , 3 + 3\sqrt{2} , 3 + 3 \sqrt{2}\) . . . .
(vi) 0.2, 0.22, 0.222, 0.2222, . . . .
(vii) 0, – 4, – 8, –12, . . . .
(viii) \(\frac{-1}{2}, \frac{-1}{2}, \frac{-1}{2}, \frac{-1}{2}\), . . . .
(ix) 1, 3, 9, 27, . . . .
(x) a, 2a, 3a, 4a, . . . .
(xi) a, \(a^2, a^3, a^4,\)  . . . .
(xii) \(\sqrt{2}, \sqrt{8} , \sqrt{18} , \sqrt {32}\) . . . .
(xiii) \(\sqrt {3}, \sqrt {6}, \sqrt {9} , \sqrt {12}\) . . . . .
(xiv) \(1^2 , 3^2 , 5^2 , 7^2\), . . . .
(xv) \(1^2 , 5^2, 7^2, 7^3\), . . . .

      2.
      A vessel is in the form of an inverted cone. Its height is 8 cm and the radius of its top, which is open, is 5 cm. It is filled with water up to the brim. When lead shots, each of which is a sphere of radius 0.5 cm are dropped into the vessel, one-fourth of the water flows out. Find the number of lead shots dropped in the vessel.

          3.
          Find the sums given below :
          1. \(7 + 10\frac 12+ 14 + ....... + 84\)
          2. \(34 + 32 + 30 + ....... + 10\)
          3. \(–5 + (–8) + (–11) + ....... + (–230)\)

              4.
              Check whether \(6n\) can end with the digit \(0\) for any natural number \(n\).

                  5.
                  An umbrella has 8 ribs which are equally spaced (see Fig. 11.10). Assuming umbrella to be a flat circle of radius 45 cm, find the area between the two consecutive ribs of the umbrella.
                  An umbrella has 8 ribs which are equally spaced

                      6.
                      A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from 30° to 60° as he walks towards the building. Find the distance he walked towards the building.

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