Area of Square Using Diagonal: Formula, Relation & Derivation

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Area of the square using diagonal means measuring area of a square through two nonadjacent vertices of the square. A diagonal line means a line that can be stretched from one corner of a square to the other corner by its center. The diagonals of a square are always equal in size and they bisect each other at right angles. To calculate a polygon’s diagonals, the same formula of the square is used. When the side length of a square is known then the formula for the diagonal of a square is used to measure the length of the diagonal.

Also Read: Surface Areas and Volumes

Keyterms: Square, Line, Polygon, Right angle, Side length, Diagonal, congruent isosceles

Read More: Geometry


Diagonal of the Square

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The lines that join the two opposite vertices of a square are called diagonal. A square has two diagonals. 

Diagonal Of a Square

Diagonal Of a Square

The properties of diagonal are the following:

  • The diagonals of a square are the perpendicular bisectors of each other.
  • They are equal in length.
  • Diagonals divide the square into two right-angled triangles which are congruent isosceles.

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How to Derive the Area of a Square Using Diagonal?

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The most common way to find out the area of a square is to square the length of its sides. Hence, a correct measure of the length of the sides of the square is necessary. 

Area of a Square

Area of a Square

When the sides of a square are replaced by the diagonals it is very important to find out the relation between the diagonal of a square and its side.

Also Read: Nature of Roots of Quadratic Equation


Relation Between the Diagonal and the Side of a Square

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A square can be divided into two right-angled triangles in which the triangle’s hypotenuse is equal to the diagonals of the square. Pythagoras theorem can be applied to show the relation between the sides of the right-angled triangle and the hypotenuse. Therefore, it also represents the relation between the diagonal of a square.

Diagonal and side of a square

Diagonal and side of a square

Consider the angle θ, making an angle with the side AB and the diagonal AC as shown in the image.

Sin θ = a/ d ….(1)

We know that, for a square, all the angles are right angles.

Since a diagonal divides the angle equally,

We can say that θ = 45°

Substituting in Eq(1),

Sin 45° = a/ d

As Sin 45° = 1/√2

1/√2 = a/ d

d = √2 x a

Therefore, 

Diagonal = √2 x side

Also Read: Section Formula


Measuring the Area of a Square Using Diagonal

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Area of square = side × side

When diagonal is equal to √2 × side

Then side = 1/ √2 diagonal.

The formula of area of the square using diagonal =

 1/ √2 diagonal × 1/ √2 diagonal

=1/2 (diagonal)2

Area of square = ½ d2

The area of the square using diagonal is =½ d2

Read More: Triangle


Things to Remember

  • A diagonal line means a line that can be stretched from one corner of a square to the other corner by its center.
  • The most common way to find out the area of a square is to square the length of its sides.
  • Pythagoras theorem can be applied to show the relation between the sides of the right-angled triangle and the hypotenuse.
  • The formula of area of the square using diagonal is ½ d2.
  • The length of the diagonal can be calculated by using the formula, Diagonal = √2 x side.

Also Read:


Sample Questions

Ques. Write the diagonal formula of the square. (2 marks)

Ans. The diagonal formula of the square is d = a√2. Here, ‘d’ represents diagonal, and ‘a’ represents the side of the square. This formula is derived from the Pythagoras Theorem.

Ques. How to find out the length of the diagonal of a square? (2 marks)

Ans. The length of the diagonal of a square can be found by multiplying the length of one side by the square root of 2. When the length of one side is x, then the diagonals of the square cross (intersect) at a 90° angle.

Ques. The angles of a quadrilateral are in the ratio of 2 : 3 : 5 : 8. Find the measure of each angle. (2 marks)

Ans. Sum of all interior angles of a quadrilateral = 360°

Let the angles of the quadrilateral be 2x°, 3x°, 5x° and 8x°.

2x + 3x + 5x + 8x = 360°

⇒ 18x = 360°

⇒ x = 20°

Hence the angles are

2 × 20 = 40°,

3 × 20 = 60°,

5 × 20 = 100°

and 8 × 20 = 160°

Ques. What is the area of a square? (2 marks)

Ans. A square’s all the sides are of equal measure. As all the sides are equal, the area of a square would be length times width that is equal to side × side. Therefore, the area of a square side square.

Ques. Can we say the diagonal of a square is equal to its sides? (2 marks)

Ans. No, the diagonal of a square is not equal to its sides. The formula to calculate the diagonal of a square is (d) = √2 × s, here, ‘s’ represents the side of the square.

Ques. What will be the area of a square of 4 cm? (2 marks)

Ans. Consider the side-length of the square is 4 cm. Hence, using the counting squares method the area of the square will be 16 cm2.

Ques. What are the relations between diagonal and side of a square? (2 marks)

Ans. The relations between diagonal and side of a square is given by the formula,

Diagonal =√2 x a

Ques. How do you find the total number of diagonals in a square? (2 marks)

Ans. To find out the total number of diagonals in a square you need to multiply the number of diagonals per vertex (n-3) by the total number of vertices, n, and then divide it by 2.

Ques. In a square, how many diagonals are there? (2 marks)

Ans. In a square, there are two diagonals of equal length. These diagonals intersect at the center of the square. A pentagon of regular size has five diagonals and all these diagonals have the same length.

Ques. In the parallelogram given alongside if m∠Q = 110°, find all the other angles.  (2 marks)

Ans. Given m∠Q = 110°

Then m∠S = 110° (Opposite angles are equal)

Since ∠P and ∠Q are supplementary.

Then m∠P + m∠Q = 180°

⇒ m∠P + 110° = 180°

⇒ m∠P = 180° – 110° = 70°

⇒ m∠P = m∠R = 70° (Opposite angles)

Hence m∠P = 70, m∠R = 70°

and m∠S = 110°

Ques. ABCD is a rhombus. Find the values of x, y and z.  (2 marks)

Ans. AB = BC (Sides of a rhombus)

x = 13 cm.

Since the diagonals of a rhombus bisect each other

z = 5 and y = 12

Hence, x = 13 cm, y = 12 cm and z = 5 cm.

Ques. Length and breadth of a rectangular wire are 9 cm and 7 cm respectively. If the wire is bent into a square, find the length of its side.  (2 marks)

Ans. Perimeter of the rectangle = 2 [length + breadth]

= 2[9 + 7] = 2 × 16 = 32 cm.

Now perimeter of the square = Perimeter of rectangle = 32 cm.

Side of the square = 

32/4 = 8 cm.

Hence, the length of the side of the square = 8 cm.

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CBSE X Related Questions

1.
A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from 30° to 60° as he walks towards the building. Find the distance he walked towards the building.

      2.

      Form the pair of linear equations for the following problems and find their solution by substitution method.

      (i) The difference between two numbers is 26 and one number is three times the other. Find them.

      (ii) The larger of two supplementary angles exceeds the smaller by 18 degrees. Find them.

      (iii) The coach of a cricket team buys 7 bats and 6 balls for Rs 3800. Later, she buys 3 bats and 5 balls for Rs 1750. Find the cost of each bat and each ball.

      (iv) The taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km, the charge paid is Rs 105 and for a journey of 15 km, the charge paid is Rs 155. What are the fixed charges and the charge per km? How much does a person have to pay for travelling a distance of 25 km.

      (v) A fraction becomes\(\frac{ 9}{11}\), if 2 is added to both the numerator and the denominator. If, 3 is added to both the numerator and the denominator it becomes \(\frac{5}{6}\). Find the fraction.

      (vi) Five years hence, the age of Jacob will be three times that of his son. Five years ago, Jacob’s age was seven times that of his son. What are their present ages?

          3.

          The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them

          Monthly consumption 
          (in units)

           Number of consumers

          65 - 85 

          4

          85 - 105

          5

          105 - 125

          13

          125 - 145

          20

          145 - 165

          14

          165 - 185

          8

          185 - 205

          4

              4.
              Which of the following pairs of linear equations are consistent/inconsistent? If consistent, obtain the solution graphically: (i) \(x + y = 5\),\( 2x + 2y = 10\) (ii)\( x – y = 8 , 3x – 3y = 16\) (iii) \(2x + y – 6 = 0\) , \(4x – 2y – 4 = 0\) (iv) \(2x – 2y – 2 = 0,\) \( 4x – 4y – 5 = 0\)

                  5.

                  Solve the following pair of linear equations by the substitution method. 
                  (i) x + y = 14 
                      x – y = 4   

                  (ii) s – t = 3 
                      \(\frac{s}{3} + \frac{t}{2}\) =6 

                  (iii) 3x – y = 3 
                        9x – 3y = 9

                  (iv) 0.2x + 0.3y = 1.3 
                       0.4x + 0.5y = 2.3 

                  (v)\(\sqrt2x\) + \(\sqrt3y\)=0
                      \(\sqrt3x\) - \(\sqrt8y\) = 0

                  (vi) \(\frac{3x}{2} - \frac{5y}{3}\) =-2,
                      \(\frac{ x}{3} + \frac{y}{2}\) = \(\frac{ 13}{6}\)

                      6.
                      The angle of elevation of the top of a building from the foot of the tower is 30° and the angle of elevation of the top of the tower from the foot of the building is 60°. If the tower is 50 m high, find the height of the building.

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