NCERT Solutions For Class 7 Science Chapter 15 : Visualizing Solid Shapes

NCERT Solutions for class 7 Mathematics Chapter 15 Visualizing Solid Shapes are provided in the article below. Plane shapes have two measurements like length and breadth which are called dimensions of a plane and therefore they are called two-dimensional shapes whereas a solid object has three measurements like length, breadth, height or depth. Hence, they are called three-dimensional shapes or 3-D shapes. Some of the important topics in this chapter include:

Download: NCERT Solutions for Class 7 Mathematics Chapter 15 pdf

NCERT Solutions for Class 7 Mathematics Chapter 15

NCERT Solutions for Class 7 Mathematics Chapter 15 Visualizing Solid Shapes are given below.

NCERT Solution class 7 mathematics chapter 15

Class 7 Maths Chapter 15 Visualising Solid Shapes – Important Topics

Three dimensional figure: Three-dimensional figures are those which consist of length, breadth and height.

Some of the important three dimensional figures include:

Cube
Cuboid
Cone
Cylinder
Pyramid

Volume of Cube – a³

Volume of Cuboid – length x breadth x height

Volume of Cone – 1/3 $\pi$r²h

Volume of Cylinder – $\pi$r²h

NCERT Solutions for Class 7 Maths Chapter 15 Exercises

NCERT Solutions for Class 7 Maths Chapter 15 Visualising Solid Shapes Exercises are given below.

Read More:

Visualising Solid Shapes MCQ	Measurement of Objects	Isomeric Sketch
Rectangular Pyramid	3D Shapes	Hexagon Formula

Read More:

NCERT Solutions for Class 7 Maths	Number System	Geometry
Arithmetics	Basic Maths	Maths Formulas

CBSE X Related Questions

1.
In a right triangle ABC, right-angled at A, if $\sin B = \dfrac{1}{4}$, then the value of $\sec B$ is
- 4
- $\dfrac{\sqrt{15}}{4}$
- $\sqrt{15}$
- $\dfrac{4}{\sqrt{15}}$
View Solution
2.
$\alpha, \beta$ are zeroes of the polynomial $3x^2 - 8x + k$. Find the value of $k$, if $\alpha^2 + \beta^2 = \dfrac{40}{9}$
View Solution
3.
Directions: In Question Numbers 19 and 20, a statement of Assertion (A) is followed by a statement of Reason (R).
Choose the correct option from the following:
(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
(B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
(C) Assertion (A) is true, but Reason (R) is false.
(D) Assertion (A) is false, but Reason (R) is true.
Assertion (A): For any two prime numbers $p$ and $q$, their HCF is 1 and LCM is $p + q$.
Reason (R): For any two natural numbers, HCF × LCM = product of numbers.
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
4.
From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$
View Solution
5.
Find the zeroes of the polynomial $2x^2 + 7x + 5$ and verify the relationship between its zeroes and coefficients.
View Solution
6.
If the zeroes of the polynomial $ax^2 + bx + \dfrac{2a}{b}$ are reciprocal of each other, then the value of $b$ is
- $\dfrac{1}{2}$
- 2
- -2
- $-\dfrac{1}{2}$
View Solution

View All

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NCERT Solutions For Class 7 Science Chapter 15 : Visualizing Solid Shapes

Download: NCERT Solutions for Class 7 Mathematics Chapter 15 pdf

NCERT Solutions for Class 7 Mathematics Chapter 15

Class 7 Maths Chapter 15 Visualising Solid Shapes – Important Topics

NCERT Solutions for Class 7 Maths Chapter 15 Exercises

CBSE X Related Questions

1.
In a right triangle ABC, right-angled at A, if $\sin B = \dfrac{1}{4}$, then the value of $\sec B$ is

2.
\(\alpha, \beta\) are zeroes of the polynomial \(3x^2 - 8x + k\). Find the value of \(k\), if \(\alpha^2 + \beta^2 = \dfrac{40}{9}\)

4.
From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$

5.
Find the zeroes of the polynomial \(2x^2 + 7x + 5\) and verify the relationship between its zeroes and coefficients.

6.
If the zeroes of the polynomial $ax^2 + bx + \dfrac{2a}{b}$ are reciprocal of each other, then the value of $b$ is

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NCERT Solutions For Class 7 Science Chapter 15 : Visualizing Solid Shapes

​Download: NCERT Solutions for Class 7 Mathematics Chapter 15 pdf

NCERT Solutions for Class 7 Mathematics Chapter 15

Class 7 Maths Chapter 15 Visualising Solid Shapes – Important Topics

NCERT Solutions for Class 7 Maths Chapter 15 Exercises

CBSE X Related Questions

1.In a right triangle ABC, right-angled at A, if $\sin B = \dfrac{1}{4}$, then the value of $\sec B$ is

2.\(\alpha, \beta\) are zeroes of the polynomial \(3x^2 - 8x + k\). Find the value of \(k\), if \(\alpha^2 + \beta^2 = \dfrac{40}{9}\)

4.From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$

5.Find the zeroes of the polynomial \(2x^2 + 7x + 5\) and verify the relationship between its zeroes and coefficients.

6.If the zeroes of the polynomial $ax^2 + bx + \dfrac{2a}{b}$ are reciprocal of each other, then the value of $b$ is

Comments

SUBSCRIBE TO OUR NEWS LETTER

Download: NCERT Solutions for Class 7 Mathematics Chapter 15 pdf

1.
In a right triangle ABC, right-angled at A, if $\sin B = \dfrac{1}{4}$, then the value of $\sec B$ is

2.
\(\alpha, \beta\) are zeroes of the polynomial \(3x^2 - 8x + k\). Find the value of \(k\), if \(\alpha^2 + \beta^2 = \dfrac{40}{9}\)

4.
From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$

5.
Find the zeroes of the polynomial \(2x^2 + 7x + 5\) and verify the relationship between its zeroes and coefficients.

6.
If the zeroes of the polynomial $ax^2 + bx + \dfrac{2a}{b}$ are reciprocal of each other, then the value of $b$ is