NCERT Solutions for Class 7 Mathematics Chapter 14: Symmetry

NCERT Solutions for class 7 Mathematics Chapter 14 Symmetry are provided in the article below. If two or more parts of a figure are identical after folding or flipping then it is said to be symmetry. To be symmetrical the two halves of a shape must be of same shape and size. If the shape is not symmetrical then it is said to be asymmetrical. Some of the important topics in Symmetry chapter include:

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 14 pdf

NCERT Solutions for Class 7 Mathematics Chapter 14

NCERT Solutions for Class 7 Mathematics Chapter 14 Symmetry is given below.

NCERT Solutions for Class 7 Mathematics

Symmetry: A figure is said to be symmetrical if one half of the figure is a mirror image of the other.

Depending on the lines of symmetry, symmetrical figures can be classified into:

No Line of Symmetry (for the asymmetrical figure)
One Line of Symmetry
Two Line of Symmetry
Multiple (more than 2) Line of Symmetry
Infinite Line of Symmetry

NCERT Solutions for Class 7 Maths Chapter 14 Exercises

NCERT Solutions for Class 7 Maths Chapter 14 Symmetry Exercises is given below.

Read More:

Asymmetric Relation	Line of Symmetry
Line of Symmetry in a Rectangle	Line of Symmetry in Parallelogram

Class 7 Maths Guide:

NCERT Solutions for Class 7 Maths	Number System	Geometry
Arithmetics	Basic Maths	Maths Formulas

CBSE X Related Questions

1.
Which of the following pairs of linear equations are consistent/inconsistent? If consistent, obtain the solution graphically: (i) \(x + y = 5\),\( 2x + 2y = 10\) (ii)\( x – y = 8 , 3x – 3y = 16\) (iii) \(2x + y – 6 = 0\) , \(4x – 2y – 4 = 0\) (iv) \(2x – 2y – 2 = 0,\) \( 4x – 4y – 5 = 0\)

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2.
A vessel is in the form of an inverted cone. Its height is 8 cm and the radius of its top, which is open, is 5 cm. It is filled with water up to the brim. When lead shots, each of which is a sphere of radius 0.5 cm are dropped into the vessel, one-fourth of the water flows out. Find the number of lead shots dropped in the vessel.

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3.
An umbrella has 8 ribs which are equally spaced (see Fig. 11.10). Assuming umbrella to be a flat circle of radius 45 cm, find the area between the two consecutive ribs of the umbrella.

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4.
Solve the following pair of linear equations by the substitution method.
(i) x + y = 14
x – y = 4
(ii) s – t = 3
  \(\frac{s}{3} + \frac{t}{2}\) =6
(iii) 3x – y = 3
9x – 3y = 9
(iv) 0.2x + 0.3y = 1.3
0.4x + 0.5y = 2.3
(v)\(\sqrt2x\) + \(\sqrt3y\)=0
  \(\sqrt3x\) - \(\sqrt8y\) = 0
(vi) \(\frac{3x}{2} - \frac{5y}{3}\) =-2,
  \(\frac{ x}{3} + \frac{y}{2}\) = \(\frac{ 13}{6}\)

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5.
Prove the following identities, where the angles involved are acute angles for which the expressions are defined:\(\frac{(\text{1 + tan² A})}{(\text{1 + cot² A})} = (\frac{\text{1 - tan A }}{\text{ 1 - cot A}})^²= \text{tan² A}\)

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6.
The lengths of 40 leaves of a plant are measured correct to the nearest millimetre, and the data obtained is represented in the following table :
Length (in mm)
Number of leaves
118 - 126
3
127 - 135
5
136 - 144
9
145 - 153
12
154 - 162
5
163 - 171
4
172 - 180
2
Find the median length of the leaves.
(Hint : The data needs to be converted to continuous classes for finding the median, since the formula assumes continuous classes. The classes then change to 117.5 - 126.5, 126.5 - 135.5, . . ., 171.5 - 180.5.)

Length (in mm)	Number of leaves
118 - 126	3
127 - 135	5
136 - 144	9
145 - 153	12
154 - 162	5
163 - 171	4
172 - 180	2

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NCERT Solutions for Class 7 Mathematics Chapter 14: Symmetry

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 14 pdf

NCERT Solutions for Class 7 Mathematics Chapter 14

NCERT Solutions for Class 7 Mathematics

NCERT Solutions for Class 7 Maths Chapter 14 Exercises

CBSE X Related Questions

3.
An umbrella has 8 ribs which are equally spaced (see Fig. 11.10). Assuming umbrella to be a flat circle of radius 45 cm, find the area between the two consecutive ribs of the umbrella.

5.
Prove the following identities, where the angles involved are acute angles for which the expressions are defined:\(\frac{(\text{1 + tan² A})}{(\text{1 + cot² A})} = (\frac{\text{1 - tan A }}{\text{ 1 - cot A}})^²= \text{tan² A}\)

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NCERT Solutions for Class 7 Mathematics Chapter 14: Symmetry

Download PDF: NCERT Solutions for Class 7 Mathematics Chapter 14 pdf

NCERT Solutions for Class 7 Mathematics Chapter 14

NCERT Solutions for Class 7 Mathematics

NCERT Solutions for Class 7 Maths Chapter 14 Exercises

CBSE X Related Questions

3. An umbrella has 8 ribs which are equally spaced (see Fig. 11.10). Assuming umbrella to be a flat circle of radius 45 cm, find the area between the two consecutive ribs of the umbrella.

5. Prove the following identities, where the angles involved are acute angles for which the expressions are defined:\(\frac{(\text{1 + tan² A})}{(\text{1 + cot² A})} = (\frac{\text{1 - tan A }}{\text{ 1 - cot A}})^²= \text{tan² A}\)

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3.
An umbrella has 8 ribs which are equally spaced (see Fig. 11.10). Assuming umbrella to be a flat circle of radius 45 cm, find the area between the two consecutive ribs of the umbrella.

5.
Prove the following identities, where the angles involved are acute angles for which the expressions are defined:\(\frac{(\text{1 + tan² A})}{(\text{1 + cot² A})} = (\frac{\text{1 - tan A }}{\text{ 1 - cot A}})^²= \text{tan² A}\)