NCERT Solutions for Class 7 Mathematics Chapter 14: Symmetry

NCERT Solutions for class 7 Mathematics Chapter 14 Symmetry are provided in the article below. If two or more parts of a figure are identical after folding or flipping then it is said to be symmetry. To be symmetrical the two halves of a shape must be of same shape and size. If the shape is not symmetrical then it is said to be asymmetrical. Some of the important topics in Symmetry chapter include:

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NCERT Solutions for Class 7 Mathematics Chapter 14

NCERT Solutions for Class 7 Mathematics Chapter 14 Symmetry is given below.

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NCERT Solutions for Class 7 Mathematics

Symmetry: A figure is said to be symmetrical if one half of the figure is a mirror image of the other.

Depending on the lines of symmetry, symmetrical figures can be classified into:

  • No Line of Symmetry (for the asymmetrical figure)
  • One Line of Symmetry 
  • Two Line of Symmetry 
  • Multiple (more than 2) Line of Symmetry
  • Infinite Line of Symmetry

NCERT Solutions for Class 7 Maths Chapter 14 Exercises

NCERT Solutions for Class 7 Maths Chapter 14 Symmetry Exercises is given below.

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Class 7 Maths Guide:

CBSE X Related Questions

  • 1.
    In the given figure, \(AB \parallel EF\). If \(AB = 24\) cm, \(EF = 36\) cm and \(DA = 7\) cm, then \(AE\) equals

      • \(2.5\) cm
      • \(10.5\) cm
      • \(3.5\) cm
      • \(\frac{14}{3}\) cm

    • 2.
      If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

        • \(4 \text{ cm}\)
        • \(4\sqrt{2} \text{ cm}\)
        • \(8 \text{ cm}\)
        • \(2\sqrt{2} \text{ cm}\)

      • 3.
        There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

          • 144
          • 2
          • 420
          • 272

        • 4.
          D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.


            • 5.
              In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.


                • 6.
                  The natural number 1 is :

                    • a prime number.
                    • a composite number.
                    • prime as well as composite.
                    • neither prime nor composite.

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