NCERT Solutions for Class 7 Mathematics Chapter 10: Practical Geometry

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NCERT Solutions for Class 7 Mathematics Chapter 10 Practical Geometry are provided in the article below. Practical geometry is an important branch of geometry which deals with the study of the size, positions, shapes as well as dimensions of objects. Whether you have to draw a line segment or measure it, draw a circle or arcs, draw an angle, etc. it can easily be possible with the help of geometrical tools. Some of the important topics in Practical Geometry chapter are:

Download: NCERT Solutions for Class 7 Mathematics Chapter 10 pdf

NCERT Solutions for Class 7 Mathematics Chapter 10

NCERT Solutions for Class 7 Mathematics Chapter 10 Practical Geometry is given below.

Class 7 Maths Chapter 10 Practical Geometry – Important Topics

Practical Geometry: It is the practical study of constructing geometrical figures.

Perpendicular Bisector: It is the line that is constructed by the use of angles to bisect a line segment into two equal halves.

Angle Bisector: It is a line that is constructed to bisect an angle into two equal halves.

Example: Make a line AB and place a point P on the outside of it. Draw a line CD that runs parallel to AB and passes through point P.

Ans.

Draw an AB line.
Join PQ with a point Q on AB and a point P outside AB.
Draw on the arc to cut AB at X and PQ at Z with Q as the centre and any radius.
Draw an arc cutting QP at Y with P as the centre and the same radius.
Draw an arc to cut the preceding arc at E, with Y as the centre and the radius equal to XZ.
To get the desired line, join PE and produce it on both sides.

NCERT Solutions for Class 7 Maths Chapter 10 Exercises

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercises are given below.

Read More:

Construction of Rhombus	Perpendicular Lines	ASA Triangles Construction
SAS Triangles Construction	RHS Triangles Construction	Perimeter two angles constructing triangles

Class 7 Maths Guides:

NCERT Solutions for Class 7 Maths	Number System	Geometry
Arithmetics	Basic Maths	Maths Formulas

CBSE X Related Questions

1.
Which of the following pairs of linear equations are consistent/inconsistent? If consistent, obtain the solution graphically: (i) \(x + y = 5\),\( 2x + 2y = 10\) (ii)\( x – y = 8 , 3x – 3y = 16\) (iii) \(2x + y – 6 = 0\) , \(4x – 2y – 4 = 0\) (iv) \(2x – 2y – 2 = 0,\) \( 4x – 4y – 5 = 0\)

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2.
An umbrella has 8 ribs which are equally spaced (see Fig. 11.10). Assuming umbrella to be a flat circle of radius 45 cm, find the area between the two consecutive ribs of the umbrella.

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3.
Solve the following pair of linear equations by the substitution method.
(i) x + y = 14
x – y = 4
(ii) s – t = 3
  \(\frac{s}{3} + \frac{t}{2}\) =6
(iii) 3x – y = 3
9x – 3y = 9
(iv) 0.2x + 0.3y = 1.3
0.4x + 0.5y = 2.3
(v)\(\sqrt2x\) + \(\sqrt3y\)=0
  \(\sqrt3x\) - \(\sqrt8y\) = 0
(vi) \(\frac{3x}{2} - \frac{5y}{3}\) =-2,
  \(\frac{ x}{3} + \frac{y}{2}\) = \(\frac{ 13}{6}\)

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4.
A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from 30° to 60° as he walks towards the building. Find the distance he walked towards the building.

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5.
Prove the following identities, where the angles involved are acute angles for which the expressions are defined:\(\frac{(\text{1 + tan² A})}{(\text{1 + cot² A})} = (\frac{\text{1 - tan A }}{\text{ 1 - cot A}})^²= \text{tan² A}\)

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6.
A vessel is in the form of an inverted cone. Its height is 8 cm and the radius of its top, which is open, is 5 cm. It is filled with water up to the brim. When lead shots, each of which is a sphere of radius 0.5 cm are dropped into the vessel, one-fourth of the water flows out. Find the number of lead shots dropped in the vessel.

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NCERT Solutions for Class 7 Mathematics Chapter 10: Practical Geometry

Download: NCERT Solutions for Class 7 Mathematics Chapter 10 pdf

NCERT Solutions for Class 7 Mathematics Chapter 10

Class 7 Maths Chapter 10 Practical Geometry – Important Topics

NCERT Solutions for Class 7 Maths Chapter 10 Exercises

CBSE X Related Questions

2.
An umbrella has 8 ribs which are equally spaced (see Fig. 11.10). Assuming umbrella to be a flat circle of radius 45 cm, find the area between the two consecutive ribs of the umbrella.

4.
A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from 30° to 60° as he walks towards the building. Find the distance he walked towards the building.

5.
Prove the following identities, where the angles involved are acute angles for which the expressions are defined:\(\frac{(\text{1 + tan² A})}{(\text{1 + cot² A})} = (\frac{\text{1 - tan A }}{\text{ 1 - cot A}})^²= \text{tan² A}\)

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NCERT Solutions for Class 7 Mathematics Chapter 10: Practical Geometry

Download: NCERT Solutions for Class 7 Mathematics Chapter 10 pdf

NCERT Solutions for Class 7 Mathematics Chapter 10

Class 7 Maths Chapter 10 Practical Geometry – Important Topics

NCERT Solutions for Class 7 Maths Chapter 10 Exercises

CBSE X Related Questions

2. An umbrella has 8 ribs which are equally spaced (see Fig. 11.10). Assuming umbrella to be a flat circle of radius 45 cm, find the area between the two consecutive ribs of the umbrella.

4. A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from 30° to 60° as he walks towards the building. Find the distance he walked towards the building.

5. Prove the following identities, where the angles involved are acute angles for which the expressions are defined:\(\frac{(\text{1 + tan² A})}{(\text{1 + cot² A})} = (\frac{\text{1 - tan A }}{\text{ 1 - cot A}})^²= \text{tan² A}\)

Comments

SUBSCRIBE TO OUR NEWS LETTER

2.
An umbrella has 8 ribs which are equally spaced (see Fig. 11.10). Assuming umbrella to be a flat circle of radius 45 cm, find the area between the two consecutive ribs of the umbrella.

4.
A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from 30° to 60° as he walks towards the building. Find the distance he walked towards the building.

5.
Prove the following identities, where the angles involved are acute angles for which the expressions are defined:\(\frac{(\text{1 + tan² A})}{(\text{1 + cot² A})} = (\frac{\text{1 - tan A }}{\text{ 1 - cot A}})^²= \text{tan² A}\)