NCERT Solutions for Class 9 Maths Chapter 4 Exercise 4.3 Solutions

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NCERT Solutions for Class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.3 Solutions are based on the graph of linear equations.

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Exercise Solutions of Class 9 Maths Chapter 4 Linear Equation in Two Variables

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Chapter Related Topics
Pair of Linear Equations in Two Variables Formula	Pair of Linear Equations in Two Variables Revision Notes	Linear Equation in Two Variables

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CBSE X Related Questions

1.
If $\sin \theta = \frac{1}{9}$, then $\tan \theta$ is equal to
- $\frac{1}{4\sqrt{5}}$
- $\frac{4\sqrt{5}}{9}$
- $\frac{1}{8}$
- $4\sqrt{5}$
View Solution
2.
Find the smallest value of $p$ for which the quadratic equation $x^2 - 2(p + 1)x + p^2 = 0$ has real roots. Hence, find the roots of the equation so obtained.
View Solution
3.
Check whether the following system of equations is consistent or not. If consistent, solve graphically: \[ x - 2y + 4 = 0, \quad 2x - y - 4 = 0 \]
View Solution
4.
OAB is sector of a circle with centre O and radius 7 cm. If length of arc $ \widehat{AB} = \frac{22}{3} $ cm, then $ \angle AOB $ is equal to
- $ \left(\frac{120}{7}\right)^\circ $
- $ 45^\circ $
- $ 60^\circ $
- $ 30^\circ $
View Solution
5.
ABCD is a rectangle with its vertices at (2, --2), (8, 4), (4, 8) and (--2, 2) taken in order. Length of its diagonal is
- $4\sqrt{2}$
- $6\sqrt{2}$
- $4\sqrt{26}$
- $2\sqrt{26}$
View Solution
6.
The point $(3, -5)$ lies on the line $mx - y = 11$. The value of $m$ is
- 3
- -2
- -8
- 2
View Solution

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NCERT Solutions for Class 9 Maths Chapter 4 Exercise 4.3 Solutions

Exercise Solutions of Class 9 Maths Chapter 4 Linear Equation in Two Variables

CBSE X Related Questions

1.
If \(\sin \theta = \frac{1}{9}\), then \(\tan \theta\) is equal to

2.
Find the smallest value of $p$ for which the quadratic equation $x^2 - 2(p + 1)x + p^2 = 0$ has real roots. Hence, find the roots of the equation so obtained.

3.
Check whether the following system of equations is consistent or not. If consistent, solve graphically: \[ x - 2y + 4 = 0, \quad 2x - y - 4 = 0 \]

4.
OAB is sector of a circle with centre O and radius 7 cm. If length of arc \( \widehat{AB} = \frac{22}{3} \) cm, then \( \angle AOB \) is equal to

5.
ABCD is a rectangle with its vertices at (2, --2), (8, 4), (4, 8) and (--2, 2) taken in order. Length of its diagonal is

6.
The point \((3, -5)\) lies on the line \(mx - y = 11\). The value of \(m\) is

Similar Mathematics Concepts

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NCERT Solutions for Class 9 Maths Chapter 4 Exercise 4.3 Solutions

Exercise Solutions of Class 9 Maths Chapter 4 Linear Equation in Two Variables

CBSE X Related Questions

1.If \(\sin \theta = \frac{1}{9}\), then \(\tan \theta\) is equal to

2.Find the smallest value of $p$ for which the quadratic equation $x^2 - 2(p + 1)x + p^2 = 0$ has real roots. Hence, find the roots of the equation so obtained.

3.Check whether the following system of equations is consistent or not. If consistent, solve graphically: \[ x - 2y + 4 = 0, \quad 2x - y - 4 = 0 \]

4.OAB is sector of a circle with centre O and radius 7 cm. If length of arc \( \widehat{AB} = \frac{22}{3} \) cm, then \( \angle AOB \) is equal to

5.ABCD is a rectangle with its vertices at (2, --2), (8, 4), (4, 8) and (--2, 2) taken in order. Length of its diagonal is

6.The point \((3, -5)\) lies on the line \(mx - y = 11\). The value of \(m\) is

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
If \(\sin \theta = \frac{1}{9}\), then \(\tan \theta\) is equal to

2.
Find the smallest value of $p$ for which the quadratic equation $x^2 - 2(p + 1)x + p^2 = 0$ has real roots. Hence, find the roots of the equation so obtained.

3.
Check whether the following system of equations is consistent or not. If consistent, solve graphically: \[ x - 2y + 4 = 0, \quad 2x - y - 4 = 0 \]

4.
OAB is sector of a circle with centre O and radius 7 cm. If length of arc \( \widehat{AB} = \frac{22}{3} \) cm, then \( \angle AOB \) is equal to

5.
ABCD is a rectangle with its vertices at (2, --2), (8, 4), (4, 8) and (--2, 2) taken in order. Length of its diagonal is

6.
The point \((3, -5)\) lies on the line \(mx - y = 11\). The value of \(m\) is