NCERT Solutions for Class 9 Maths Chapter 4 Exercise 4.1 Solutions

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NCERT Solutions for Class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.1 Solutions are based on plotting points on a plane if its coordinates are mentioned.

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Exercise Solutions of Class 9 Maths Chapter 4 Linear Equation in Two Variables

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Pair of Linear Equations in Two Variables Formula	Pair of Linear Equations in Two Variables Revision Notes	Linear Equation in Two Variables

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CBSE X Related Questions

1.
The point $(3, -5)$ lies on the line $mx - y = 11$. The value of $m$ is
- 3
- -2
- -8
- 2
View Solution
2.
Find the smallest value of $p$ for which the quadratic equation $x^2 - 2(p + 1)x + p^2 = 0$ has real roots. Hence, find the roots of the equation so obtained.
View Solution
3.
If $\sin \theta = \frac{1}{9}$, then $\tan \theta$ is equal to
- $\frac{1}{4\sqrt{5}}$
- $\frac{4\sqrt{5}}{9}$
- $\frac{1}{8}$
- $4\sqrt{5}$
View Solution
4.
If the points $A(6, 1)$, $B(p, 2)$, $C(9, 4)$, and $D(7, q)$ are the vertices of a parallelogram $ABCD$, then find the values of $p$ and $q$. Hence, check whether $ABCD$ is a rectangle or not.
View Solution
5.
ABCD is a rectangle with its vertices at (2, --2), (8, 4), (4, 8) and (--2, 2) taken in order. Length of its diagonal is
- $4\sqrt{2}$
- $6\sqrt{2}$
- $4\sqrt{26}$
- $2\sqrt{26}$
View Solution
6.
In a right triangle ABC, right-angled at A, if $\sin B = \dfrac{1}{4}$, then the value of $\sec B$ is
- 4
- $\dfrac{\sqrt{15}}{4}$
- $\sqrt{15}$
- $\dfrac{4}{\sqrt{15}}$
View Solution

View All

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NCERT Solutions for Class 9 Maths Chapter 4 Exercise 4.1 Solutions

Exercise Solutions of Class 9 Maths Chapter 4 Linear Equation in Two Variables

CBSE X Related Questions

1.
The point \((3, -5)\) lies on the line \(mx - y = 11\). The value of \(m\) is

2.
Find the smallest value of $p$ for which the quadratic equation $x^2 - 2(p + 1)x + p^2 = 0$ has real roots. Hence, find the roots of the equation so obtained.

3.
If \(\sin \theta = \frac{1}{9}\), then \(\tan \theta\) is equal to

4.
If the points \(A(6, 1)\), \(B(p, 2)\), \(C(9, 4)\), and \(D(7, q)\) are the vertices of a parallelogram \(ABCD\), then find the values of \(p\) and \(q\). Hence, check whether \(ABCD\) is a rectangle or not.

5.
ABCD is a rectangle with its vertices at (2, --2), (8, 4), (4, 8) and (--2, 2) taken in order. Length of its diagonal is

6.
In a right triangle ABC, right-angled at A, if $\sin B = \dfrac{1}{4}$, then the value of $\sec B$ is

Similar Mathematics Concepts

Comments

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NCERT Solutions for Class 9 Maths Chapter 4 Exercise 4.1 Solutions

Exercise Solutions of Class 9 Maths Chapter 4 Linear Equation in Two Variables

CBSE X Related Questions

1.The point \((3, -5)\) lies on the line \(mx - y = 11\). The value of \(m\) is

2.Find the smallest value of $p$ for which the quadratic equation $x^2 - 2(p + 1)x + p^2 = 0$ has real roots. Hence, find the roots of the equation so obtained.

3.If \(\sin \theta = \frac{1}{9}\), then \(\tan \theta\) is equal to

4.If the points \(A(6, 1)\), \(B(p, 2)\), \(C(9, 4)\), and \(D(7, q)\) are the vertices of a parallelogram \(ABCD\), then find the values of \(p\) and \(q\). Hence, check whether \(ABCD\) is a rectangle or not.

5.ABCD is a rectangle with its vertices at (2, --2), (8, 4), (4, 8) and (--2, 2) taken in order. Length of its diagonal is

6.In a right triangle ABC, right-angled at A, if $\sin B = \dfrac{1}{4}$, then the value of $\sec B$ is

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
The point \((3, -5)\) lies on the line \(mx - y = 11\). The value of \(m\) is

2.
Find the smallest value of $p$ for which the quadratic equation $x^2 - 2(p + 1)x + p^2 = 0$ has real roots. Hence, find the roots of the equation so obtained.

3.
If \(\sin \theta = \frac{1}{9}\), then \(\tan \theta\) is equal to

4.
If the points \(A(6, 1)\), \(B(p, 2)\), \(C(9, 4)\), and \(D(7, q)\) are the vertices of a parallelogram \(ABCD\), then find the values of \(p\) and \(q\). Hence, check whether \(ABCD\) is a rectangle or not.

5.
ABCD is a rectangle with its vertices at (2, --2), (8, 4), (4, 8) and (--2, 2) taken in order. Length of its diagonal is

6.
In a right triangle ABC, right-angled at A, if $\sin B = \dfrac{1}{4}$, then the value of $\sec B$ is