MCQ On Surface Area And Volume

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Jasmine Grover

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Surface area and volume are basically used to deduce any three-dimensional geometrical shape. The surface area is the area or region occupied by the surface of the object. On the other hand, volume is said to be the amount of space available in an object. In geometry, there are different shapes and sizes such as Sphere, cube, cuboid, etc. and each shape has its surface area and volume.

But this is different in two-dimensional figures such as squares, circles and so on. In this, we can measure only the area covered by these figures and there is zero volume. Generally, the area is of two types:

  1. Total Surface Area – It is the total area covered by the surface of the object. If the shape has a curved surface and base, the total area will be the sum of the two areas.
  2. Lateral Surface area/Curved surface area – Curved surface area refers to the curved part only not including the base. It is also referred to as Lateral surface area.

Volume: The amount of space, measured in cubic units, that an object or substance occupies is called volume. 2D figures don’t have volume such as circles.

The video below explains this:

Surface Area and Volume Detailed Video Explanation:


Q1) If we cut a cone in two parts by a plane parallel to the base, then the bottom part left over is the:

  1. cone
  2. sphere
  3. Frustrum of the cone
  4. cylinder

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Ans: (c) Frustrum of the cone

Explanation:

Given in the figure

Frustrum of the cone

Frustrum of the cone

Q2) 18 solid spheres are made by melting a solid metallic cone of base diameter as 3 cm and height as 12 cm. The radius of each sphere is:

  1. 6
  2. 1/2
  3. 1/4
  4. 1/6

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Ans: (d) 1/6

Explanation: Volume of 18 spheres = Volume of cone

N x volume of sphere = volume of cone

18 x (4/3) π r3 = (1/3) π r2h

18 x (4/3) π r3 = (1/3) π r2 x 12

r= 1/6.

Q3) The radius of the top and bottom of a bucket of slant height 28 cm are 24 cm and 9 cm. The curved surface area of the bucket is:

  1. 3630 cm2
  2. 3750 cm2
  3. 2904 cm2
  4. none of the above.

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Ans: (c) 2904 cm2

Explanation: Curved surface area of the bucket = π (R1+R2) x slant height (l)

Curved surface area = (22/7) x (24+9) x 28

Curved surface area = 22 x 33 x 4= 2904 cm2.

Q4) A tank is made up of the shape of the cylinder with a hemispherical depression at one end. The height of the cylinder is 1.17 m and radius 30 cm. the total surface area of the tank is:

  1. 2.77 m
  2. 3.3 m
  3. 2.18 m
  4. 3 m

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Ans: (a) 2.77 m

Explanation: Total surface area of the tank = CSA of cylinder + CSA of Hemisphere

= 2πrh + 2πr2 = 2πr (h + r)

= 2x 22/7 x 30 (117 + 30)

= 27720 cm2 or 27720/10,000 =2.772 m.

Q5) A shuttle cock used for badminton has the shape of the combination of

  1. Frustrum of a cone and a hemisphere
  2. a cylinder and a sphere
  3. a sphere and a cone
  4. a cylinder and a hemisphere

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Ans: (a) Frustrum of a cone and a hemisphere

Explanation:

A shuttle cock so used while playing badminton has the shape of the combination of frustum of a cone and a hemisphere.

Q6) A hollow cube of internal edge 24 cm is filled with spherical marbles of diameter 0.8 cm and it is assumed that 1/8th space of the cube remains vacant. Then the number of marbles that the cube can accommodate is

  1. 14229
  2. 3242
  3. 3000
  4. None of these

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Ans: (b) 3242

Explanation:

Volume of cube = a3= 243 = 13824 cm3

Volume of cube that remains vacant = 1/8 x (13824) = 1728 cm3

Volume occupied by spherical marbles = 13824-1728= 12096 cm3

Radius of the spherical marble= 0.8/2= 0.4 cm

Volume of one spherical marble = (4/3) πr3 = (4/3) π (0.4)= 0.2680 cm3

No. of spherical marbles, n = 12096 x 0.2680= 3241.728= 3242 marbles.

Q7) A solid piece of iron in the form of a cuboid of dimensions (56 x 33 x 24) cm, is moulded to form a solid sphere. The radius of the sphere is

  1. 23
  2. 25
  3. 19
  4. 21

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Ans: (d) 21 cm.

Explanation:

Given: length, l= 49 cm, breadth, b= 33cm, height, h= 24 cm.

Volume of cube= 49 x 33 x 24 cm3

Let r be the radius of sphere,

Volume of sphere= (4/3) π r3

Volume of cuboid= volume of sphere moulded

49 x 33 x 24 = (4/3) π r3

29106 x (3/4) x (1/ π) = r3

r=21 cm.

Q8) The diameters of the two circular ends of the bucket are 42 cm and 22 cm. The height of the bucket is 35 cm. The capacity of the bucket is

  1. 32.7 L
  2. 33.7 L
  3. 31.7 L
  4. 29.06 L

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Ans: (d) 29.06 L

Explanation:

Given that,

The height of the bucket =h= 35cm

Diameter of the one circular end of the bucket= 42 cm

Radius, R=21 cm

Diameter of the one circular end of the bucket= 22 cm

Radius, r=11 cm

Volume of the bucket, v= (1/3) πh (R2+r2+ Rr)

= (1/3) π x 35 (212+112+ 21x 11)

= 29064.96/1000= 29.06 L.

Q9) When two same solid hemispheres of equal base radius r cm are attached together along with their bases. The total surface area of the combination is

  1. 6πr2
  2. 4 πr2
  3. 3 πr2
  4. 2 πr2

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Ans: (b) 4πr2

Explanation:

When two same solid hemispheres of equal base radius are attached together along with their bases a Sphere is formed.

The curved surface area of a sphere =4πr2.

Q10) A solid cylinder of radius r and height h is placed over another cylinder of equal height and radius. The total surface area of the shape so formed is

  1. 4πrh + 2πr2
  2. 2πrh + 4πr2
  3. 4πrh + 4πr2
  4. 2πr2 + 2πrh

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Ans: (a) 4πrh + 2πr2

Explanation:

As we know,

The total surface area of the cylinder = 2πr2 + 2πrh2

When one cylinder is placed over the other cylinder of equal height and radius then the height of the new cylinder will be 2h and radius as r.

Thus, the total surface area of the shape so formed =2πr (2h) + 2πr= 4πrh + 2πr2.

Q11) If the volume of a cube is 1728 cm3, the length of its edge is equal to

  1. 12
  2. 13
  3. 14
  4. 15

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Ans: (a) 12 cm

Explanation:

Volume of cube = a3

Hence, a = cube root of 1728= 12

Therefore, a= 12 cm.

Q12) Cylindrical pencil sharpened at one edge is the combination of

  1. a frustum of a cone and cylinder
  2. a cone and a cylinder
  3. a hemisphere and a cylinder
  4. two cylinders

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Ans: (b) a cone and a cylinder

Explanation:

A Cylindrical pencil sharpened at one edge is the combination of a cone and a cylinder

A Cylindrical pencil sharpened at one edge is the combination of a cone and a cylinder

Q13) If we join two hemispheres of equal radius along with their bases, then we get a

  1. Sphere
  2. cone
  3. cylinder
  4. cube

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Ans: (a) Sphere

Explanation:

When we join two hemispheres of the equal radius then we get one complete Sphere.

Q14) The number of shots each having a radius of 2 cm can be made from a cuboidal lead solid of dimensions (9 x 11 x 12) cm is equal to approx.

  1. 84
  2. 90
  3. 35
  4. 92

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Ans: (c) 35

Explanation:

Volume of cuboidal lead solid = 9 x 11 x 12= 1188 cm3

Radius, r= 2 cm

Volume of each shot= (4/3) π r3

= (4/3) π (2)3

= 33.51 cm3

Number of lead shots can be made= 1188/33.51=35.45

Q15) The shape of an ice cream cone forms a combination of

  1. Sphere and a cylinder
  2. Cone and a sphere
  3. Cone and a cylinder
  4. Hemisphere and a cone

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Ans: (d) Hemisphere and a cone

Explanation:

The shape of an ice cream cone forms a combination of a Hemisphere and a cone.

Q16) If a cone is cut parallel to the base of it by a plane in two parts, then the shape of the top of the cone would be

  1. cone itself
  2. frustrum
  3. trapezium
  4. sphere

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Ans: (a) cone itself

Explanation:

If we cut a cone into two portion parallel to the base, then the shape of the upper portion is the cone itself.

Cone cut parallel to the base

Upper portion is cone itself

Q17) If the volume of a cube is given as 1331 cm3, the length of its edge is equal to

  1. 11 cm
  2. 12 cm
  3. 13 cm
  4. 14 cm

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Ans: (a) 11 cm

Explanation:

The volume of a cube is = a3

Hence, a= 1331

Therefore, a= cube root of 1331 => a=11 cm.

CBSE X Related Questions

1.

Prove the following identities, where the angles involved are acute angles for which the expressions are defined:\(\frac{(\text{1 + tan² A})}{(\text{1 + cot² A})} = (\frac{\text{1 - tan A }}{\text{ 1 - cot A}})^²= \text{tan² A}\)

      2.
      Which of the following pairs of linear equations are consistent/inconsistent? If consistent, obtain the solution graphically: (i) \(x + y = 5\),\( 2x + 2y = 10\) (ii)\( x – y = 8 , 3x – 3y = 16\) (iii) \(2x + y – 6 = 0\) , \(4x – 2y – 4 = 0\) (iv) \(2x – 2y – 2 = 0,\) \( 4x – 4y – 5 = 0\)

          3.
          If 3 cot A = 4, check whether \(\frac{(1-\text{tan}^2 A)}{(1+\text{tan}^2 A)}\) = cos2 A – sinA or not

              4.
              Find the sums given below :
              1. \(7 + 10\frac 12+ 14 + ....... + 84\)
              2. \(34 + 32 + 30 + ....... + 10\)
              3. \(–5 + (–8) + (–11) + ....... + (–230)\)

                  5.

                  A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.

                      6.
                      An umbrella has 8 ribs which are equally spaced (see Fig. 11.10). Assuming umbrella to be a flat circle of radius 45 cm, find the area between the two consecutive ribs of the umbrella.
                      An umbrella has 8 ribs which are equally spaced

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