Mode of Grouped Data

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Jasmine Grover

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In statistics, the mode (aka modal value) is one of the three measures of central tendency. It is defined as the value that occurs repeatedly in a given data set. A set can have one, two, or more than two modes, or even no mode at all.

Mode is the number or value that appears most frequently or the highest number of times in a data set.

For example, the modal value of the set {2, 3, 3, 7, 5, 8, 4, 3, 9} is 3.

Key Terms: Mode, Mode of Grouped Data, Types of Grouped Data, Mode Formula of Grouped Data


Definition of Mode

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In statistics, we represent the data using tables, graphs, pie charts, etc. To analyze the represented data and understand it further, we define the entire collection of data roughly using a representative value. This representative value is called the measure of central tendency.

There are three main measures of central tendency. They are mean, median, and mode.

Mode is the value that occurs most frequently in an observation. In simple terms, it is the value that appears the most number of times in a data set.

For the data set {4, 5, 6, 5, 2, 3, 7, 9} the mode is 5, as it appears twice in the set.

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Types of Mode

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There are different types of modes like unimodal, bimodal, trimodal, and multimodal mode.

Unimodal Mode

A data set with one mode is called a unimodal mode.

For example, Consider the set A = {3, 4, 5, 3, 1, 7, 3, 6}.

Here, only the value 3 appears three times in the given set. Hence, the set has only one mode value which is 3. So it is a unimodal set.

Bimodal Mode

A data set with two mode values is called a bimodal mode. In such a data set, there are two values with the highest frequency.

For example, Consider the set B = {3, 4, 5, 3, 1, 7, 5, 2, 8, 5, 3, 6}.

Here, the values 3 and 5 both are repeating three times. Hence, the set has two modal values 3 and 5. So, it is a bimodal set.

Trimodal Mode

A data set with three modes is called a trimodal mode. In such a data set, there are three values with the highest frequency.

For example, Consider the set C = {4, 6, 7, 4, 3, 4, 5, 3, 1, 7, 5, 2, 8, 5, 3, 6}.

Here, the values 3, 4, and 5 are repeating three times. Hence, the set has three modal values 3, 4, and 5. So, it is a trimodal set.

Multimodal Mode

A data set with four or more modes is called a multimodal mode. In such a data set, there are four or more values with the highest frequency.

For example, Consider the set D = {7, 8, 2, 7, 4, 6, 7, 4, 3, 4, 5, 3, 1, 7, 5, 2, 8, 5, 3, 6}.

Here, the values 3, 4, 5, and 7 are repeating three times. Hence, the set has four mode values 3, 4, 5, and 7. So, it is a multimodal set.


Formula of Mode

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We cannot find the mode of a continuous series or grouped data, by looking at the data set. For that, we need to calculate the modal class, as the mode lies in the modal class. The formula for calculating the mode for a grouped data is as follows:

what is formula of mode

Where,

l = lower level of the modal class

h = size of the class interval

f1= frequency of the modal class interval

f0= frequency of the class interval preceding the modal class

f2 = frequency of the class interval succeeding the modal class

The steps to calculate the mode of grouped data with equal class intervals using the above formula is as follows:

Step 1: Prepare the frequency distribution table such that the observations are in the first column and their respective frequency is in the second column.

Step 2: Find out the class that has the maximum frequency. This class is your modal class.

Step 3: Find the class size by computing: upper limit - lower limit.

Step 4: Calculate the mode using the above formula.

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Sample Questions

Ques: What is the mode of the following data? (5 marks)

Ans:

Class Frequency
50 - 55 2
55 - 60 7
60 - 65 8
65 - 70 4

In this data, the class with maximum frequency is 60 - 65, with a frequency of 8.

So, the modal class is 60 - 65.

Class size,

h = upper limit - lower limit

h = 65 - 60 = 5

what is formula of mode

Here,

l = 60

h = 5

f1= 8

f0= 7

f2 = 4

Mode = 60 + \((\frac{8 - 7}{2*8 - 7 - 4})\) * 5

Mode = 60 + 1 = 61

Therefore, the Mode is 61.

Ques: In a class of 30 students, the marks obtained by students in Science out of 50 marks are given in the table below. Find the mode of the data. (5 marks)

Ans:

Marks Obtained Number of Students
10 - 20 5
20 - 30 12
30 - 40 8
40 - 50 5

In this data, the maximum class frequency is 12, for the class interval 20 - 30.

Hence, the modal class is 20 - 30.

The class interval size is h = 10.

Lower limit l = 20

f1= 12

f0= 5

f2 = 8

Now,

formula of mode

Mode = 20 + \((\frac{12- 5}{2*12- 5-8})\) * 10

Mode = 26.364

Therefore, the mode is 26.364.

Ques: Find the modal value of the frequency distribution tabulated below. (4 marks)

Ans:

Marks Obtained Number of Students
20 - 30 30
30 - 40 55
40 - 50 44
50 - 60 25

In this data, the maximum class frequency is 55, for the class interval 30 - 40.

Hence, the modal class is 30 - 40.

The class interval size is h = 10.

Lower limit l = 30

f1= 55

f0= 30

f2 = 44

formula of mode

Mode = 30 + \((\frac{55- 30}{2*55- 30- 44})\) *10

Mode = 10 + 6.944 = 16.994

Therefore, the mode is 16.994.

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CBSE X Related Questions

1.

Prove the following identities, where the angles involved are acute angles for which the expressions are defined:\(\frac{(\text{1 + tan² A})}{(\text{1 + cot² A})} = (\frac{\text{1 - tan A }}{\text{ 1 - cot A}})^²= \text{tan² A}\)

      2.
      An umbrella has 8 ribs which are equally spaced (see Fig. 11.10). Assuming umbrella to be a flat circle of radius 45 cm, find the area between the two consecutive ribs of the umbrella.
      An umbrella has 8 ribs which are equally spaced

          3.

          Form the pair of linear equations for the following problems and find their solution by substitution method.

          (i) The difference between two numbers is 26 and one number is three times the other. Find them.

          (ii) The larger of two supplementary angles exceeds the smaller by 18 degrees. Find them.

          (iii) The coach of a cricket team buys 7 bats and 6 balls for Rs 3800. Later, she buys 3 bats and 5 balls for Rs 1750. Find the cost of each bat and each ball.

          (iv) The taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km, the charge paid is Rs 105 and for a journey of 15 km, the charge paid is Rs 155. What are the fixed charges and the charge per km? How much does a person have to pay for travelling a distance of 25 km.

          (v) A fraction becomes\(\frac{ 9}{11}\), if 2 is added to both the numerator and the denominator. If, 3 is added to both the numerator and the denominator it becomes \(\frac{5}{6}\). Find the fraction.

          (vi) Five years hence, the age of Jacob will be three times that of his son. Five years ago, Jacob’s age was seven times that of his son. What are their present ages?

              4.
              The angle of elevation of the top of a building from the foot of the tower is 30° and the angle of elevation of the top of the tower from the foot of the building is 60°. If the tower is 50 m high, find the height of the building.

                  5.

                  Solve the following pair of linear equations by the substitution method. 
                  (i) x + y = 14 
                      x – y = 4   

                  (ii) s – t = 3 
                      \(\frac{s}{3} + \frac{t}{2}\) =6 

                  (iii) 3x – y = 3 
                        9x – 3y = 9

                  (iv) 0.2x + 0.3y = 1.3 
                       0.4x + 0.5y = 2.3 

                  (v)\(\sqrt2x\) + \(\sqrt3y\)=0
                      \(\sqrt3x\) - \(\sqrt8y\) = 0

                  (vi) \(\frac{3x}{2} - \frac{5y}{3}\) =-2,
                      \(\frac{ x}{3} + \frac{y}{2}\) = \(\frac{ 13}{6}\)

                      6.

                      The lengths of 40 leaves of a plant are measured correct to the nearest millimetre, and the data obtained is represented in the following table :

                      Length (in mm)

                      Number of leaves

                      118 - 126

                      3

                      127 - 135 

                      5

                      136 - 144

                      9

                      145 - 153

                      12

                      154 - 162

                      5

                      163 - 171

                      4

                      172 - 180

                      2

                      Find the median length of the leaves. 
                      (Hint : The data needs to be converted to continuous classes for finding the median, since the formula assumes continuous classes. The classes then change to 117.5 - 126.5, 126.5 - 135.5, . . ., 171.5 - 180.5.)

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