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Pythagoras theorem is a geometric theorem in which the sum of squares on the foot of the right triangle is equal to the square of its hypotenuse. This theorem is used to find the length of the sides and angles of a right-angled triangle that is not known. A right-angled triangle is a polygon having 3 sides, having one of the angles as right angle (90°). Using this theorem, we can extract the perpendicular, base, and hypotenuse formulas.
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Pythagoras Theorem
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The theorem states that “The square of the hypotenuse in a right-angled triangle is equal to the sum of squares of the other two sides”. For a right-angled triangle, the Hypotenuse is considered the longest side which is opposite to the 90° angle. The other two sides referred to in the definition are called Base or adjacent and Perpendicular or the height.
The sides of a right-angled triangle (a, b, c) come with a positive integer value when they are squared and put into the equation known as the Pythagorean Triple.
The Pythagoras theorem is only applicable when the triangle is a Right-angled Triangle.
Pythagoras Theorem
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Pythagoras Theorem Detailed Video Explanation:
Pythagoras Theorem Formula
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Consider the above right-angled triangle PQR. In this triangle –
PQ= “a” is the perpendicular,
QR= “b” is the base and
PR= “c” is the hypotenuse.
Angle Q is 90° angle
So, according to the definition given by Pythagoras, the Pythagorean Theorem Formula is given by-
Hypotenuse2 = Perpendicular2 + Base2
i.e. c2=a2+b2
Consider 3 squares a, b, c on three sides of a triangle as shown in the figure below.
Now, by Pythagoras Theorem-
Pythagoras Theorem Formula
Area of square “c” = Area of square “a” + Area of square “b”.
Note: “a” and “b” are the other two sides and “c” is the longest axis.
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Proof of Pythagoras Theorem
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Let us consider a Right-angled triangle PQR, right-angled at Q.
To Prove: PR2=PQ2+QR2
Construction: Draw a perpendicular QS meeting at PR at S.
A perpendicular QS meeting at PR at S
Proof:
We know, ΔRSQ~ΔRQP
Therefore, RSRQ=RQRP (Corresponding sides of Similar Triangle)
Or, RQ2=RS * RP…………………..(1)
Also, ΔQSP~ΔRQP
Therefore, PSQP=QPRP (Corresponding sides of Similar Triangle)
Or, QP2=PS * RP…………………..(2)
Adding the equations (1) & (2) we get,
RQ2 + QP2= RS * RP + PS * RP
RQ2 + QP2= RP( RS+PS)
Since RS+PS=RP
Therefore, RP2=RQ2+QP2
Or, c2= b2+a2
Or, c2 =a2+b2
Or, Hypotenuse2 = Perpendicular2 + Base2
Hence, The Pythagoras Theorem is proved.
The Converse of Pythagoras Theorem
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The converse of Pythagoras theorem can be stated as: A triangle can be proved to be a right-angle triangle when the square of the length of the longest side of a triangle is equal to the sum of the squares of the other two sides.
In \(\bigtriangleup\) ABC, if C2 = a2 + b2, then \(\angle\)C is a right angle triangle, \(\bigtriangleup\)PQR being the right angle
The Converse of Pythagoras Theorem
This can be proved by contraction
Let’s assume c2 = a2 + b2 in \(\bigtriangleup\)ABC and the triangle is not right triangle.
Then let's assume another \(\bigtriangleup\)PQR. Through the construction of \(\bigtriangleup\)PQR so that PR = a, QR = b and \(\angle\)R is a right angle.
The Converse of Pythagoras Theorem
By the Pythagoras theorem, (PQ)2 = a2 + b2
But we are aware that a2 + b2 = c2 and c = AB
Hence (PQ)2 = a2 + b2 = (AB)2
That is (PQ)2 = (AB)2
Since PQ and AB are the lengths of the sides, we can consider them to be positive square roots
PQ = AB
That is all the three given sides of \(\bigtriangleup\)PQR is congruent to all the three sides of \(\bigtriangleup\)ABC. Hence the two given triangles are congruent by the Side-Side-Side property of congruency.
Since the \(\bigtriangleup\)ABC is congruent to \(\bigtriangleup\)PQR and it is a right angle triangle, therefore \(\bigtriangleup\)ABC is also a right-angle triangle.
This is a contradiction, hence the assumptions we made must be wrong.
Application of Pythagoras Theorem
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- This theorem helps us to find the diagonal of a square.
- Pythagoras Theorem helps us to find whether a triangle is a right-angled triangle or not.
- For a Right-angled triangle using this Theorem, we can find the length of the unknown side of the other two sides are known
- Pythagoras theorem enables us to calculate the diagonal length of a roof, the distance between the foot of a slanted ladder, the perpendicular height of the wall or bean on which the ladder is slanted.
- Pythagoras theorem is very useful for civil engineering projects
- This theorem is also used for navigation purposes as it is difficult to measure the distance across water bodies.
- Cartographers also use the Pythagoras theorem to find the distance between two points on a 2D sheet or map
- Pythagoras theorem can also be used to find the steepness of the hill slope or mountain slope
Things to Remember
- Pythagoras theorem: \(c = \sqrt{a^2+b^2}\)
- Pythagoras theorem states the relation between all the three sides of a right triangle.
- It helps in the calculation of the sides and angles of a triangle.
- Pythagoras theorem helps in understanding whether a triangle is a right-angled triangle or not.
- It helps in the trigonometry ratio calculation along with distance and height measurement.
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Sample Questions
Ques: Find the value of x. (2 marks)
Ans.- Since x is on the opposite side of the right-angle so it’s the hypotenuse
Now, From the Theorem-
Hypotenuse2 = Perpendicular2 + Base2
x2 = 152 + 102
⇒ x= 152+102
⇒ x = 18
Therefore, the value of unknown side “x” is 18.
Ques: The sides of a triangle are 10,8 and 6 units. Check whether it is a right-angled triangle or not. (3 marks)
Ans.- Using Pythagoras theorem,
Hypotenuse2 = Perpendicular2 + Base2
Given,
Perpendicular=8
Base=6
Hypotenuse=10 (since it is the longest measuring length)
From the formula,
82+62=102
⇒ 64+36=100
⇒ 100=100
L.H.S = R.H.S.
Therefore, the angle opposite to 10 is a right-angle.
Ques: A bamboo is placed against the door such that its foot is at the distance of 2.5m from the door and its top reaches a Wallpaper that is 6m above the ground and the wallpaper is fixed above the door. Find the length of the bamboo? (2 marks)
Ans.- Let AB be a ladder and CA be the Bamboo with the wallpaper at A.
Also, BC=2.5m and CA=6m
From Pythagoras theorem,
Hypotenuse2 = Perpendicular2 + Base2
AB2=BC2 + CA2
⇒AB2=2.52 + 62
⇒AB= (42.25)1/2
⇒AB= 6.5 m
The length of the bamboo is 6.5 m
Ques: A fenced rectangular plot of length 15cm and diagonal 17cm. Find the perimeter of the rectangular plot? (3 marks)
Ans.- The angle between the two sides of a rectangular plot is 90 degrees. Thus, the diagonal divides the rectangle into two right-angled triangles where the diagonal forms the hypotenuse. The length of perpendicular of that triangle is given by the length of that rectangular plot and similarly, the breadth corresponds to the base of that triangle.
For the right angled triangle ABD,
AB2+BD2=AD2
⇒172=152+BD2
⇒289-225=BD2
⇒ BD= 64
⇒ BD= 8
The base of the right-angled triangle is 8cm which is the breadth of the rectangle.
Therefore, Perimeter of the rectangle= 2* (Length + Breadth)
= 2(15+8)
= 46
The perimeter of the given rectangular plot is equal to 46cm.
Ques: Aniket, Roshni, and Karanveer were having a birthday party at Deepshika’s house. After the party gets over, Roshni and Karanveer went back to their respective house in a rented car hired through Uber while Aniket stayed back. Roshni’s house was 12 miles straight towards the east, from Deepshika’s house. Karanveer’s house was 5 miles straight south to Deepshika’s house. How far was their house (Roshni’s and Karanveer’s)? (2 marks)
Ques. A triangle has sides 8 cm, 11 cm and 15 cm. Determine if it is a right triangle. (2 marks)
Ans. Let’s assume hypotenuse = 15 cm (it is the longest side) = c
c2 = 152 = 225
Other sides a = 8cm, b = 11cm
a2 + b2 = 82 + 112 = 64 + 121 = 185
185 \(\neq\) 225
a2 + b2 \(\neq\) c2
Hence it is not a right angle triangle.
Ques. ABC is a right triangle. AC is its hypotenuse. Length of side AB is \(2\sqrt{5}\). Side BC is twice of side AB. Find the length of AC. (3 marks)
Ans. Let AB = a, BC = b, AC = c
AB = a = \(2\sqrt{5}\)
BC is two times of AB, b = 2a = \(2\sqrt{5}\)
AC = Hypotenuse = c
On applying Pythagoras theorem a2 + b2 = c2
(\(2\sqrt{5}\))2 + (\( 4\sqrt{5}\))2 = c2
4(5) + 16(5) = c2
c2 = 20 + 80 = 100
c = 10
AC = 10
Ques. The hypotenuse of a right triangle is 6 cm. Its area is 9 cm2. Find the sides. (5 marks)
Ans. Let AB = a and BC = b
In \(\bigtriangleup\)ABC, base = b and altitude = a
Area of the triangle = \(\frac{1}{2} \times (base \times altitude)\)
Hence \(\frac{1}{2} \times (ab)\) = 9
ab = 18 (Equation 1)
Using the Pythagoras formula, \(a^2 + b^2 = 6^2 = 36\)
We add an substract 2ab to complete the square:
\(a^2 + b^2 - 2ab + 2ab = 36\)
\((a - b)^2 + 2ab = 36\)
\((a-b)^2 + 36 = 36 \) (Using ab = 18 from Equation 1)
\((a - b)^2 = 0\)
a = b
By substituting a by b in Equation 1 we get:
\(b^2 = 18 \)
\(b = 3\sqrt{2}\)
Side AB = BC = \(3\sqrt{2}\) cm
Ques. In a right-angled triangle, the longest side is 8 cm. One of the remaining sides is \(4\sqrt{3}\) cm long. Find the length of the other side. (3 marks)
Ans. Let the lengths of sides be a, b, and c (hypotenuse)
The hypotenuse is the longest side, hence c = 8
Let b = \(4\sqrt{3}\)
From the Pythagoras theorem, \(a^2 + b^2 = c^2\)
\(a^2 + (4\sqrt{3})^2 = 8^2\)
\(a^2 + 16(3) = 64\)
\(a^2 + 48 = 64\)
\(a^2 = 16\)
a = 4
Therefore the third side = 4 cm
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