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Trigonometric ratios refer to the specific measurement methods of the right-angle triangle which has an interior angle as \(90^{\circ}\). Trigonometry helps to calculate and find the measurement of the sides of lengths or angles or both of a right-angle triangle. The various trigonometric ratios are sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant (cosec). In trigonometric ratios, the reference angle is denoted by \(\theta\).
Key Takeaways: Trigonometry, Trigonometric Ratios, Trigonometric Identities, Complementary angles, Right angle triangle
Trigonometric Ratios
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Let us look at both cases:
case I | case II |
---|---|
sine A = perpendicular/ hypotenuse= BC /AC | sine C = perpendicular/hypotenuse=AB/AC |
cosine A = base/hypotenuse=AB/AC | cosine C = base/hypotenuse=BC/AC |
tangent A = perpendicular/base=BC/AB | tangent C = perpendicular/base=AB/BC |
cosecant A = hypotenuse/perpendicular=AC/BC | cosecant C = hypotenuse/perpendicular=AC/AB |
secant A = hypotenuse/base=AC/AB | secant C = hypotenuse/base=AC/BC |
cotangent A = base/perpendicular=AB/BC | cotangent C = base/perpendicular=BC/AB |
Trigonometric Ratios Relation
The relation between different trigonometric relation is given below.
\(cosec \theta = 1/\sin \theta \)
\(\sec \theta = 1/\cos \theta\)
\(\tan \theta = \sin \theta/\cos \theta\)
\(\cot \theta = \cos \theta/ \sin \theta = 1/\tan \theta\)
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Trigonometric Ratios Range and Variation from 0 to \(90^{\circ}\) Angles
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Given below are the trigonometric ratios at specific and \(90^{\circ}\)angles
Range of Trigonometric Ratios between 0 to \(90^{\circ}\) Angles
Trigonometric Ratios range between 0 to 90 degrees:
For 0 degrees \(\leq\) \(\theta\) \(\leq\) 90 degrees
- \(0\leq\sin\theta\leq1\)
- \(0\leq\cos\theta\leq1\)
- \(0\leq\tan\theta<\infty\)
- \(1\leq\sec\theta<\infty\)
- \(0\leq\cot\theta<\infty\)
- \(1\leq cosec \theta<\infty\)
sec\(\theta\) and tan\(\theta\) are not defined at 90 degrees.
cosec\(\theta\) and cot\(\theta\) are not defined at 0 degrees.
Trigonometric Ratios Variation from \(0^{\circ}\) to \(90^{\circ}\)
Variation of the \(\theta\) increasing from 0 to 90 degrees:
- sin\(\theta\) increases from 0 to 1
- cos\(\theta\) decreases from 1 to 0
- tan\(\theta\) increases from 0 to \(\infty\)
- cosec\(\theta\) decreases from \(\theta \) to 1
- sec\(\theta\) increases from 1 to \(\infty\)
- cot\(\theta\) decreases from \(\infty\) to 0
Trigonometric Ratios at 90 degrees
Trigonometric ratios at \(90^{\circ}\) angle is \(90^{\circ} - \theta\) when \(\theta \) is an acute angle.
- \(\sin (90^{\circ}-\theta) = cos \theta\)
- \(\cos (90^{\circ}-\theta) = sin \theta\)
- \(\tan (90^{\circ}-\theta) = \cot \theta\)
- \(\cot (90^{\circ}-\theta) = \tan \theta\)
- \(cosec (90^{\circ}-\theta) = \sec \theta\)
- \(\sec (90^{\circ}-\theta) = cosec \theta\)
Trigonometric Identities
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The equation which consists of a trigonometric ratio of angle(s) is defined as a trigonometric identity. Depending, if it is real for all figures of the angles involved. The identities are mentioned below:
- tan θ = sinθ/cosθ
- cot θ = cosθ/sinθ
- sin² θ + cos² θ = 1
- sin² θ = 1 – cos² θ
- cos² θ = 1 – sin² θ
- cosec² θ – cot² θ = 1
- cosec² θ = 1 + cot² θ
- cot² θ = cosec² θ – 1
- sec² θ – tan² θ = 1
- sec² θ = 1 + tan² θ
- tan² θ = sec² θ – 1
- sin θ cosec θ = 1
- cos θ sec θ = 1
- tan θ cot θ = 1
Standard Value of Trigonometric Ratios
Values of standard angles of trigonometric ratios are given below.
∠A | 0° | 30° | 45° | 60° | 90° |
sin A | 0 | ½ | \(\frac{1}{\sqrt{2}}\) | \(\frac{3}{\sqrt{2}}\) | 1 |
cos A | 1 | \(\frac{3}{\sqrt{2}}\) | \(\frac{1}{\sqrt{2}}\) | ½ | 0 |
tan A | 0 | \(\frac{1}{\sqrt{3}}\) | 1 | √3 | not defined |
cosec A | not defined | 2 | √2 | \(\frac{2}{\sqrt{3}}\) | 1 |
sec A | 1 | \(\frac{2}{\sqrt{3}}\) | √2 | 2 | not defined |
cot A | not defined | √3 | 1 | \(\frac{1}{\sqrt{3}}\) | 0 |
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Points to Remember
- A trigonometric ratio is purely based upon the angle ‘θ’ and remains the same for the same angle-sized right triangles which are different.
- Besides this, the value of sin θ and cos θ will never exceed one as the opposite side is also 1.
- The adjacent side is never greater than the hypotenuse since the hypotenuse is the longest side in a right-angled triangle.
- In trigonometric ratios, sin\(\theta\) is equal to the opposite side by hypotenuse whereas cosec\(\theta\) is equal to hypotenuse by the opposite side.
- cos\(\theta\) is equal to the adjacent side by the hypotenuse whereas sec\(\theta\) is equal to hypotenuse by the adjacent side.
- tan\(\theta\) is the opposite side by the adjacent side whereas cot\(\theta\) is equal to the adjacent side by the opposite side.
Sample Questions
Ques. If the value of tan θ + cot θ = 5, then find the exact value of tan2θ + cotθ. (2 marks)
Ans. 1 Given:
tan θ + cot θ = 5
By squirting both sides,
tan2θ + cot2θ + 2 tan θ cot θ = 25
tan2θ + cot2θ + 2 = 25
∴ tan2θ + cot2θ = 23
Ques. Consider a right angled ?ABC with tan B value = 12/ 5, then find sin B. (2 marks)
Ans. tan B = 12/5
∴ cot B = 5/12
cosec2 B = 1 + cot2 B= 1 + [(5/12)2/latex]=1+[latex]
= 144+25/144
=169/144
cosec B = 13/12
∴ sin B = 12/13
Ques. If the value of Sin A = 3/4, identify the value of cos A and tan A. (3 marks)
Ans. Take the value of, ABC is a right-angled triangle and the right-angled triangle at B.
Sin A = 3/4
As given, Sin A = Opposite Side divided by Hypotenuse Side = ¾
Now, let us take the BC to be 3 and AC will be 4, where k is the positive real number.
According to the Pythagoras theorem, it is stated ;
Hypotenuse2 = Perpendicular2 + Base2
AC2 = AB2 + BC2
Replacing the value of AC and BC in the above expression to get;
(4k)2 = (AB)2 + (3k)2
16k2 – 9k2 = AB2
AB2 = 7k2
Hence, AB = √7 k
Now, we are required to find the value of cos A and tan A.
cos A = Adjacent Side/Hypotenuse side = AB/AC
cos A = √7 k/4k = √7/4
And, tan A = Opposite side/Adjacent side = BC/AB
tan A = 3k/√7 k = 3/√7
Ques. Simplify 2 tan 2 45° + cos 2 30° – sin2 60°.(2 marks)
Ans. As we know,
tan 45° = 1
cos 30° = √3/2
sin 60° = √3/2
Now, putting these values in the above equation:
2(1)2 + (√3/2)2 – (√3/2)2
= 2 + 0
= 2
Ques. If the value of tan 2A = cot (A – 18°), in which 2A is an acute angle, find the actual value of A. (2 marks)
Ans. we have given the figures,
tan 2A = cot (A – 18°)
As we know by trigonometric identities that the formulae will be,
tan 2A = cot (90° – 2A)
Replacing the above equation in the given equation, ;
Then, cot (90° – 2A) = cot (A – 18°)
Now, 90° – 2A = A – 18° which gives 108° = 3A
A = 108° / 3
Therefore, the value of A = 36°
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