Area of a Trapezoid Formula with Example: Types, Derivation, Examples

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Area of a Trapezoid can be calculated using the lengths of the two parallel sides and the height of the trapezoid. A trapezoid is a two-dimensional quadrilateral that has two sides parallel, known as bases and two non-parallel sides known as legs. Trapezoids can be of different types such as isosceles trapezoid, scalene trapezoid, acute trapezoid, obtuse trapezoid and right trapezoid. 

Key Terms: Area of Trapezoid, Isosceles Trapezoid, Acute Trapezoid, Obtuse Trapezoid, Right Trapezoid, Scalene Trapezoid


What is a Trapezoid?

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Convex quadrilateral with at least one pair of parallel sides is known as Trapezoid or Trapezium. The other two sides are non-parallel. Parallel sides are called bases and non-parallel sides are called the legs or the lateral sides.

Line that connects the mid-points of two non-parallel sides is called the mid-segment. If a line segment is drawn between the two unequal lines the trapezium will be divided into two unequal segments.

Trapezoid 

Fig. Trapezoid 


Types of Trapezoids

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There are different types of trapezoids. Examples of some of the important trapezoids are Isosceles trapezoids, scalene trapezoids and right-angled trapezoids

Based on Sides

Isosceles Trapezoids

When a trapezoid has two equal non-parallel sides, it is called an Isosceles trapezoid. In the above diagram, ABCD is an isosceles trapezoid where the non-parallel sides are equal i.e. AD=BC.

Isosceles Trapezoid

Fig: Isosceles Trapezoid

Scalene Trapezoid

A scalene trapezoid is a type of trapezoid whose sides and angles are unequal. In the above figure, ABCD is a scalene trapezoid where all the sides and all the angles are unequal.

 Scalene Trapezoid 

Fig: Scalene Trapezoid 

Based on Angles

Acute Trapezoid

An acute trapezoid is a type of trapezoid that has two equal adjacent angles. Here, in case of trapezoid ABCD, ‹BAD= ‹CDA. Thus, it is an acute trapezoid.

Acute Trapezoid 

Fig: Acute Trapezoid 

Obtuse Trapezoids

An obtuse trapezoid is a trapezoid in which two opposite angles are obtuse( >90°). In the above image ABCD is an obtuse trapezoid in which ‹ADC and ‹BCD both are obtuse.

Obtuse Trapezoid

Fig: Obtuse Trapezoid

Right Trapezoid

In the case of the Right trapezoid, the two adjacent angles are right angles. In the above given figure, ABCD is a Right trapezoid where ‹DAB and ‹CDA are both right angles.

Right Trapezoid

Fig. Right Trapezoid


Properties of Trapezoids

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Here are some of the properties of a trapezoid:

  • A trapezoid has two parallel and two non-parallel sides named as bases and legs respectively.
  • Like other quadrilaterals the sum total of the interior angles of a trapezoid is always equal to 360°.
  • In a trapezoid, the length of a midsegment is half of the total length of the parallel sides.
  • In the case of an isosceles trapezoid the diagonals are equal in length.
  • In a trapezium the adjacent angles formed in between the adjacent sides and one of the non-parallel sides are supplementary. 

Area of Trapezoids

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The area of a trapezoid can be calculated using the lengths of the two parallel sides and the height of the trapezoid. The formula to compute the area(A) of a trapezoid using the base and the height is:

\(A = \frac{(a +b)}{2} .h\)

(Here, a and b are the lengths of the parallel sides and h is the height between them). 


Derivation of Trapezoids

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Let us assume that ABCD is a trapezoid having two parallel sides AB and DC and two non-parallel sides namely DA and CB.

Derivation of Trapezoid Formula

Fig. Derivation of Trapezoid Formula

Now, a perpendicular is drawn from the point D on the side AB, let DL= h.

AC divides the trapezoid ABCD into two equal triangles ADC and ABC.

So, the area of the trapezoid ABCD = Δ ADC + Δ ABC…………………………..(i)

Now, as DL=h is the altitude of the trapezoid ABCD, ‘h’ is the altitude of the ΔADC and ΔABC .

Therefore, the area of ΔADC = 1/2.DC.h

And, the area of Δ ABC = 1/2.AB.h

Substituting these values in (i) we get,

Area of Trapezoid ABCD = (1/2.DC.h) + (1/2.AB.h)

= 1/2( AB+DC).h

= 1/2( Sum of the parallel sides).(height between the parallel sides)

Thus, we get the formula of the trapezoid ABCD. 


Solved Examples

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Find out the area of a trapezoid whose bases are 24cm and 32cm respectively and the perpendicular height is 7cm.

Solution: In this problem,

a= 24cm; b=32 cm; and h=7 cm

Applying the formula of the area of the trapezoid we get,

Area(A)=((a+b))/2.h = 1/2(24+32)7= 196cm2

There is a trapezoid-shaped garden nearby your house. Its two parallel bases are of 26 m and 40m each. If the area of the trapezoid is 3960 m2. Find out the distance between the parallel bases of the garden.

Solution: As given,

a= 26m: b=40m and area A= 3960m2

Let ‘h’ be the distance between the parallel bases.

As per the formula of trapezoid,

Area (A)=((a+b))/2.h 

Rearranging it we will get,

h= (2 A)/((a+b))

 = (2(3960))/((26+40) )

=7920/66

=120

Therefore, the distance between the parallel bases of the garden is 120m.


Things to Remember

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  • Trapezoids are the quadrilaterals where two of the sides are parallel to each other while the other two are not.
  • If a line segment is drawn between the two unequal lines the trapezium will be divided into two unequal segments.
  • Based on the side’s trapezoids can be of two types- Isosceles trapezoid (having equal non-parallels) and Scalene trapezoid (neither sides nor angles are equal).
  • Based on the angle’s trapezoids are of three types- Acute trapezoid (having equal adjacent angles), Obtuse trapezoids (where two opposite angles are >90°) and Right Trapezoids (where adjacent angles are 90°).
  • The area of a trapezoid can be calculated using the lengths of the parallel sides and the perpendicular distance between them.
  • The formula to compute the area(A) of a trapezoid using the base and the height is
  • (Where, a and b are the lengths of the parallel sides and h is the height between them) 
  • In an isosceles trapezoid the diagonals are equal in length.
  • The sum total of the interior angles of a trapezoid is always equal to 360°. 

Sample Questions

Ques. What is the formula of the area of a trapezoid? (2 Marks)

Ans. The formula of the area of a trapezoid is

Area = ½ (Sum of the parallel sides) x Distance between the parallel sides

Ques. What is an isosceles and right-sided trapezoid? (2 Marks)

Ans. When a trapezoid has two equal non-parallel sides, it is called an Isosceles trapezoid while in a trapezoid when the two adjacent angles are right angles, it is called a right-sided trapezoid.

Ques. Find out the area of a trapezoid whose bases are 26cm and 42cm respectively and the perpendicular height is 9cm. (2 Marks)

Ans. In this problem,

a= 26cm; b=42 cm; and h=9cm

Applying the formula of the area of the trapezoid we get,

Area(A) = ((a+b))/2.h = 1/2(26+42)9 = 612cm2

So, the area of the trapezoid is 612cm2.

Ques. The area of a trapezoid is 660cm2, the lengths of the parallel sides are 23cm and 43cm. What would be the distance between the parallel sides? (2 Marks)

Ans. In this problem,

A = 23 cm; b = 43 cm; area A= 660 cm2

Let ‘h’ be the distance between the parallel bases.

According to the formula of the area of trapezoid,

Area (A) = ((a+b))/2.h

Rearranging it we will get,

h = (2 A)/((a+b))

= (2(660))/((23+43) )

=1320/66

=20

Therefore, the distance between the parallel bases of the garden is 20m. 

Ques. The area of a trapezoidal-shaped field is 480m2. The height of the trapezoid is 10m and one of the parallel sides is 21m in length. Find out the length of the other parallel side. (3 Marks)

Ans. In this problem,

a= 21m, h=10m and area A=480m2

Let us assume that the length of the other parallel is x cm.

According to the formula of the area of trapezoid,

Area (A)=((a+b))/2.h

Or, 480 = ((21+x))/2.10

Or, x =75m

Therefore, the length of the other parallel side is 75m.

Ques. What will be the sum of the length of the bases if the area of a trapezoid is 1000m2 and the height is 25m. (3 Marks)

Ans. In this problem,

Area of the trapezoid(A) is 1000m2 and the height(h)= 25m

Let us assume that the lengths of the parallels are ‘a’ and ‘b’ respectively.

According to the formula of the area of trapezoid,

Area (A)=((a+b))/2.h

Or, (a+b)= 2(A)/h

Or, (a+b)= 2.1000/25

= 80

Therefore, the sum length of the parallels is 80m.

Ques. Assume that one base of a trapezoid is 10cm more than the height. If the other base is 18cm and the area of the trapezoid is 480cm2, find out the height and the base of that trapezoid. (4 Marks)

Ans. Let’s assume height= x cm

The length of the base is (x+10) cm.

According to the formula of the area of trapezoid,

Area (A)=((a+b))/2.h

Or, 480= ((x+10+18))/2.x

Or, 480= ((x+28))/2.x

Or, 480= x^2/2+14x

Or, x2+ 28x-960=0

Or, (x+48)(x-20)=0

Or, x=-48,x=20

Taking the positive value of the x, we will get the height of the trapezoid is 20cm and the length of the base is (20+10)= 30 cm. 

Ques. In the given figure, find the value of ‘x’ if the area of the trapezoid is 144cm2? (3 Marks)

find the value of ‘x’ if the area of the trapezoid is 144cm2

Ans. According to the formula of the area of trapezoid,

Area (

Area (A)=((a+b))/2.h

Or, 144 = ½ (6x+12x).4x

Or, 144= ½ .72x2

Or, x= 2

So, the value of ‘x’ is 2. 

CBSE X Related Questions

1.
Which of the following pairs of linear equations are consistent/inconsistent? If consistent, obtain the solution graphically: (i) \(x + y = 5\),\( 2x + 2y = 10\) (ii)\( x – y = 8 , 3x – 3y = 16\) (iii) \(2x + y – 6 = 0\) , \(4x – 2y – 4 = 0\) (iv) \(2x – 2y – 2 = 0,\) \( 4x – 4y – 5 = 0\)

      2.

      Solve the following pair of linear equations by the substitution method. 
      (i) x + y = 14 
          x – y = 4   

      (ii) s – t = 3 
          \(\frac{s}{3} + \frac{t}{2}\) =6 

      (iii) 3x – y = 3 
            9x – 3y = 9

      (iv) 0.2x + 0.3y = 1.3 
           0.4x + 0.5y = 2.3 

      (v)\(\sqrt2x\) + \(\sqrt3y\)=0
          \(\sqrt3x\) - \(\sqrt8y\) = 0

      (vi) \(\frac{3x}{2} - \frac{5y}{3}\) =-2,
          \(\frac{ x}{3} + \frac{y}{2}\) = \(\frac{ 13}{6}\)

          3.

          The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them

          Monthly consumption 
          (in units)

           Number of consumers

          65 - 85 

          4

          85 - 105

          5

          105 - 125

          13

          125 - 145

          20

          145 - 165

          14

          165 - 185

          8

          185 - 205

          4

              4.
              Check whether \(6n\) can end with the digit \(0\) for any natural number \(n\).

                  5.

                  A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.

                      6.
                      Find the sums given below :
                      1. \(7 + 10\frac 12+ 14 + ....... + 84\)
                      2. \(34 + 32 + 30 + ....... + 10\)
                      3. \(–5 + (–8) + (–11) + ....... + (–230)\)

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