NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.1

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Exercise 7.1 is given in this article. Class 10 Maths Chapter 7 is an important chapter and its Exercise 7.1 has about 10 questions related to the distance formula.

Read More: Coordinate Geometry MCQs


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Check out the solutions of Class 10 Maths NCERT solutions chapter 7 Coordinate Geometry Exercise 7.1

Read More: NCERT Solutions For Class 10 Maths Coordinate Geometry

Check out other exercise solutions of Class 10 Maths Chapter 7


Class 10 Chapter 7 Topics:

CBSE Class 10 Maths Study Guides:

CBSE X Related Questions

  • 1.
    In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

      • $55^\circ$
      • $20^\circ$
      • $35^\circ$
      • $70^\circ$

    • 2.
      If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

        • \(\frac{7}{2}\)
        • \(\frac{6}{7}\)
        • \(\frac{-7}{6}\)
        • \(\frac{7}{6}\)

      • 3.
        If roots of the quadratic equation \(x^2 - k\sqrt{3}x + 2 = 0\) are real and equal, then value of k is

          • \(-2\)
          • \(\sqrt{\frac{8}{3}}\)
          • \(1\)
          • \(2\)

        • 4.
          In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

            • $6$
            • $4$
            • $\pm 4$
            • $3$

          • 5.
            If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

              • \(4 \text{ cm}\)
              • \(4\sqrt{2} \text{ cm}\)
              • \(8 \text{ cm}\)
              • \(2\sqrt{2} \text{ cm}\)

            • 6.
              If for a data, median is 5 and mode is 4, then mean is equal to :

                • 7
                • 11
                • \(\frac{11}{2}\)
                • \(\frac{14}{3}\)

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