Congruence Of Triangles: Conditions (SSS, SAS, ASA, RHS)

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Shekhar Suman

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Congruence of triangles is a property of two triangles. Any two triangles are said to be congruent if all the 3 corresponding sides and angles of triangles are equal in measure. Read this entire article to know about the congruence of triangles, conditions for congruence of two triangles, corresponding parts of congruent triangles and solved examples related to congruence of triangles. Two shapes are said to be congruent if their size and shape are the same. Images of two shapes are in a way that the mirror image of one should coincide with the other.

Keyterms: Geometry, Triangle, Congruence in the triangles, Angle, Area of Triangle, SSS, SAS, ASA, AAS, RHS

Read more: Nature of roots of quadratic equations


Congruent Triangles

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Two triangles are said to be congruent if their all-corresponding sides and angles are equal.

Congruent triangles
Congruent triangles

Sides: AB=BC=AC=PQ=QR=PR

Angles: ∠A=∠B=∠C=∠P=∠Q=∠R

So, we can say both triangles ABC and PQR are congruent.


Conditions for congruence of Triangles

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If there are two triangles A and B then if they fulfil any of the below mentioned conditions then they are said to be congruent and they are mentioned like below:

A\(\cong\) B

  1. SSS (Side-Side-Side) – Two triangles are said to be congruent by SSS condition if all three sides are equal.
  2. SAS(Side-Angle-Side)- Two triangles are said to be congruent by SAS condition if their two sides and 1 angle are equal.
  3. ASA(Angle-Side-Angle)- Two triangles are said to be congruent by ASA condition if their two angles and 1 side are equal.
  4. AAS(Angle-Angle-Side)- Two triangles are said to be congruent by AAS condition if their two angles and 1 side are equal.
  5. RHS (Right angle- Hypotenuse-Side)- If the hypotenuse and side of one right-angled triangle are equal to the hypotenuse and the corresponding side of another right-angled triangle, the two triangles are congruent

Read more: Pythagoras Theorem


SSS: Side-Side- Side Rule

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If all the three corresponding sides of two triangles are equal then they are said to be congruent by SSS rule.

SSS: Side-Side- Side Rule
SSS: Side-Side- Side Rule

So, in this case, 

AB=PQ

AC=PR

BC=QR

Then triangles ABC and PQR are congruent by SSS rule.


SAS: Side-Angle- Side

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If any two corresponding sides of two triangles and one angle are equal then two triangles are said to be congruent with SAS rule.

SAS: Side-Angle- Side
SAS: Side-Angle- Side

So, in this case,

AB=PQ

BC=QR and

∠A=∠P

Then triangles ABC and PQR are congruent by SAS rule.


ASA: Angle – Side - Angle

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If any two corresponding angles of two triangles and one side is equal then two triangles are said to be congruent with ASA rule.

ASA: Angle – Side - Angle
ASA: Angle – Side - Angle

So, in this case,

∠B=∠Q

BC=QR and

∠A=∠P

Then triangles ABC and PQR are congruent by ASA rule

RHS: (Right angle- Hypotenuse-Side)

Two triangles are said to be congruent by RHS If the hypotenuse and a side of a right- angled triangle is equivalent to the hypotenuse and a side of the second right- angled triangle.

Also Read:


Things to Remember

  • Congruent triangles are those triangles whose sides and angles are exactly equal. 
  • There are 4 rules to determine if two triangles are congruent: SSS, SAS, ASA, RHS
  • SSS congruence rule states that if all sides of a triangle are equal, the triangles are congruent. 
  • SAS congruence rule states that if two sides and an angle in the middle of the two sides are equal, the two triangles are congruent.
  • ASA congruence rule states that if two angles and a side in the middle of the two angle are equal, the triangles are congruent
  • RHS rule states that if in a right angled triangle hypotenuse and one side are equal, the two triangles are congruent. 

Read More: Euclidean plane geometry


Sample Questions

Ques1: In triangle ABC, if AB=AC and B= 70°, then what is the value of A? (4 Marks)

Ans. In a Δ ABC

AB=AC (Given)

B=∠C= 70°, (Angle opposite to equal sides are equal)

As per angle sum property some of 3 angles of a triangle is 180 degrees. 

∠A + ∠B +∠C= 180°

∠A+70°+70°= 180°

∠A = 180° – 140°

∠A = 40°

Ques2: What is CPCT? (2 Marks)

Ans. CPCT stands for Corresponding Parts of Congruent Triangles. It is a theorem which states that if two or more triangles which are congruent to each other then the corresponding angles and sides are also congruent to each other.

Ques3: Is it possible two equilateral triangles are always congruent? (2 Marks)

Ans. No it is not always possible. Equilateral triangle angles are of 60 degrees each but it is noy necessary that their sides are always equal.

Ques4: The length of two sides of an isosceles triangle are 5cm and 8 cm, find perimeter of triangle. (3 Marks)

Ans. If we consider two sides of isosceles triangles are 5 cm and third one 8 cm then perimeter will be 5 cm+5 cm+8 cm= 18 cm

If we consider two sides of isosceles triangles are 8 cm and third one 5 cm then perimeter will be 8 +8 +5 = 21 cm.

Ques 5: In the given figure, find these two triangles LMN and ONM are congruent and by which rule? (4 Marks)
In the given figure, find these two triangles LMN and ONM are congruent

Ans. In ΔLMN and ΔONM

LM=ON

LN=OM

MN=NM

By SSS rule, ΔLMN and ΔONM are congruent.

Ques 5: The triangle ABC is an isosceles triangle. In the given figure, AB = AC and AP = AQ. Show that CP = BQ. (4 Marks)

Ans.

The triangle ABC is an isosceles triangle

Given: In ΔABQ and ΔACP, 

AB = AC (Stated in question)

∠BAQ = ∠CAP (Common angle)

AQ = AP (Stated in question)

Hence using SAS congruence,

ΔABQ \(\cong\)ΔACP

So, CP = BQ (Corresponding parts of congruent triangles) 

Ques 6: ΔABC and ΔDBC are 2 isosceles triangles on the same base, as shown in the figure. The line segment BC and vertices A and D are on the same side of BC and AD has been extended to intersect BC at P. Prove that : (i) ΔABD \(\cong\) ΔACD (ii) ΔABP \(\cong\) ΔACP (4 Marks)
ΔABC and ΔDBC are 2 isosceles triangles on the same base

Ans: (i) In the triangles ABD & ACD,

It is given that AB = AC and BD = CD. 

AD is common to both triangles. 

So, using SSS congruence, 

ΔABD \(\cong\) ΔACD

(ii) In the triangles ABP & ACP,

It is given that AB = AC 

∠BAP = ∠CAP [corresponding parts of congruent triangles, ΔABD \(\cong\) ΔACD]

AP is common to both triangles. 

So SAS congruence rule, 

ΔABP \(\cong\) ΔACP

Ques 7: In the figure given below, AE = AD & BD = CE. Show that ΔAEB \(\cong\) ΔADC. (4 Marks)
In the figure given below, AE = AD & BD = CE.

Ans: It is given that AE = AD … (a)

& CE = BD … (b)

Adding (a) and (b), 

We get AE + CE = AD + BD

So, AC = AB … (c)

In ΔAEB & ΔADC,

It is given that AE = AD 

AB = AC (from (c))

∠A is common in both the triangles.

So, using SAS congruence criteria, 

ΔAEB is congruent to ΔADC

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CBSE X Related Questions

1.

Form the pair of linear equations for the following problems and find their solution by substitution method.

(i) The difference between two numbers is 26 and one number is three times the other. Find them.

(ii) The larger of two supplementary angles exceeds the smaller by 18 degrees. Find them.

(iii) The coach of a cricket team buys 7 bats and 6 balls for Rs 3800. Later, she buys 3 bats and 5 balls for Rs 1750. Find the cost of each bat and each ball.

(iv) The taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km, the charge paid is Rs 105 and for a journey of 15 km, the charge paid is Rs 155. What are the fixed charges and the charge per km? How much does a person have to pay for travelling a distance of 25 km.

(v) A fraction becomes\(\frac{ 9}{11}\), if 2 is added to both the numerator and the denominator. If, 3 is added to both the numerator and the denominator it becomes \(\frac{5}{6}\). Find the fraction.

(vi) Five years hence, the age of Jacob will be three times that of his son. Five years ago, Jacob’s age was seven times that of his son. What are their present ages?

      2.
      Find the sums given below :
      1. \(7 + 10\frac 12+ 14 + ....... + 84\)
      2. \(34 + 32 + 30 + ....... + 10\)
      3. \(–5 + (–8) + (–11) + ....... + (–230)\)

          3.
          Which of the following are APs? If they form an AP, find the common difference d and write three more terms.
          (i) 2, 4, 8, 16, . . . .
          (ii) \(2, \frac{5}{2},3,\frac{7}{2}\), . . . .
          (iii) – 1.2, – 3.2, – 5.2, – 7.2, . . . .
          (iv) – 10, – 6, – 2, 2, . . .
          (v) 3, \(3 + \sqrt{2} , 3 + 3\sqrt{2} , 3 + 3 \sqrt{2}\) . . . .
          (vi) 0.2, 0.22, 0.222, 0.2222, . . . .
          (vii) 0, – 4, – 8, –12, . . . .
          (viii) \(\frac{-1}{2}, \frac{-1}{2}, \frac{-1}{2}, \frac{-1}{2}\), . . . .
          (ix) 1, 3, 9, 27, . . . .
          (x) a, 2a, 3a, 4a, . . . .
          (xi) a, \(a^2, a^3, a^4,\)  . . . .
          (xii) \(\sqrt{2}, \sqrt{8} , \sqrt{18} , \sqrt {32}\) . . . .
          (xiii) \(\sqrt {3}, \sqrt {6}, \sqrt {9} , \sqrt {12}\) . . . . .
          (xiv) \(1^2 , 3^2 , 5^2 , 7^2\), . . . .
          (xv) \(1^2 , 5^2, 7^2, 7^3\), . . . .

              4.
              Which of the following pairs of linear equations are consistent/inconsistent? If consistent, obtain the solution graphically: (i) \(x + y = 5\),\( 2x + 2y = 10\) (ii)\( x – y = 8 , 3x – 3y = 16\) (iii) \(2x + y – 6 = 0\) , \(4x – 2y – 4 = 0\) (iv) \(2x – 2y – 2 = 0,\) \( 4x – 4y – 5 = 0\)

                  5.
                  The angle of elevation of the top of a building from the foot of the tower is 30° and the angle of elevation of the top of the tower from the foot of the building is 60°. If the tower is 50 m high, find the height of the building.

                      6.
                      A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from 30° to 60° as he walks towards the building. Find the distance he walked towards the building.

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