CBSE Class 10 Science Question Paper 2024 PDF (Set 2 - 31/4/2) is available for download here. CBSE conducted the Science exam on March 2, 2024, from 10:30 AM to 1:30 PM. The total marks for the theory paper are 80. The question paper contains 20% MCQ-based questions, 40% competency-based questions, and 40% short and long answer type questions.
CBSE Class 10 Science Question Paper 2024 (Set 2 - 31/4/2) with Answer Key
| CBSE Class 10 Science Question Paper 2024 (Set 2 - 31/4/2) with Answer Key |  Download |
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CBSE Science Question Paper (Set 2 – 31/4/2) 2024 Solution
| Question | Answer | Detailed Solution |
|---|---|---|
| 1. A chemical reaction in which exchange of ions occurs between the reactants is known as: (A) Endothermic Reaction (B) Exothermic Reaction (C) Double Displacement Reaction (D) Displacement Reaction |
(C) Double Displacement Reaction | A double displacement reaction involves the exchange of ions between two reactants, forming new products. Example: NaCl + AgNO3 → NaNO3 + AgCl. These reactions often result in the formation of a precipitate, gas, or water. |
| 2. A zygote is formed by the fusion of a male gamete and a female gamete. The number of chromosomes in the zygote of a human is: (A) 23 (B) 44 (C) 46 (D) 92 |
(C) 46 | In humans, the male gamete (sperm) and female gamete (egg) each contribute 23 chromosomes. The zygote thus has 46 chromosomes (23 pairs), which include 22 pairs of autosomes and 1 pair of sex chromosomes. |
| 3. The part of the seed which is a source of food during germination is: (A) Cotyledon (B) Radicle (C) Plumule (D) Embryo |
(A) Cotyledon | Cotyledons store food for the germinating seedling. The food is used until the plant can produce its own through photosynthesis. Radicle develops into roots, and plumule develops into the shoot. |
| 4. The plants that can be raised by the method of vegetative propagation are: (A) Sugarcane, roses, grapes (B) Sugarcane, mustard, potato (C) Banana, orange, mustard (D) Papaya, mustard, potato |
(A) Sugarcane, roses, grapes | Vegetative propagation allows new plants to grow from parts like stems or roots. Sugarcane, roses, and grapes propagate through stem cuttings or layering, ensuring uniform and rapid growth. |
| 5. A plant growth inhibitor hormone which causes wilting of leaves is called: (A) Auxin (B) Cytokinin (C) Abscisic Acid (D) Gibberellin |
(C) Abscisic Acid | Abscisic acid is a stress hormone in plants that induces dormancy and regulates stomatal closure during water stress, causing wilting. |
| 6. An aqueous solution of a salt turns blue litmus to red. The salt could be obtained by the reaction of: (A) HNO3 and NaOH (B) H2SO4 and KOH (C) CH3COOH and NaOH (D) HCl and NH4OH |
(D) HCl and NH4OH | Ammonium chloride (NH4Cl) is formed when HCl reacts with NH4OH. It is an acidic salt that turns blue litmus paper red. |
| 7. Four solutions, namely glucose, alcohol, hydrochloric acid, and sulphuric acid, are connected one by one in an electric circuit with a bulb. The solutions in which the bulb will glow are: (A) Glucose and alcohol (B) Alcohol and hydrochloric acid (C) Glucose and sulphuric acid (D) Hydrochloric acid and sulphuric acid |
(D) Hydrochloric acid and sulphuric acid | Hydrochloric acid (HCl) and sulphuric acid (H2SO4) ionize in water, allowing them to conduct electricity, whereas glucose and alcohol do not ionize. |
| 8. The metals which are found in both free state as well as combined state are: (A) Gold and platinum (B) Platinum and silver (C) Copper and silver (D) Gold and silver |
(C) Copper and silver | Copper and silver are found in free states due to low reactivity and in combined states like ores (e.g., copper sulphide and silver sulphide). |
| 9. The number of single and double bonds present in a molecule of benzene (C6H6) respectively, are: (A) 6 and 6 (B) 9 and 3 (C) 3 and 9 (D) 3 and 3 |
(B) 9 and 3 | Benzene consists of 9 single bonds (6 C-H and 3 C-C) and 3 double bonds (C=C) arranged in an alternating pattern, contributing to its resonance structure. |
| 10. In human beings, when the process of digestion is completed, the (i) proteins, (ii) carbohydrates, and (iii) fats are respectively converted into: (A) (i) Amino acids, (ii) glucose, and (iii) fatty acids (B) (i) Amino acids, (ii) glucose, and (iii) fatty acids and glycerol (C) (i) Glucose, (ii) fatty acids and glycerol, and (iii) amino acids (D) (i) Sugars, (ii) amino acids, and (iii) fatty acids and glycerol |
(B) (i) Amino acids, (ii) glucose, and (iii) fatty acids and glycerol | Proteins are digested into amino acids, carbohydrates into glucose, and fats into fatty acids and glycerol. These are absorbed and used for energy, growth, and repair. |
| 11. The non-biodegradable wastes among the following are: (i) Garden waste (ii) Ball point pen refills (iii) Empty medicine bottles made of glass (iv) Peels of fruits and vegetables (v) Old cotton shirt (A) (i) and (ii) (B) (ii) and (iii) (C) (i), (iv), and (v) (D) (i), (iii), and (iv) |
(B) (ii) and (iii) | Non-biodegradable wastes are those that cannot be broken down by natural processes. Among the options, ball point pen refills (plastic) and empty glass bottles do not degrade naturally, unlike garden waste, fruit peels, and cotton shirts. |
| 12. A rectangular loop carrying a current is placed near a straight conductor with steady current. The straight conductor will: (A) Remain stationary (B) Move towards the loop (C) Move away from the loop (D) Rotate about its axis |
(B) Move towards the loop | Magnetic interaction causes attraction between the parallel currents in the loop and conductor. According to the right-hand rule, the conductors with currents in the same direction attract each other. |
| 13. Absolute refractive index of glass is 3/2 and water is 4/3. If the speed of light in glass is 2 × 108 m/s, the speed of light in water is: (A) 9/4 × 108 m/s (B) 5/2 × 108 m/s (C) 7/3 × 108 m/s (D) 16/9 × 108 m/s |
(A) 9/4 × 108 m/s | Using the relation \( n = c / v \), where \( c = 3 × 108 \) m/s and \( v \) is the speed of light in the medium, the calculated speed in water is \( v_{water} = 9/4 × 108 \) m/s. |
| 14. The color of light scattered by fine dust particles is: (A) Red (B) Orange (C) Blue (D) Yellow |
(C) Blue | According to Rayleigh's scattering law, shorter wavelengths, like blue, scatter more than longer wavelengths, such as red, leading to the dominance of blue in scattered light. |
| 15. Which of the following resistor combinations have an equivalent resistance of 1 Ω? (A) I and IV (B) Only IV (C) I and II (D) I, II, and III |
(C) I and II | Calculating resistance for each setup confirms that combinations I and II provide 1 Ω equivalent resistance based on series and parallel resistor rules. |
| 16. An electric iron of resistance 20 Ω draws a current of 5 A. The heat developed in the iron in 30 seconds is: (A) 15000 J (B) 6000 J (C) 1500 J (D) 3000 J |
(A) 15000 J | Using Joule's law of heating, ( H = I^2 R t ): Given ( I = 5 ,A, R = 20, t = 30 , s), the heat developed is ( H = (5)^2 . 20 . 30 = 15000J). |
| 17. Assertion (A): Oxygen is essential for all aerobic forms of life. Reason (R): Free oxygen atoms combine with molecular oxygen to form ozone. (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A). (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A). (C) Assertion (A) is true, but Reason (R) is false. (D) Assertion (A) is false, but Reason (R) is true. |
(B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A). | While both statements are true, the reason does not explain why oxygen is essential for aerobic life. Oxygen is required for energy production in cells through aerobic respiration, which is unrelated to ozone formation. |
| 18. Assertion (A): Most plants close their stomata at night. Reason (R): Closing of stomata helps to conserve water as a large amount of water evaporates from the leaves. (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A). (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A). (C) Assertion (A) is true, but Reason (R) is false. (D) Assertion (A) is false, but Reason (R) is true. |
(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A). | Plants close their stomata at night to conserve water as photosynthesis is inactive in the absence of sunlight. This prevents unnecessary water loss through transpiration. |
| 19. Assertion (A): The extraction of metals from their sulphide ores cannot take place without roasting of the ore. Reason (R): Roasting converts sulphide ores directly into metals. (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A). (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A). (C) Assertion (A) is true, but Reason (R) is false. (D) Assertion (A) is false, but Reason (R) is true. |
(B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A). | Roasting converts sulphide ores into oxides, not directly into metals. Oxides are then reduced to extract metals. Thus, while roasting is necessary, the reason provided is inaccurate. |
| 20. Assertion (A): Magnetic field lines never intersect each other. Reason (R): If they intersect, then at the point of intersection, the compass needle would point towards two directions, which is not possible. (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A). (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A). (C) Assertion (A) is true, but Reason (R) is false. (D) Assertion (A) is false, but Reason (R) is true. |
(A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A). | Magnetic field lines never intersect because the direction of the magnetic field at any given point is unique. If they intersected, a compass needle would have conflicting directions, which is impossible. |
| 21. (a) We need to water the soil in plants on a regular basis. But it ultimately reaches the leaves of the plant. Explain how this takes place. | (a) Ascent of sap | (a) Water absorbed by root hairs through osmosis moves through root cortex to xylem vessels. Transpiration pull created by evaporation of water from leaves helps in upward movement of water. |
| OR 21.(b) Name the type of nutrition exhibited by Amoeba. Explain how food is taken in and digested by this organism. | (b) Holozoic nutrition | (b) Amoeba exhibits holozoic nutrition. It engulfs food particles using pseudopodia to form a food vacuole. Digestive enzymes break down the food, and nutrients are absorbed into the cytoplasm. Undigested material is expelled outside. |
| 22. A spatula full of sodium carbonate is taken in a test tube and 2 mL of dilute ethanoic acid is added to it. (a) Write a chemical equation for the reaction. (b) Suggest a method of testing the gas liberated in the reaction. |
(a) Na2CO3 + 2CH3COOH → 2CH3COONa + CO2 + H2O (b) Lime water test |
(a) Sodium carbonate reacts with ethanoic acid to produce sodium ethanoate, carbon dioxide, and water. (b) The gas liberated is carbon dioxide. Passing the gas through lime water turns it milky due to the formation of calcium carbonate. |
| 23. (a) 1 gram of solid sodium chloride was taken in a clean and dry test tube and concentrated sulfuric acid was added to it. (i) Name the gas evolved in the reaction. (ii) What will be observed when this gas is tested with (I) dry and (II) wet blue litmus paper? Write your conclusion about the nature of the gas. |
(a) (i) HCl (ii) Dry litmus: No change; Wet litmus: Turns red |
(a) (i) The gas evolved is hydrogen chloride (HCl). (ii) Dry litmus shows no change as dry HCl gas does not ionize. Wet litmus turns red due to acidic properties of HCl in moisture. |
| OR 23.(b) Some metals react with acids to produce salt and hydrogen gas. Illustrate with an example. How will you test the presence of this gas? | (b) Reaction: Zn + H2SO4 → ZnSO4 + H2 | (b) Zinc reacts with sulfuric acid to produce zinc sulfate and hydrogen gas. The presence of hydrogen can be confirmed by the "pop" sound when a burning splinter is brought near the gas. |
| 24. Mendel crossed pea plants with two pairs of contrasting characters: RRYy (Round, Yellow) × rryy (Wrinkled, Green). He observed 4 types of combinations in the F2 generation. Which of the combinations were new? Write the conclusion drawn by this experiment. | New combinations: Round-Green, Wrinkled-Yellow | Mendel observed new combinations: Round-Green (RRyy) and Wrinkled-Yellow (rrYy). He concluded that the inheritance of two traits occurs independently, leading to the Law of Independent Assortment. |
| 25. Name the phenomenon of light responsible for Tyndall effect. Write an event where this phenomenon can be observed. | Scattering of light | The Tyndall effect is caused by the scattering of light by small particles. It can be observed when sunlight passes through a canopy of trees in a forest, making the path of the light beam visible. |
| 26. State Joule’s law of heating. How is this effect useful in electric circuits where a fuse is used as a safety device? | Joule’s Law of Heating | Joule's law states that the heat produced in a conductor is directly proportional to the square of the current (I), resistance (R), and time (t): \( H = I^2 R t \) In electric circuits, this principle is used in fuses. When excessive current flows, the heat generated increases rapidly, causing the fuse to melt and break the circuit. This prevents damage to devices and reduces fire hazards. |
| 27. A small amount of copper oxide was taken in a beaker and dilute hydrochloric acid was added with continuous stirring of the solution. Name the compound formed and state the colour of its solution. Write the balanced chemical equation for the reaction that occurs. Based on the reaction, state the nature (acidic/basic) of copper oxide. | Copper(II) chloride, green solution | The compound formed is copper(II) chloride (CuCl2) and the solution is green in colour. The balanced chemical equation is: CuO + 2HCl → CuCl2 + H2O Copper oxide is basic in nature as it reacts with acid to form a salt and water. |
| 28. Define the term power of accommodation of the human eye. What happens to the image distance in the eye when we increase the distance of an object from the eye? Name and explain the role of the part of the human eye responsible for this adjustment. | Power of accommodation | The power of accommodation is the ability of the eye to adjust the focal length of its lens to focus on objects at varying distances. When the object distance increases, the image distance remains constant as the eye lens focuses the image on the retina. This adjustment is achieved by the ciliary muscles, which change the curvature of the lens to modify its focal length. |
| 29. Study the picture showing three food chains and answer the following questions: (i) Name the type of ecosystems that exist in food chains (b) and (c). (ii) The first trophic level in all food chains are producers. Why? What percentage of solar energy do these producers capture for their use? (iii) Why are the arrows shown in the diagram in one direction only and not vice versa? Justify. |
(i) Grassland and aquatic (ii) Producers capture 1% (iii) One-way energy flow |
(i) Ecosystem types: - (b): Grassland - (c): Aquatic (ii) Producers are the first trophic level as they convert solar energy into chemical energy through photosynthesis. They capture about 1% of solar energy. (iii) Energy flows in a one-way direction in food chains, from producers to consumers, and is not recycled back. Each transfer results in energy loss, primarily as heat. |
| 30. How is the sex of a newborn individual determined in different species of animals? Give three examples to support your answer. | Genetic and environmental | The sex of a newborn is determined by genetic or environmental factors depending on the species: - Humans: XY system, where males are XY and females are XX. The sperm determines the sex of the offspring. - Birds: ZW system, where males are ZZ and females are ZW. The egg determines the sex. - Turtles: Temperature-dependent. High incubation temperatures produce females, while low temperatures produce males. |
| 31. Why is the conversion of ethanol to ethanoic acid an oxidation reaction? Name the oxidising agent used in this conversion. Write the chemical equation for this oxidation reaction. How is this reaction different from the reaction in which ethanol burns in the presence of oxygen? | Oxidation reaction | The conversion of ethanol to ethanoic acid is an oxidation reaction because ethanol gains oxygen or loses hydrogen atoms during the reaction. Oxidising agents like alkaline potassium permanganate (KMnO4) or acidified potassium dichromate (K2Cr2O7) are used. Chemical equation: C2H5OH + [O] → CH3COOH + H2O Difference: Controlled oxidation converts ethanol to ethanoic acid. During combustion, ethanol reacts with oxygen to form carbon dioxide, water, and energy. Combustion equation: C2H5OH + 3O2 → 2CO2 + 3H2O + Heat |
| 32. (a) How is a solenoid prepared? Differentiate between a circular coil and a solenoid. (b) Draw the pattern of the magnetic field lines inside a current-carrying solenoid. What does this pattern indicate? |
Solenoid preparation and magnetic field | (a) A solenoid is prepared by winding insulated copper wire tightly into a cylindrical coil around a core material, such as soft iron. When electric current flows, it behaves like a magnet. Differences: - Circular coil: Single loop with weaker magnetic field. - Solenoid: Multiple loops forming a uniform, strong magnetic field. (b) Inside a solenoid, magnetic field lines are uniform, strong, and parallel, resembling those of a bar magnet. This pattern indicates the solenoid acts like a bar magnet with distinct poles. |
| 33. (a) Explain with the help of a labelled diagram, the process of reproduction in Hydra by budding. Name the cells used for reproduction in this process. | (a) Hydra budding | (a) Hydra reproduces asexually through budding. Small outgrowths (buds) develop on the parent Hydra due to mitotic cell division. These mature and detach to form a new Hydra. Cells involved: Undifferentiated cells. |
| OR 33.(b) List two roles of each of the following in the human reproductive system: (i) Seminal vesicles and prostate gland (ii) Oviduct (iii) Testis |
(b) Roles in reproduction | (b) Roles: (i) Seminal vesicles and prostate gland: Produce seminal fluid that nourishes and facilitates sperm movement. (ii) Oviduct: Site of fertilisation; carries the zygote to the uterus. (iii) Testis: Produces sperm and testosterone, essential for male characteristics. |
| 34. (a) When lead nitrate is heated strongly in a boiling tube, two gases are liberated, and a solid residue is left behind in the test tube. (i) Name the type of chemical reaction and define it. (ii) Write the name and formula of the coloured gas liberated. (iii) Write the balanced chemical equation for the reaction. (iv) Name the residue left in the test tube and state the method of testing its nature. |
(a) Thermal decomposition | (a) (i) Thermal decomposition: A compound breaks down into simpler substances when heated. (ii) Coloured gas: Nitrogen dioxide (NO2, reddish-brown). (iii) 2Pb(NO3)2 → 2PbO + 4NO2 + O2 (iv) Residue: Lead oxide (PbO), tested by its basic nature (turns red litmus blue). |
| OR 34.(b) (i) Write a balanced chemical equation for the reaction: Lead nitrate + Potassium iodide → Lead iodide + Potassium nitrate. Is this a double displacement reaction? Justify. (ii) Write the method of preparation of Ca(OH)2. What happens when CO2 is passed through it? Write the balanced chemical equation for the reaction involved. |
(b) Double displacement |
(b) (i) Pb(NO3)2 + 2KI → PbI2 (yellow precipitate) + 2KNO3. Double displacement as ions exchange places. (ii) CaO + H2O → Ca(OH)2. Reaction with CO2: Ca(OH)2 + CO2 → CaCO3 + H2O. |
| 35. (a) The variation of image distance (v) with object distance (u) for a convex lens is given below: | Object distance (u) (cm) | Image distance (v) (cm) | | -150 | +30 | | -75 | +37.5 | | -50 | +50 | | -37.5 | +75 | | -30 | +150 | | -15 | +37.5 | (i) Without calculation, find the focal length of the convex lens. Justify. (ii) Which observation is incorrect? Why? (iii) Find the approximate magnification for u = -30 cm. |
Focal length: 25 cm | (a) (i) From the table, focal length f = 25 cm, as u = -50 and v = +50 satisfy the lens formula. (ii) Observation -15, +37.5 is incorrect as it violates the lens formula. (iii) Magnification m = v/u = 150/(-30) = -5. |
| OR 35.(b) (i) Define principal axis of a lens. Draw a ray diagram to show what happens when a ray of light parallel to the principal axis of a concave lens passes through it. (ii) The focal length of a concave lens is 20 cm. At what distance from the lens should a 5 cm tall object be placed so that its image is formed at a distance of 15 cm? Calculate the size of the image. |
Magnification: -5 | (b) (i) The principal axis is an imaginary line passing through the optical center and focal points of the lens. (ii) Lens formula: 1/f = 1/v - 1/u. Substituting f = -20, v = -15, u = -60 cm. Magnification: m = v/u = 1.25 cm (image height). |
| 36. (a) (i) Define a reflex arc. Why have reflex arcs evolved in animals? Trace the sequence of events which occur when you suddenly touch a hot object. (ii) Name the part of the nervous system which helps in communication between the central nervous system and other parts of the body. What are the two components of this system? |
Reflex arc and geotropism | (a) (i) A reflex arc is the pathway that mediates a reflex action, allowing rapid and involuntary responses to stimuli. Reflex arcs evolved to protect organisms from harm by providing immediate reactions. Events: Heat stimulates receptors → Sensory neuron → Spinal cord → Motor neuron → Effector muscle withdraws hand. (ii) Peripheral nervous system (PNS) connects CNS with the body. Components: Somatic (voluntary actions) and Autonomic (involuntary actions). |
| OR 36.(b) (i) Leaves of the 'chhui-mui' plant begin to fold up and droop in response to a stimulus. Name the stimulus and write the cause for such a rapid movement. Is there any growth involved in the movement? (ii) Define geotropism in plants. What is meant by positive and negative geotropism? Give one example of each type. |
Nervous and plant movements | (b) (i) Stimulus: Touch. Cause: Turgor pressure changes in pulvini cells at the base of leaflets cause rapid folding. No growth is involved. (ii) Geotropism: Plant response to gravity. Positive geotropism: Roots grow downwards (e.g., roots). Negative geotropism: Shoots grow upwards (e.g., stems). |
| 37. Study the following circuit: (a) Find the value of total resistance between points A and B. (b) Find the resistance between points B and C. (c) (i) Calculate the current drawn from the battery when the key is closed. |
Resistance and potential difference | (a) Resistance between A and B: \( R_{AB} = 4 Ω + 6 Ω + 16 Ω = 26 Ω \). (b) Resistance between B and C: Two 8 Ω resistors in parallel: \( 1/R_{BC} = 1/8 + 1/8 = 2/8 \). Hence, \( R_{BC} = 4 Ω \). (c) (i) Total resistance: \( R_{total} = R_{AB} + R_{BC} = 26 Ω + 4 Ω = 30 Ω \). Using Ohm's law: \( I = V/R = 6V/30Ω = 0.2 A \). OR |
| OR 37.(c) (ii) In the above circuit, which will have more potential difference across its ends: the 16 Ω resistor or the parallel combination of two 8 Ω resistors? Justify your answer. | 16 Ω | (c) (ii) The 16 Ω resistor will have a larger potential difference across its ends because it has a greater resistance compared to the parallel combination of two 8 Ω resistors. In a series circuit, ( V = IR ), and the higher resistance gets a larger share of the total voltage. |
| 38. Three metal samples of magnesium, aluminium, and iron were taken and rubbed with sandpaper. They were put separately in test tubes containing dilute hydrochloric acid and the temperature changes were observed. (a) Which test tube had the fastest rate of bubble formation and highest temperature? (b) Which metal did not react with dilute hydrochloric acid? Give a reason. (c) (i) Why is hydrogen gas not evolved when a metal reacts with dilute nitric acid? Name the products formed. |
Metal reactivity |
(a) Magnesium reacted fastest with dilute HCl, producing the highest temperature due to its high reactivity. (b) Copper did not react with HCl as it is less reactive than hydrogen and cannot displace it. (c) (i) Nitric acid oxidises hydrogen gas into water. Products: Metal nitrate and water. |
| OR 38.(c) (ii) Name the type of reaction on which the reactivity of metals is based. How would you determine which metal is more reactive: X or Y? | Displacement reaction | (c) (ii) Reaction: Displacement. Metal X and Y are tested by placing them in each other's salt solutions. The more reactive metal will displace the other from its salt solution. |
| 39. Kidneys are vital for survival. Several factors can reduce their function, leading to waste accumulation and death. In case of failure, an artificial kidney is used for dialysis. (a) (i) Name the artery that brings oxygenated blood to the kidney. (ii) Name the cluster of blood capillaries in the Bowman’s capsule. (b) Name the organ that stores urine. Is this organ under hormonal or nervous control? (c) (i) List two major steps involved in the formation of urine and their functions. |
Renal function |
(a) (i) Renal artery. |
| OR 39.(c) (ii) In which part of the nephron does selective reabsorption take place? List the factors influencing water reabsorption. | Nephron reabsorption |
(c) (ii) Selective reabsorption occurs in the proximal convoluted tubule. Factors: Hormonal control (ADH), hydration status, and solute concentration in filtrate. |
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