NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.5

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NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability comprises all solutions for all Exercise 5.5 questions. Exercise 5.5 is based on logarithmic differentiation. NCERT Solutions for Class 12 Maths Chapter 5 will carry a weightage of around 8-17 marks in the CBSE Term 2 Exam 2022. NCERT has provided a total of 18 problems and solutions based on the important topic covered in this exercise.

Download PDF NCERT Solutions for Class 12 Chapter 5 Continuity and Differentiability Exercise 5.5

NCERT Solutions for Class 12 Maths Chapter 5: Important Topics

Important topics covered in the Continuity and Differentiability chapter are:

Mean Value Theorem
Rolle’s Theorem
Limits
Euler’s Number
Quotient Rule

Also check: NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability

CBSE CLASS XII Related Questions

1.
Based upon the results of regular medical check-ups in a hospital, it was found that out of 1000 people, 700 were very healthy, 200 maintained average health and 100 had a poor health record.
Let $ A_1 $: People with good health,
$ A_2 $: People with average health,
and $ A_3 $: People with poor health.
During a pandemic, the data expressed that the chances of people contracting the disease from category $ A_1, A_2 $ and $ A_3 $ are 25%, 35% and 50%, respectively.
Based upon the above information, answer the following questions:
(i) A person was tested randomly. What is the probability that he/she has contracted the disease?}
(ii) Given that the person has not contracted the disease, what is the probability that the person is from category $ A_2 $?
View Solution
2.
Find $ \int \frac{3x + 1}{(x - 2)^2 (x + 2)} \, dx $
View Solution
3.
Solve the differential equation $ (x - \sin y) \, dy + (\tan y) \, dx = 0 $, given $ y(0) = 0 $.
View Solution
4.
Let $ \vec{a} $ be a position vector whose tip is the point (2, -3). If $ \overrightarrow{AB} = \vec{a} $, where coordinates of A are (–4, 5), then the coordinates of B are:
- (-2, -2)
- (2, -2)
- (-2, 2)
- (2, 2)
View Solution
5.
The given graph illustrates:
- $y = \tan^{-1} x$
- $y = \csc^{-1} x$
- $y = \cot^{-1} x$
- $y = \sec^{-1} x$
View Solution
6.
If $ f(x) = \begin{cases} \frac{\sin^2 ax}{x^2}, & \text{if } x \neq 0 \\ 1, & \text{if } x = 0 \end{cases} $ is continuous at $ x = 0 $, then the value of 'a' is :
- 1
- -1
- 0
- $ \pm 1 $
View Solution

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NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability

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NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.2

NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.3

NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.4

CBSE CLASS XII Previous Year Papers

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Mathematics NCERT Solutions

NCERT Solutions For Class 12 Mathematics Chapter 13: Probability

NCERT Solutions For Class 12 Mathematics Chapter 9: Differential Equations

NCERT Solutions For Class 12 Mathematics Chapter 7 Integrals

NCERT Solutions For Class 12 Mathematics Chapter 12: Linear Programming

NCERT Solutions for Class 12 Maths Chapter 3 Matrices

NCERT Solutions For Class 12 Mathematics Chapter 6 Applications of Derivatives

NCERT Solutions For Class 12 Mathematics Chapter 2 Inverse Trigonometric Functions

NCERT Solutions for Class 12 Maths Chapter 4 Determinants

NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability

NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra

You can also check

Exercise 5.1 Solutions	34 Questions (Short Answers)
Exercise 5.2 Solutions	10 Questions(Short Answers)
Exercise 5.3 Solutions	15 Questions ( Short Answers)
Exercise 5.4 Solutions	10 Questions (Short Answers)
Exercise 5.5 Solutions	18 Questions ( Short Answers)
Exercise 5.6 Solutions	11 Questions (Short Answers)
Exercise 5.7 Solutions	17 Questions (Short Answers)
Exercise 5.8 Solutions	6 Questions (Short Answers)
Miscellaneous Exercise Solutions	23 Questions (6 Long Answers, 17 Short Answers)

Mean Value Theorem	Difference quotient formula	Rolle’s Theorem
Binary Operations	Exponential growth formula	Second Order Derivative
Continuous Function	Mean value theorem formula	Limits and Continuity
Slope of secant line formula	Quotient Rule	Euler’s Number

NCERT Solutions for Class 12 Maths	Maths MCQs	Maths Syllabus
Maths Study Material	Trigonometry	Arithmetic
Mathematics Notes	Permutation and Combination	Algebra

NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.5

Download PDF NCERT Solutions for Class 12 Chapter 5 Continuity and Differentiability Exercise 5.5

NCERT Solutions for Class 12 Maths Chapter 5: Important Topics

Other Exercise Solutions of Class 12 Maths Chapter 5 Continuity and Differentiability

CBSE CLASS XII Related Questions

2.
Find \( \int \frac{3x + 1}{(x - 2)^2 (x + 2)} \, dx \)

3.
Solve the differential equation \( (x - \sin y) \, dy + (\tan y) \, dx = 0 \), given \( y(0) = 0 \).

4.
Let \( \vec{a} \) be a position vector whose tip is the point (2, -3). If \( \overrightarrow{AB} = \vec{a} \), where coordinates of A are (–4, 5), then the coordinates of B are:

5.
The given graph illustrates:

6.
If \( f(x) = \begin{cases} \frac{\sin^2 ax}{x^2}, & \text{if } x \neq 0 \\ 1, & \text{if } x = 0 \end{cases} \) is continuous at \( x = 0 \), then the value of 'a' is :

Similar Mathematics Concepts

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NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exercise 5.5

Download PDF NCERT Solutions for Class 12 Chapter 5 Continuity and Differentiability Exercise 5.5

NCERT Solutions for Class 12 Maths Chapter 5: Important Topics

Other Exercise Solutions of Class 12 Maths Chapter 5 Continuity and Differentiability

CBSE CLASS XII Related Questions

2.Find \( \int \frac{3x + 1}{(x - 2)^2 (x + 2)} \, dx \)

3.Solve the differential equation \( (x - \sin y) \, dy + (\tan y) \, dx = 0 \), given \( y(0) = 0 \).

4.Let \( \vec{a} \) be a position vector whose tip is the point (2, -3). If \( \overrightarrow{AB} = \vec{a} \), where coordinates of A are (–4, 5), then the coordinates of B are:

5.The given graph illustrates:

6.If \( f(x) = \begin{cases} \frac{\sin^2 ax}{x^2}, & \text{if } x \neq 0 \\ 1, & \text{if } x = 0 \end{cases} \) is continuous at \( x = 0 \), then the value of 'a' is :

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

2.
Find \( \int \frac{3x + 1}{(x - 2)^2 (x + 2)} \, dx \)

3.
Solve the differential equation \( (x - \sin y) \, dy + (\tan y) \, dx = 0 \), given \( y(0) = 0 \).

4.
Let \( \vec{a} \) be a position vector whose tip is the point (2, -3). If \( \overrightarrow{AB} = \vec{a} \), where coordinates of A are (–4, 5), then the coordinates of B are:

5.
The given graph illustrates:

6.
If \( f(x) = \begin{cases} \frac{\sin^2 ax}{x^2}, & \text{if } x \neq 0 \\ 1, & \text{if } x = 0 \end{cases} \) is continuous at \( x = 0 \), then the value of 'a' is :