NCERT Solutions for Class 12 Chapter 13 Probability Exercise 13.4

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Class 12 Maths NCERT Solutions Chapter 13 Probability Exercise 13.4 is based on Random Variables and its Probability Distributions. Key topics covered under these concepts are:

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CBSE CLASS XII Related Questions

  • 1.
    The probability that a student buys a colouring book is 0.7, and a box of colours is 0.2. The probability that she buys a colouring book, given that she buys a box of colours, is 0.3. Find:
    (i) The probability that she buys both the colouring book and the box of colours.
    (ii) The probability that she buys a box of colours given she buys the colouring book.


      • 2.

        Prove that:
        \( \tan^{-1}(\sqrt{x}) = \frac{1}{2} \cos^{-1}\left( \frac{1 - x}{1 + x} \right), \quad x \in [0, 1] \)


          • 3.

            A carpenter needs to make a wooden cuboidal box, closed from all sides, which has a square base and fixed volume. Since he is short of the paint required to paint the box on completion, he wants the surface area to be minimum.
            On the basis of the above information, answer the following questions :
            Find \( \frac{dS}{dx} \).


              • 4.
                The domain of the function \( f(x) = \cos^{-1}(2x) \) is:

                  • \([-1, 1]\)
                  • \(\left[0, \frac{1}{2}\right]\)
                  • \([-2, 2]\)
                  • \(\left[-\frac{1}{2}, \frac{1}{2}\right]\)

                • 5.

                  Let \( \vec{a} \) and \( \vec{b} \) be two co-initial vectors forming adjacent sides of a parallelogram such that:
                  \[ |\vec{a}| = 10, \quad |\vec{b}| = 2, \quad \vec{a} \cdot \vec{b} = 12 \] Find the area of the parallelogram.


                    • 6.
                      If \( \sqrt{1 - x^2} + \sqrt{1 - y^2} = a(x - y) \), then prove that \( \frac{dy}{dx} = \frac{\sqrt{1 - y^2}}{\sqrt{1 - x^2}} \).

                        CBSE CLASS XII Previous Year Papers

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