JEE Advanced 2017 Question Paper: Download Question Paper with Answer Key PDFs

JEE Advanced 2017 Question Paper with answer key PDF are available for free download. Students rated the paper moderately difficult. Physics section had a mixture of both conceptual and formula-based questions. The Chemistry section was a bit difficult compared to Math and Physics as it had mostly calculation-based questions. Inorganic Chemistry had the highest weightage.

*The article might have information for the previous academic years, which will be updated soon subject to the notification issued by the University/College.

JEE Advanced 2017 Questions

  • 1.

    Let $ y(x) $ be the solution of the differential equation $$ x^2 \frac{dy}{dx} + xy = x^2 + y^2, \quad x > \frac{1}{e}, $$ satisfying $ y(1) = 0 $. Then the value of $ 2 \cdot \frac{(y(e))^2}{y(e^2)} $ is ________.


      • 2.
        Let $ a_0, a_1, ..., a_{23} $ be real numbers such that $$ \left(1 + \frac{2}{5}x \right)^{23} = \sum_{i=0}^{23} a_i x^i $$ for every real number $ x $. Let $ a_r $ be the largest among the numbers $ a_j $ for $ 0 \leq j \leq 23 $. Then the value of $ r $ is ________.


          • 3.

            The left and right compartments of a thermally isolated container of length $L$ are separated by a thermally conducting, movable piston of area $A$. The left and right compartments are filled with $\frac{3}{2}$ and 1 moles of an ideal gas, respectively. In the left compartment the piston is attached by a spring with spring constant $k$ and natural length $\frac{2L}{5}$. In thermodynamic equilibrium, the piston is at a distance $\frac{L}{2}$ from the left and right edges of the container as shown in the figure. Under the above conditions, if the pressure in the right compartment is $P = \frac{kL}{A} \alpha$, then the value of $\alpha$ is ____


              • 4.
                The total number of real solutions of the equation $$ \theta = \tan^{-1}(2 \tan \theta) - \frac{1}{2} \sin^{-1} \left( \frac{6 \tan \theta}{9 + \tan^2 \theta} \right) $$ is
                (Here, the inverse trigonometric functions $ \sin^{-1} x $ and $ \tan^{-1} x $ assume values in $[-\frac{\pi}{2}, \frac{\pi}{2}]$ and $(-\frac{\pi}{2}, \frac{\pi}{2})$, respectively.)

                  • 1
                  • 2
                  • 3
                  • 5

                • 5.
                  Let $$ \alpha = \frac{1}{\sin 60^\circ \sin 61^\circ} + \frac{1}{\sin 62^\circ \sin 63^\circ} + \cdots + \frac{1}{\sin 118^\circ \sin 119^\circ}. $$ Then the value of $$ \left( \frac{\csc 1^\circ}{\alpha} \right)^2 $$ is \rule{1cm}{0.15mm}.

                    Fees Structure

                    Structure based on different categories

                    CategoriesState
                    General2800
                    Women1400
                    sc1400
                    pwd1400

                    Note: The application fee for foreign nationals from SAARC countries is USD 75 while for candidates who belong to Non-SAARC countries, the application fee is USD 150. Indian Nationals (including PIO/OCI) who have chosen exam centers outside India, have to pay USD 75 as the application fee.

                    In case of any inaccuracy, Notify Us! 

                    Comments


                    No Comments To Show