HCF: Definition, Process, Methods, Examples

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The highest number that divides each of the two or more numbers is the HCF or Highest Common Factor. The Greatest Common Factor (HCF) is also known as the Greatest Common Measure (GCM) or the Greatest Common Divisor (GCD). HCM and LCM are two alternative ways of finding the smallest common multiple of any two or more numbers. LCM, or Least Common Multiple, is used to discover the smallest common multiple of any two or more integers.

Key Terms: HCF, LCM, Greatest Common Factor, Greatest Common Divisor, Factors, Division, Number, Prime Number

Read More: Minors and Cofactors


Meaning of HCF

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HCF stands for Highest Common Factor in its entire form. The highest factor that may evenly divide two numbers is the HCF of two numbers. HCF can be calculated using two or more numbers. It is the biggest divisor for any two or more numbers that can divide them evenly or fully.

For instance: Since 15 is the greatest number that can divide both 60 and 75 perfectly, it is the highest common factor of 60 and 75.

Read More: Natural Numbers and Whole Numbers


HCF Process

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We can calculate the HCF of any pair of numbers using one of two methods:

  • By prime factorization method
  • By division method

Prime Factorization Method for HCF

To get the HCF of numbers using the prime factorisation method, follow the steps outlined below.

  • Step 1: Each number should be written as a product of its prime components. Prime factorization is the name given to this procedure.
  • Step 2: Make a list of the factors that both numbers have in common.
  • Step 3: The HCF is the sum of all common prime factors ( use the lower power of each common factor)

Example 1: Examine the HCF values of 60 and 75.

Solution:

Each number should be written as a product of its prime components.

22 x 3 x 5 = 60

3 x 52 = 75

The HCF is the sum of all common prime factors.

In this case, the common prime factors are 3 and 5.

The lowest power of 3 is 3 while the highest power of 5 is 5.

Hence, HCF = 3 x 5 = 15

Example 2: Calculate the HCF for 36, 24 and 12.

Solution:

Each number should be written as a product of its prime components.

22 x 32 = 36

23 x 3 = 24

22 x 3 = 12

The HCF is the sum of all common prime factors ( use the lowest power of each common factor)

In this case, the common prime factors are 2 and 3.

The lowest power of 2 is 22, whereas the highest power of 3 is 3.

Hence, HCF = 22 x 3 = 12

Example 3: Calculate the HCF for 36, 27, and 80.

Solution:

Each number should be written as a product of its prime components.

22 x 32 = 36

33 = 27

24 x 5 = 80

The HCF is the sum of all common prime factors.

In this case, there are no shared prime factors.

Hence, HCF is 1.

HCF Using Division Method

The division approach is just dividing the provided numbers at the same time to find the common factors between them. To solve HCF difficulties, follow the instructions outlined below.

  • Step 1: Separate the given numbers with commas and write them horizontally in a sequence.
  • Step 2: The smallest prime number that can divide the given integer is the smallest prime number. It should split the given numbers exactly. (Write on the left side of the page.)
  • Step 3: Write the quotients now.
  • Step 4: Repeat the procedure until there are no more co-prime numbers.
  • Step 5: Because the factors on the left-hand side split all the integers exactly, we'll get the common prime factors. The HCF of the given numbers is the product of these common prime factors.

Read More: Real Numbers

Example 1: Consider the HCFs of 30 and 75.

Example 1: Consider the HCFs of 30 and 75
Example 1: Consider the HCFs of 30 and 75

As can be seen, the prime factors indicated on the left side split all the numbers perfectly. As a result, they're all prime factors in common. For the numbers at the bottom, there is no common prime factor.

Hence, HCF = 3 × 5 = 15.

Example 2: Determine the HCF of 36 and 24.

Example 2: Determine the HCF of 36 and 24.
Example 2: Determine the HCF of 36 and 24.

HCF = 2 × 2 × 3 = 12.

Example 3: Calculate the HCF of 36, 12, 24, and 48.

Example 3: Calculate the HCF of 36, 12, 24, and 48.
Example 3: Calculate the HCF of 36, 12, 24, and 48.

HCF = 2 × 2 × 3 = 12.

Read More: Prime Numbers


Shortcut approach for HCF

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How to calculate the HCF of any pair of numbers.

  • Step 1: First, divide the larger number by the smaller number, as in Larger Number/Smaller Number.
  • Step 2: Step 1's divisor is divided by the remainder. Step 1/Remainder divisor
  • Step 3: Step 2's divisor is divided by the residual once more.
  • Step 2: Remainder divisor
  • Step 4: Repeat the process until there is no longer any residual.
  • Step 5: The HCF is the divisor of the final step.

Process To Calculate HCF Of Three Numbers

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Here’s the processes for calculating HCF of three numbers that have been presented to us:

1) Determine the HCF of two numbers.

2) Then Calculate the HCF of the third number and the HCF calculated in step 1.

3) The HCF of the three numbers will be the HCF you got in step 2.

The procedures outlined above can also be used to calculate the HCF of more than three values.


HCF of Four Numerical Values

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To get the HCF of four digits, use these simple steps:

  • To begin, divide the four digits into two groups of two.
  • Find the HCF of a two-number pair.
  • Then, using the HCF of HCFs determined in the preceding step, get the HCF of HCFs.
  • The final HCF will be the four-number HCF that is necessary.

HCF of Prime Numbers

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Any two or prime numbers' HCF is always equal to one.

Since prime numbers are those that only have two factors: 1 or the number itself. As a result, if no other factor exists, the HCF of such numbers will be 1. The following are some examples:

  • HCF (2, 3) = 1
  • HCF (3, 7) = 1
  • HCF (5, 13) = 1
  • HCF (19, 23) = 1

Read More: Area of Rectangle


Things to Remember

  • The highest number that divides each of the two or more numbers is the HCF or Highest Common Factor.
  • When two or more numbers are divided by the HCF, each number is divided without a remainder.
  • When two or more integers are added together, the HCF is always less than or equal to each of the numbers.
  • When two or more prime numbers are added together, the HCF is always 1.
  • Euclid devised a method for calculating the HCF.
  • The HCF of two or more numbers divides the supplied numbers, the HCF of prime numbers is always equal to one. 
  • The HCF of two or more numbers is always less than or equal to the given numbers.

Read More: Area of Square Using Diagonal


Sample Questions

Ques: Calculate the HCF of 30 and 45. (2 Marks)

Ans:  The HCF of 30 and 45 is 15

Hence, the HCF of 30 and 45 is 15.

Ques: Calculate the HCF of 12 and 36. (2 Marks)

Ans: HCF of 12 and 36 = 12

Hence, HCF of 12 and 36 = 12

Ques: Calculate the HCF of 9, 27, and 30. (2 Marks)

Ans: First, determine the HCF of any two numbers. Let's start by determining the HCF of 9 and 27.

HCF of 9 and 27 = 9

Hence, HCF of 9 and 27 = 9

HCF of 9 ,27, 30

= HCF of [(HCF of 9, 27) and 30

= HCF of [9 and 30]

HCF of 9, 27, 30 = 3

So, HCF of 9, 27, 30 = 3

Ques: Calculate the HCF of 5 and 7 (2 Marks)

Ans: HCF of 5 and 7 = 1

So, HCF of 5 and 7 = 1

Ques: The ratio of two given numbers is 5:11. What are the numbers for one of the HCFs that is number 7? (2 Marks)

Ans: Assuming that the numbers are 5m and 11m.

The highest common factor is "m" in this case (HCF).

5 X 7 = 35 and 11 X 7 = 77 are the numbers.

Ques: Calculate the length of the plank that can be used to measure the specified lengths of 4 m 50 cm, 9 m 90 cm, and 16 m 20 cm in the time allotted. (3 Marks)

Ans: When it comes to converting length to centimetres,

4 m 50 cm = 450 cm

9 m 90 cm = 990 cm

16 m 20 cm = 1620 cm

The highest common factor must be used to establish the length of a large plank that can be used to measure supplied length values in a short period.

450 = 2 × 3 × 3 × 5 × 5 = 2 × 32 × 52

990 = 2 × 3 × 3 × 5 × 11 = 2 × 32 × 5 × 11

1620 = 2 × 2 × 3 × 3 × 3 × 3 × 5 = 22 × 34 × 5

HCF (450, 990, 1620) = 2 × 3 × 3 × 5 = 90

Ques: Finding the biggest number after dividing 70 and 50 leaves one and four remainders. (2 Marks)

Ans: When dividing 70 and 50, the fundamental digit leaves one and four remainders.

It is possible to obtain the numbers 69 and 46.

Calculate the HCF 69 (3 23) and 46 (2 23).

Between 69 and 46, the highest common factor (HCF) is 23.

Ques: In each scenario, find the biggest integer that divides 64, 136, and 238 and leaves the same residual. (2 Marks)

Ans: The highest common factor of (136 – 64), (238 – 136) and (238 – 64), which is the HCF (72, 102, 174) must be discovered to determine the appropriate number.

72 = 23 × 32

102 = 2 × 3 × 17

174 = 2 × 3 × 29

HCF (72, 102, 174) = 2 × 3 = 6

The required number is six.

Ques: Find the maximum number of pupils to whom 182 chocolates and 247 candies may be distributed so that each student receives the same number of each. What is the total number of chocolates and candies that each student will receive? (2 Marks)

Ans: The count of pupils is determined by the HCF value of the count of chocolates and sweets that must be located.

HCF (182, 247) = 13

There are 13 pupils in total.

Chocolates counted for each pupil = 182/13 = 14

Total number of candies per student = 247/13 = 19

Read More:

CBSE X Related Questions

1.
The angle of elevation of the top of a building from the foot of the tower is 30° and the angle of elevation of the top of the tower from the foot of the building is 60°. If the tower is 50 m high, find the height of the building.

      2.
      Check whether \(6n\) can end with the digit \(0\) for any natural number \(n\).

          3.

          A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.

              4.
              Find the sums given below :
              1. \(7 + 10\frac 12+ 14 + ....... + 84\)
              2. \(34 + 32 + 30 + ....... + 10\)
              3. \(–5 + (–8) + (–11) + ....... + (–230)\)

                  5.
                  Which of the following are APs? If they form an AP, find the common difference d and write three more terms.
                  (i) 2, 4, 8, 16, . . . .
                  (ii) \(2, \frac{5}{2},3,\frac{7}{2}\), . . . .
                  (iii) – 1.2, – 3.2, – 5.2, – 7.2, . . . .
                  (iv) – 10, – 6, – 2, 2, . . .
                  (v) 3, \(3 + \sqrt{2} , 3 + 3\sqrt{2} , 3 + 3 \sqrt{2}\) . . . .
                  (vi) 0.2, 0.22, 0.222, 0.2222, . . . .
                  (vii) 0, – 4, – 8, –12, . . . .
                  (viii) \(\frac{-1}{2}, \frac{-1}{2}, \frac{-1}{2}, \frac{-1}{2}\), . . . .
                  (ix) 1, 3, 9, 27, . . . .
                  (x) a, 2a, 3a, 4a, . . . .
                  (xi) a, \(a^2, a^3, a^4,\)  . . . .
                  (xii) \(\sqrt{2}, \sqrt{8} , \sqrt{18} , \sqrt {32}\) . . . .
                  (xiii) \(\sqrt {3}, \sqrt {6}, \sqrt {9} , \sqrt {12}\) . . . . .
                  (xiv) \(1^2 , 3^2 , 5^2 , 7^2\), . . . .
                  (xv) \(1^2 , 5^2, 7^2, 7^3\), . . . .

                      6.

                      Solve the following pair of linear equations by the substitution method. 
                      (i) x + y = 14 
                          x – y = 4   

                      (ii) s – t = 3 
                          \(\frac{s}{3} + \frac{t}{2}\) =6 

                      (iii) 3x – y = 3 
                            9x – 3y = 9

                      (iv) 0.2x + 0.3y = 1.3 
                           0.4x + 0.5y = 2.3 

                      (v)\(\sqrt2x\) + \(\sqrt3y\)=0
                          \(\sqrt3x\) - \(\sqrt8y\) = 0

                      (vi) \(\frac{3x}{2} - \frac{5y}{3}\) =-2,
                          \(\frac{ x}{3} + \frac{y}{2}\) = \(\frac{ 13}{6}\)

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