Graphs of Inverse Trigonometric Functions: Introduction, Explanation of all topics

Collegedunia Team logo

Collegedunia Team

Content Curator

In this article, we have covered various topics for Graphs of Inverse Trigonometric Functions. You can learn about Trigonometric and Inverse Trigonometric Functions which are discussed in the following article. There are various Properties and Formulas of Inverse Trigonometric functions which are discussed in the article.

Read Also: Inverse Trigonometric Functions

Key Terms: Inverse Trigonometric Functions, Sine curves, Arcus functions, Trigonometric functions, Amplitude, Electronic device, Oscilloscope, Inverse function


Trigonometric Functions

[Click Here for Sample Questions]

Trigonometric functions are used to find the measurements like heights of mountains and tall buildings without using measurement tools. Similarly, their inverse functions are widely used in Engineering and other sciences including Physics. For example, an oscilloscope is an electronic device that converts electrical signals into graphs like that of sine function. By manipulating the controls, we can change the amplitude, the period and phase shift of sine curves.

Also Read:


Inverse Trigonometric functions

[Click Here for Sample Questions]

If f(x) is a function then the f(x)-1 is the inverse function. The Trigonometric functions are sin, cos, tan, cot, sec and cosec. Just like the mathematical operations addition and subtraction, the inverse of each other is also similar.

x=sin θ

θ-1= sin-1x (Inverse function)

So, a power of -1 is added to the inverse functions. These inverse trigonometric functions are also called as Arcus functions or cyclometric functions or anti-trigonometric functions. These functions can be represented in the form of graphs.


Properties of Inverse Trigonometric functions

[Click Here for Sample Questions]

Following are the Properties of Inverse Trigonometric functions:

Inverse sine function Inverse cosine function Inverse Tangent function Inverse Cosecant function Inverse secant function Inverse Cot function
Domain: [-1,1] Domain: [-1,1] Domain: R Domain: (-∞,-1] U [1,∞) Domain: (-∞,-1] U [1,∞) Domain: R
Range: [-π/2, π/2] Range: [0,π] Range: [-π/2, π/2] Range: [-π/2, π/2]-{0} Range: [0, π]-{π/2} Range: (0, π)

Formulas of Inverse Trigonometric Functions

[Click Here for Sample Questions]

With respect to the domain and range of the Trigonometric functions, there are some important formulas:

  • sin(sin-1x) = x if -1≤ x ≤1 and sin(sin-1y)=y if -π/2 ≤ y ≤ π/2.
  • cos(cos-1x)=x if -1≤ x ≤1 and cos(cos-1y)=y if 0 ≤ y(arc cos) ≤ π.
  • tan(tan-1x)=x if -∞ < x < ∞ and tan(tan-1y)=y if -π/2 ≤ y(arc tan) ≤ π/2.
  • cot(cot-1x)=x if -∞ < x < ∞ and cot(cot-1x)=y if 0
  • sec(sec-1x)=x if -∞≤x≤-1 or 1≤x≤∞ and sec(sec-1y)=y if 0≤y≤π, y≠π/2.
  • cosec(cosec-1x)=x if -∞≤x≤-1 or 1≤x≤∞ and cosec(cosec-1y)=y if -π/2 ≤ y ≤ π/2, y≠0.

Also Read:


Graphs of Inverse Trigonometric Functions

[Click Here for Sample Questions]

At different angles every trigonometric function has a value ranging from -∞ to ∞. Based on the values graphs are drawn for the Trigonometric functions. The graphs vary from function to function and are as follows:

  • Arc sine Function: The sine function is not one to one function in the domain -π/2 ≤ y ≤ π/2. But it changes to be a one to one function in the domain [-π/2, π/2]. When the several points of intersection are joined the graph is in the form of a curve with crests and troughs.
Arc sine Function
Arc sine Function
  • Arc cosine Function: The cosine function is not one to one function. But it changes to be a one-to-one function in the domain [0,π]. When the several values at different angles are joined, the graph obtained is attached.
Arc cosine Function:
Arc cos Function
  • Arc tan function: The tangent function is obtained as a one to one function at the domain [-π/2,π/2]. When the several values at different angles are joined, the graph obtained is attached.
Arc tan function
Arc tan function
  • Arc cot function: The cotangent trigonometric function is the reverse of tangent function. When the several values at different angles are joined, the graph obtained is as attached.
Arc cot function
Arc cot function
  • Arc cosec function: The graph drawn for arc cosec function is different. There is no continuous line or intersection. Two types of line are available in two different quadrants.
Arc cosec function
Arc cosec function
  • Arc sec function: A curve is obtained on the outside portion between -1 and 1 for the inverse secant function. The graph is as follows.
Arc sec function
Arc sec function

Things to Remember

[Click Here for Sample Questions]

Following are some points which should be cleared by the readers:

  • If f(x) is a function then the f(x)-1 is the inverse function. The Trigonometric functions are sin, cos, tan, cot, sec and cosec.
Inverse sine function Inverse cosine function Inverse Tangent function Inverse Cosecant function Inverse secant function Inverse Cot function
Domain: [-1,1] Domain: [-1,1] Domain: R Domain: (-∞,-1] U [1,∞) Domain: (-∞,-1] U [1,∞) Domain: R
Range: [-π/2, π/2] Range: [0,π] Range: [-π/2, π/2] Range: [-π/2, π/2]-{0} Range: [0, π]-{π/2} Range: (0, π)
  • sin(sin-1x) = x if -1≤ x ≤1 and sin(sin-1y)=y if -π/2 ≤ y ≤ π/2.
  • cos(cos-1x)=x if -1≤ x ≤1 and cos(cos-1y)=y if 0 ≤ y(arc cos) ≤ π.
  • tan(tan-1x)=x if -∞ < x < ∞ and tan(tan-1y)=y if -π/2 ≤ y(arc tan) ≤ π/2.
  • cot(cot-1x)=x if -∞ < x < ∞ and cot(cot-1x)=y if 0
  • sec(sec-1x)=x if -∞≤x≤-1 or 1≤x≤∞ and sec(sec-1y)=y if 0≤y≤π, y≠π/2.
  • cosec(cosec-1x)=x if -∞≤x≤-1 or 1≤x≤∞ and cosec(cosec-1y)=y if -π/2 ≤ y ≤ π/2, y≠0.

Read Also: Trigonometry Important Formulas


Sample Questions

Ques: Find the principal value of the given equation: y = sin-1(1/√2). [1 Mark]

Ans: Given

y = sin-1(1/√2)

sin(y) = (1/√2)

The range of the principal value branch of sin-1(x) is (−π/2, π/2) and sin(π/4) = 1/√2.

Ques: Find the principal value of the given equation: y = cos-1(1). [1 Mark]

Ans: Given

y = cos-1(1)

cos(y) = 1

We know that the range of the principal value branch of cos-1(x) is (0, π) and cos(0) = 1.

So, the principal value of cos-1(1) = 0.

Ques: Find the principal value of the given equation: y = cosec-1(1). [1 Mark]

Ans: Given

y = cosec-1(√2)

cosec(y) = 1

The range of the principal value branch of cosec-1(x) is [-π/2, π/2] – {0} and cosec(π/2) = 1.

So, the principal value of cosec-1(1) = π/2.

Ques: Find the value of cos(sin-1 0.5). [2 Marks]

Ans: The value of the portion in brackets is an angle.

Noting the range for inverse sine function, we get

sin-1(0.5)=π/6

Hence cos(sin-1(0.5))=cos(π/6)=0.8660.

Ques: Find sin−1(sin5π/4). [2 Marks]

Ans: Since 5π/4>π/2

We know that sin5π/4=−1/√2

Thus, sin−1(sin5π/4)=sin−1(−1/√2)

−π/2≤y≤π/2 and siny=−1/√2

That angle is y=−π/4 , since

sin(−π/4) = −sin(π/4) = −1/√2

Thus, sin−1(sin5π/4)=−π/4

Ques: Find the principal value of the given equation: y = sec-1(1). [2 Marks]

Ans: Given

y = sec-1(1)

sec(y) = 1

Range of the principal value branch of sec-1(x) is [0, π] – {π/2}

sec(0) = 1.

So, the principal value of sec-1(1) = 0.

Ques: Evaluate cos(tan-1(-1)). [1 Mark]

Ans: tan-1(-1)=-π/4

cos(-π/4)=1/2 × √2

Ques: Find the value of y = sec-1(√2). [2 Marks]

Ans: Given

y = sec-1(√2)

sec(y) = (√2)

The range of the principal value branch of sec-1(x) is [0, π] – {π/2} and sec(π/4) = √2.

So, the principal value of sec-1(√2) = π/4.

For Latest Updates on Upcoming Board Exams, Click Here: https://t.me/class_10_12_board_updates


Check-Out: 

CBSE CLASS XII Related Questions

1.

If A=\(\begin{bmatrix}2&-1&1\\-1&2&-1\\1&-1&2\end{bmatrix}\)verify that A3-6A2+9A-4 I=0 and hence find A-1 

      2.

       If \(\frac{d}{dx}f(x) = 4x^3-\frac{3}{x^4}\) such that \(f(2)=0\), then \(f(x)\) is

        • \(x^4+\frac{1}{x^3}-\frac{129}{8}\)

        • \(x^3+\frac{1}{x^4}+\frac{129}{8}\)

        • \(x^4+\frac{1}{x^3}+\frac{129}{8}\)

        • \(x^3+\frac{1}{x^4}-\frac{129}{8}\)

        3.
        By using the properties of definite integrals, evaluate the integral: \(∫_0^π log(1+cosx)dx\)

            4.
            Find the vector and the cartesian equations of the lines that pass through the origin and(5,-2,3).

                5.
                Find the inverse of each of the matrices,if it exists \(\begin{bmatrix} 2 & 1 \\ 7 & 4  \end{bmatrix}\)

                    6.
                    Let f: R→R be defined as f(x) = 3x. Choose the correct answer.

                      • f is one-one onto
                      • f is many-one onto
                      • f is one-one but not onto
                      • f is neither one-one nor onto
                      CBSE CLASS XII Previous Year Papers

                      Comments



                      No Comments To Show