| Updated On - Nov 4, 2024
CUET Physics Question Paper 2024 (Set D) is available here. NTA conducted CUET 2024 Physics paper on 16 May in Shift 2A from 3 PM to 4 PM. CUET Physics Question Paper 2024 is based on objective-type questions (MCQs). Candidates get 60 minutes to solve 40 MCQs out of 50 in CUET 2024 question paper for Physics.
CUET Physics Question Paper 2024 (Set D) PDF Download
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CUET Questions
1. The cost of a machinery is ₹8,00,000. Its scrap value will be one-tenth of its original cost in 15 years. Using the linear method of depreciation, the book value of the machine at the end of the 10th year will be:
- ₹4,80,000
- ₹3,20,000
- ₹3,68,000
- ₹4,32,000
2. David can row a boat in still water at the rate of 5 km/hr. He rowed in a river downstream to meet his friend. After returning back, he observed that the duration of the upstream journey was three times that of the downstream journey. The speed of the stream was:
- 2 km/hr
- 2.5 km/hr
- 3 km/hr
- 3.5 km/hr
3. Formaldehyde undergoes Cannizzaro reaction because
(A) It has alpha-hydrogen atom.
(B) It does not have alpha-hydrogen atom.
(C) It does not undergo self-oxidation and reduction on heating with concentrated alkali.
(D) It undergoes self-oxidation and reduction on heating with concentrated alkali.
(A) It has alpha-hydrogen atom.
(B) It does not have alpha-hydrogen atom.
(C) It does not undergo self-oxidation and reduction on heating with concentrated alkali.
(D) It undergoes self-oxidation and reduction on heating with concentrated alkali.
- (A) It has alpha-hydrogen atom
- (B) It does not have alpha-hydrogen atom
- (C) It does not undergo self-oxidation and reduction on heating with concentrated alkali
- (D) It undergoes self-oxidation and reduction on heating with concentrated alkali
4. The correct solution of \(-22 < 8x - 6 \leq 26\) is the interval:
- \([-2, 4]\)
- \((-2, 4]\)
- \((-2, 4)\)
- \([-2, 4)\)
5. If \( y = e^{{2}\log_e t} \) and \( x = \log_3(e^{t^2}) \), then \( \frac{dy}{dx} \) is equal to:
If \( y = e^{{2}\log_e t} \) and \( x = \log_3(e^{t^2}) \), then \( \frac{dy}{dx} \) is equal to:
- \( \frac{1}{4t\sqrt{t}} \)
- \({2t^2} \)
- \( \frac{\log_e 3}{4t\sqrt{t}} \)
- \( \frac{2t^2}{e^{\frac{1}{2}\log_e t}} \)
6. If \( A = \begin{bmatrix} 5 & 1 \\ -2 & 0 \end{bmatrix} \) and \( B^T = \begin{bmatrix} 1 & 10 \\ -2 & -1 \end{bmatrix} \), then the matrix \( AB \) is:
- \( \begin{bmatrix} 1 & 10 \\ -1 & 0 \end{bmatrix} \)
- \( \begin{bmatrix} 15 & -11 \\ -2 & 4 \end{bmatrix} \)
- \( \begin{bmatrix} 3 & 49 \\ -2 & -20 \end{bmatrix} \)
- \( \begin{bmatrix} 1 & 9 \\ -2 & -20 \end{bmatrix} \)
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