Secant Function: Meaning, Properties, Graph

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Secant function is the reciprocal of the cosine function in general. Other than the secant function, there are other similar reciprocal functions in the mathematical domain of Inverse Trigonometric Functions. For instance, cotangent is considered the reciprocal function of the tangent function, while cosecant is the reciprocal of sine, as per their trigonometric values.

Key Takeaways: Secant function, secθ, reciprocal, Trigonometry, domain, range, tangent function, trigonometric functions, trigonometric values, coordinate plane


Meaning of Secant Function

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The secant function is the reciprocal of cosine. A reciprocal function is often defined as the reciprocal or otherwise known as the multiplicative inverse of another function. Now, when considering that −1 ≤ cos x ≤ 1, it is clear that y = sec x does not involve values which are in (−1, 1). In reference to a coordinate plane, it can be said that the secant function is considered as r/x.

In a nutshell, secant function has a range of (−∞,1] ∪[1, ∞). As per the function, y = sec, which is x = 1/cosx. Commonly, the function is defined for every value of x, with an exclusion of when cos x = 0. By and large, this means that y = sec x has a domain of . R\ {(2n + 1) \(\frac{\pi}{2}\) : n ∈ Z}

The secant function is an even function. Typically, it has been found that the secant function neither has a maximum or a minimum value limit. It is because the secant function is periodic, with a period value of 2π. The secant function or sec function, in a right-angled triangle, can otherwise also be described as the ratio of the length of the hypotenuse to the length of the base.

The secant function (commonly abbreviated to sec) is often also defined as the distance one point to another (O and M in the image illustrated below). By establishing the relation between sec (θ) and cos (θ), it can be said that, sec (θ) = r/x = 1/cos (θ)

It is important to highlight that,

Secant function sec(θ) is defined as:

Sec(θ) = r/x = 1/Cos(θ)

Also Note that,

  1. sec(θ + 2π) = \(\frac{1}{cos (\theta + 2 \pi)} = \frac{1}{cos (\theta)}\)= sec(θ)

and therefore sec(θ) is a periodic function whose period is equal to 2π.

Secant Function

Secant Function

Also Read: Direction Cosines


Properties of Secant Function

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As much as other trigonometric functions, the secant function can be depicted in the form of a line segment that is associated with the unit circle. If expressed in reference to cosine, it can be said that sec (θ) = 1/ cos (θ). The degree and value of the secant function is illustrated below.

Properties of Secant Function

Properties of Secant Function

The properties of the secant function can only be determined by the quadrant it typically lies in. The quadrant can be illustrated as,

Properties of Secant Function

Properties of Secant Function

Here are the properties of the Secant function:

  • Sec x has a period value which is typically equal to 2π. A periodic function can be defined as a function that consequently results as a function that is equal to the original one, during its meet with a particular horizontal shift, say – much like f (x+P)=f(x).
  • Sec x has been found to have vertical asymptotes at every value associated to x = π/2 + nπ, wherein n is an integer of any class.
  • The secant function has a range of (−∞,1] ∪[1, ∞).
  • Usually, the domain of the secant function is found to be the set of every real number, with an exclusion of x = π/2 + nπ, wherein n is an integer of any class.
  • The secant function is usually considered as an even function because sec(x)=sec(−x).

Also Read: Trigonometry Ratio Identity


Graph of Secant Function

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Cosine is often depicted by the x coordinate geometry of the point P (which is the point where the terminal side of an angle θ is found bisecting the circle’s circumference), we can deduce that, Sec (θ) = 1/x.

Now, the graph of the secant function in 0 ≤ x ≤ 2 π, wherein x ≠ π/2, 3π/2, can plotted as,

Graph of Secant Function

Graph of Secant Function

If you notice in the image above, the first and fourth quadrants (interval of – π/2 < x < π/2), y = sec x are found to consider positive values alone. Quite naturally, it considers the negative values only in the second and third quadrants, also otherwise denoted by the interval of π/2 < x < 3π / 2.

The image below represents a unit circle that has a centre O, alongside a point P. It makes an angle of OP.

Graph of Secant Function

Graph of Secant Function

As we already know, sec x = 1/cos x. It can be noted that, Sec x = OP/OQ = 1/OQ.

When x varies, the value of sec x is typically also seen to change with the following variation of length, OQ. The derivation of sec x becomes feasible when determining 1/y, for every value of y on the curve made of y = cosx. Plotting the graph, we get,

Graph of Secant Function

Graph of Secant Function

Also Read:


Things to Remember

Following are some important points:

  • The secant function is basically the reciprocal of cosine.
  • The absolute value of cosine of a typical angle can never really surpass one, which also means that the reciprocal of it will never be less than one as well.
  • Sec x has a period value typically equal to 2π.
  • The relation between sec (θ) and cos (θ) can be represented by sec (θ) = r/x = 1/cos (θ)

Also Read: Sin 180 Degrees Value and Derivation


Sample Questions

Ques: Determine the value of Sec 780o. (3 Marks)

Ans: We can determine the value of sec 780° by,
Sec θ = 1 / cos θ (now, by replacing the function with the values of the equation, it can be said that,
=> sec 780° = 1 / cos 780°
=> cos 780° = cos (60° + 2(360°)) = cos 60°

As secθ = 1/cosθ

=> sec 780° = 1/cos 780°

=> cos 780° = cos (60° + 2(360°)) = cos 60°

=> sec (780°) = 1/(cos 60°) = 1/(½) = 2

=> 2

Thus, the value of Sec 780° is 2.

Ques: Determine the value of Sec X, considering Cos x = 3⁄8. (3 Marks)

Ans:

Determine the value of Sec X, considering Cos x = 3⁄8

The value of sec x can be determined since we already know its function value, which is, sec x = 1/ cos x.

Now by substituting the values on each side, we get,

= â / 8
= 8/3
Therefore, the value of Sec x = 8/3

Ques: Find out the principal value of cos–1√3/2. (3 Marks)

Ans: Let’s consider the value of y = cos 1√3/2
Now, when substituting the values, we will get,
= cos y = √3/2
Thus, it can be said that, cos y = cos л/6 (the following has been considered since cos л/6 = √3/2)
Therefore, it can be determined that y = л/6
Hence, the range of cos-1 typically is [0, л]
Thus, it can be said that the principal value of cos–1√3/2 is y = л/6.

Ques: What is the value of cos (−660°)? (3 Marks)

Ans: As per the equation, we can consider the function formula. After taking the formula, it can be said,
- 660° = - 720° + 60°
Which is, - 660° = 60°

=> cos (-660°) = cos(60°)

=> ½
Since that value of cos 60 degree is ½, therefore the value of cos (- 660°) is ½.

Ques: Determine the value of x for Shreya in the given right angled triangle, â³MNO. The following value is given as sec θ=0.6. By the data given, what is the final value of x? (3 Marks)
Determine the value of x for Shreya in the given right angled triangle, â³MNO. The following value is given as sec θ=0.6. By the data given, what is the final value of x?

Ans: Shreya has been given the following data alongside the image,

Sec θ = 0.6

Now, in reference to the following formula the answer can be determined,

Sec θ = Hypotenuse / Base

Now, by replacing the functions with the real values, we get,

0.6 = Hypotenuse / Base

= 0.6 = x/5

= x = 3

The value of x in the given image is 3.

Ques: Prove the following value: sin-1 (2x√(1-x2)) = 2 sin-1x, -1/√2 ≤ x ≤ 1/√2. (3 Marks)

Ans: Consider that x = sin θ. Now, it is known that sin-1 x = θ. Thus, we can say,

=> sin-1 (2x√(1-x2)) = sin-1 (2 sinθ√(1- sin2x))

=> sin-1 (2 sinθ cosθ)

=> sin-1 (sin 2θ)

=> 2θ

=> 2 sin-1x
Thus, the value is proved.

Ques: Determine the principal value of cos -1 (- 1/√2). (3 Marks)

Ans: We can determine the value of cos−1(−1/√2) by,

=> cos−1(−1/√2)

=> cos−1(-cos π/4)

As we know, cos (π - θ) = - cosθ

Now,

=> cos-1 (cos (π - π/4))

=> π - π/4

=>3π/4

Thus, the principal value of cos−1(−1/√2) is 3π/4.

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