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Content Writer | Updated On - Sep 2, 2024
JEE Main 2018 Question Papers with Solutions are available for both Paper 1 and Paper 2. The previous years’ question papers pdf can also be downloaded from he article below. Candidates appearing for JEE Main can use the links below to download the question papers with solution for free to prepare better for the exam.
JEE Main 2018 Question Papers with Solution- Download PDFs
JEE Main Question Papers | Date | Shift/Slot | Question Paper with Solution |
---|---|---|---|
B.E./B.Tech | April 8, 2018 | Code A | Check Here |
B.E./B.Tech | April 8, 2018 | Code B | Check Here |
B.E./B.Tech | April 8, 2018 | Code C | Check Here |
B.E./B.Tech | April 8, 2018 | Code D | Check Here |
B.E./B.Tech | April 15, 2018 | Shift 1 | Check Here |
B.E./B.Tech | April 15, 2018 | Shift 2 | Check Here |
B.E./B.Tech | April 16, 2018 | Shift 1 | Check Here |
JEE Main 2018 Questions
1. An electric field \( \vec{E} = (2x \hat{i}) \, \text{N C}^{-1} \) exists in space. A cube of side \( 2 \, \text{m} \) is placed in the space as per the figure given below. The electric flux through the cube is __________ \( \text{N m}^2/\text{C} \).
2. The effective resistance between A and B, if resistance of each resistor is R, will be
- \( \frac{2R}{3} \)
- \( \frac{8R}{3} \)
- \( \frac{5R}{3} \)
- \( \frac{4R}{3} \)
3. A capacitor of reactance \( 4 \sqrt{3} \, \Omega \) and a resistor of resistance \( 4 \, \Omega \) are connected in series with an AC source of peak value \( 8 \sqrt{2} \, \text{V} \). The power dissipation in the circuit is ___________ W.
4. A particle of mass \( 0.50 \, \text{kg} \) executes simple harmonic motion under force \( F = -50 \, (\text{N m}^{-1}) x \). The time period of oscillation is \( \frac{x}{35} \, \text{s} \). The value of \( x \) is \( \dots \dots \dots \dots \). \[ \text{(Given } \pi = \frac{22}{7} \text{)} \]
5. A satellite of \( 10^3 \, \text{kg} \) mass is revolving in a circular orbit of radius \( 2R \). If \[ \frac{10^4 R}{6} \, \text{J} \] energy is supplied to the satellite, it would revolve in a new circular orbit of radius: \[ \text{(use } g = 10 \, \text{m/s}^2, \, R = \text{radius of earth)}. \]
- 2.5 R
- 3 R
- 4 R
- 6 R
*The article might have information for the previous academic years, which will be updated soon subject to the notification issued by the University/College.
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