NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.3

Jasmine Grover Content Strategy Manager

Content Strategy Manager

NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.3 is covered in this article with a detailed explanation. Chapter 10 Vector Algebra Exercise 10.1 covers basic concepts of the product of two vectors, multiplication of vector by a scalar, and projection of a vector on a line.

Download PDF: NCERT Solutions for Class 12 Maths Chapter 10 Exercise 10.3

Check out the solutions of Class 12 Maths NCERT solutions chapter 10 Vector Algebra Exercise 10.3

Check out other exercise solutions of Class 12 Maths Chapter 10 Vector Algebra

Class 12 Chapter 10 Vector Algebra Topics:

Properties of scalar product of two vectors	Laws of Vector Addition	Vector Formula
Magnitude of a vector	Vector Projection Formula	Scalar triple product of vectors
Direction of a vector	Adjacency Matrix	Components of vector
Vector Space	Cross product	Vector Calculus

CBSE Class 12 Mathematics Study Guides:

NCERT Solutions for Class 12 Maths	Math Formula	Difference between in Maths
Math MCQs	Math Study Notes	Calculus
Mensuration	Arithmetic	Trigonometry

CBSE CLASS XII Related Questions

1.
Find the value of λ, if the points A(−1,−1,2), B(2,8,λ), C(3,11,6) are collinear.

View Solution

2.
Find: \[ I = \int (\sqrt{\tan x} + \sqrt{\cot x}) dx. \]

View Solution

3.
If \( \sqrt{1 - x^2} + \sqrt{1 - y^2} = a(x - y) \), then prove that \( \frac{dy}{dx} = \frac{\sqrt{1 - y^2}}{\sqrt{1 - x^2}} \).

View Solution

4.
Find the general solution of the differential equation \[ x^2 \frac{dy}{dx} = x^2 + xy + y^2 \] OR

View Solution

5.
The probability that a student buys a colouring book is 0.7, and a box of colours is 0.2. The probability that she buys a colouring book, given that she buys a box of colours, is 0.3. Find:
(i) The probability that she buys both the colouring book and the box of colours.
(ii) The probability that she buys a box of colours given she buys the colouring book.

View Solution

6.
An amount of ₹ 10,000 is put into three investments at the rate of 10%, 12% and 15% per annum. The combined annual income of all three investments is ₹ 1,310, however, the combined annual income of the first and second investments is ₹ 190 short of the income from the third. Use matrix method and find the investment amount in each at the beginning of the year.

View Solution

NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.3

CBSE CLASS XII Related Questions

1.
Find the value of λ, if the points A(−1,−1,2), B(2,8,λ), C(3,11,6) are collinear.

2.
Find: \[ I = \int (\sqrt{\tan x} + \sqrt{\cot x}) dx. \]

3.
If \( \sqrt{1 - x^2} + \sqrt{1 - y^2} = a(x - y) \), then prove that \( \frac{dy}{dx} = \frac{\sqrt{1 - y^2}}{\sqrt{1 - x^2}} \).

4.
Find the general solution of the differential equation \[ x^2 \frac{dy}{dx} = x^2 + xy + y^2 \] OR

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.3

CBSE CLASS XII Related Questions

1.Find the value of λ, if the points A(−1,−1,2), B(2,8,λ), C(3,11,6) are collinear.

2.Find: \[ I = \int (\sqrt{\tan x} + \sqrt{\cot x}) dx. \]

3. If \( \sqrt{1 - x^2} + \sqrt{1 - y^2} = a(x - y) \), then prove that \( \frac{dy}{dx} = \frac{\sqrt{1 - y^2}}{\sqrt{1 - x^2}} \).

4.Find the general solution of the differential equation \[ x^2 \frac{dy}{dx} = x^2 + xy + y^2 \] OR

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Find the value of λ, if the points A(−1,−1,2), B(2,8,λ), C(3,11,6) are collinear.

2.
Find: \[ I = \int (\sqrt{\tan x} + \sqrt{\cot x}) dx. \]

3.
If \( \sqrt{1 - x^2} + \sqrt{1 - y^2} = a(x - y) \), then prove that \( \frac{dy}{dx} = \frac{\sqrt{1 - y^2}}{\sqrt{1 - x^2}} \).

4.
Find the general solution of the differential equation \[ x^2 \frac{dy}{dx} = x^2 + xy + y^2 \] OR