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CUET PG B.Ed. Mathematics Question Paper 2024 will be available here for download. NTA conducted CUET PG B.Ed. Mathematics paper 2024 on from March 27 in Shift 3. CUET PG Question Paper 2024 is based on objective-type questions (MCQs). According to latest exam pattern, candidates get 105 minutes to solve 75 MCQs in CUET PG 2024 B.Ed. Mathematics question paper.
CUET PG B.Ed. Mathematics Question Paper 2024 PDF Download
CUET PG B.Ed. Mathematics Question Paper 2024 PDF | CUET PG B.Ed. Mathematics Answer Key 2024 PDF |
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CUET PG Previous Year Question Paper
CUET PG Questions
2. Out of the following options, select the word that is correctly spelt:
Out of the following options, select the word that is correctly spelt:
- COMRADERIE
- CAMARADERIE
- CAMEREDERIE
- CAMAREDERIE
3. In what time will a 640 m long train cross an electric pole if its speed is 96 km/h?
In what time will a 640 m long train cross an electric pole if its speed is 96 km/h?
- 24 sec
- 54 sec
- 5.4 sec
- 12.5 sec
4. Let f : Z→ \(Z_2\), be a homomorphism of groups defined by
\(f(a) = \begin{cases} 0, & \quad \text{if } a \text{ is even}\\ 1, & \quad \text{if } a \text{ is odd} \end{cases}\)then Kerf is :
Let f : Z→ \(Z_2\), be a homomorphism of groups defined by
\(f(a) = \begin{cases} 0, & \quad \text{if } a \text{ is even}\\ 1, & \quad \text{if } a \text{ is odd} \end{cases}\)
\(f(a) = \begin{cases} 0, & \quad \text{if } a \text{ is even}\\ 1, & \quad \text{if } a \text{ is odd} \end{cases}\)
then Kerf is :
- The set of all odd integers
- The set of all even integers
- The set of all natural numbers
- The set of all real numbers
5. If the curl of vector \(\vec{A} = (2xy-3yz)\hat{i} +(x^2+axz −4z^2)\hat{j}-(3xy+byz)\hat{k}\) is zero, then a + b is equal to :
If the curl of vector \(\vec{A} = (2xy-3yz)\hat{i} +(x^2+axz −4z^2)\hat{j}-(3xy+byz)\hat{k}\) is zero, then a + b is equal to :
- 8
- -3
- 5
- 11
6. If \(\overrightarrow F=2z\hat{i}-x\hat{j}+y\hat{k}\) and Vis the region bounded by the surface x=0,y=0,x=2,y=4,z=x2,z=2, then value of \(\iiint\limits_V\overrightarrow FdV\)is
If \(\overrightarrow F=2z\hat{i}-x\hat{j}+y\hat{k}\) and Vis the region bounded by the surface x=0,y=0,x=2,y=4,z=x2,z=2, then value of \(\iiint\limits_V\overrightarrow FdV\)is
- \(\frac{32}{15}(3\hat{j}+5\hat{k})\)
- \(\frac{32}{15}(3\hat{i}+5\hat{k})\)
- \(\frac{32}{15}(5\hat{i}+3\hat{k})\)
- \(\frac{32}{15}(3\hat{i}+5\hat{j})\)
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