Specific Heat Capacity of Water: Formula, Unit & Important Questions

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Specific Heat Capacity of Water is approximately 4.2 J/g°C. Thus, it takes 4.2 joules of energy to raise 1 gram of water by 1 degree Celsius. Specific Heat Capacity is the heat required to raise temperature of the unit mass of a given substance by a given amount. Units of specific heat are calories or joules per gram per Celsius degree. For example, the specific heat of water is 1 calorie (or 4.186 joules) per gram per Celsius degree.

Also Read: Kinetic Theory

Key Terms: Specific Heat Capacity, Specific Heat, Heat Capacity, Heat Capacity of Water, Specific Heat Capacity Formula, Specific Heat Table, Heat Energy


Specific Heat of Water

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Specific Heat Capacity of Water at normal temperature and pressure is roughly 4.2 J/goC. This means that 1 gram of water requires 4.2 joules of energy to raise 1 degree Celsius. This ‘c’ value is fairly high. This is known as the specific heat of liquid water(1 cal/g.deg) or the specific heat capacity of liquid water.

Specific Heat of Water, c = 4.186J/goC

The Specific Heat of Water is relatively higher when compared to other common substances. As a result, water plays a critical role in regulating temperature.

Calorie = 4.184 joules
1 joule = 1 kilogram(m)2(s)-2 
= 0.239005736 Calorie

Specific Heat of Water

Specific Heat of Water

The following are some interesting properties of specific heat capacity:

  • Water has a higher specific heat capacity than sand. Hence, it stays cool longer.
  • Water vapour has a higher specific heat capacity than most other materials at normal temperatures.
  • At normal temperature and pressure, water vapour has a specific heat capacity (C) of about 1.9 J/g°C. 

Specific Heat Capacity of Water Explanation

  • The hydrogen bonding between water can be used to explain why water has such high specific heat.
  • The molecules must vibrate in order to raise the temperature of the water due to the numerous connected hydrogen bonds.
  • The presence of so many hydrogen bonds requires a greater amount of energy to break the water molecules through vibration.
  • Similarly, it takes some time for hot water to cool down. Temperature drops as heat is released, and the water molecules slow down their vibrational activity.
  • The heat emitted compensates for the cooling effect of heat loss from the liquid water

What is Specific Heat?

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The amount of heat energy needed to change the heat content of 1g of a substance by 1 0C is termed the specific heat. The direction of heat flow is always from the hotter substance to the colder substance and this exchange occurs till both substances attain equal temperature. Thus by the law of conservation of energy, the heat lost by the initially hot substance should be equal to the initially cold substance. 

Specific Heat of Different Substances

Specific Heat of Different Substances

Every substance has a different mass, and hence if the same amount of heat energy is applied to different substances, the temperature gain thus varies. This variation is due to the heat capacities of the substances. 

Also Read:


What is Specific Heat Capacity?

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Heat Capacity of a substance is the total amount of heat required to raise the temperature of a mass of a substance by 1°C. Let us understand this with an easy example.

  • Consider two similar substances kept close to one another. Initially, both these substances are at different temperatures.
  • When brought in contact, heat energy flows from hotter to colder substances.
  • Thus, by the law of conservation of energy, the colder substance temperature gradually increases.

Specific Heat Capacity Video Explanation

When the mass of the given substance is unity, we call it the specific heat capacity of the substance that is the total energy required to raise the temperature of unit mass of a substance by 1°C. Specific Heat Capacity is measured in cal g-1(°C)-1 or J kg-1 K-1.

Features of Heat Capacity of a Substance

  • Two materials having different temperatures when brought in contact, heat transfers from the warmer to the colder body until equilibrium.
  • Heat obtained by the initially cooler material must be equal to the heat lost, according to the Law of Conservation of Energy.
  • When a substance absorbs heat energy, the temperature of the substance rises.
  • When the same amount of heat is applied to equal masses of different substances, the temperature rise is observed to be different for each substance.
  • When the mass of a substance is 1 kg and the temperature by which it is raised is 1K, the heat capacity of the substance is called specific heat capacity or specific heat.
  • Energy can be converted from one form to another(for instance, a blender converts electrical energy into mechanical energy). However, it cannot be created or destroyed, rather, it must be conserved

 Also Check: Thermal Expansion


Specific Heat Capacity Formula

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The following formula can be used to calculate specific heat capacity values:

Q = cmΔT

c = Q/(mΔT)

Where,

  • c = specific heat
  • = required heat
  • m = mass in millimeters
  • ΔT = Temperature change of a system

Note: When a phase change occurs, this equation does not apply because the heat added or withdrawn during the phase change has no effect on the temperature.


Specific Heat Capacity Unit

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Specific heat capacity is the quantity of heat required to raise the temperature per unit mass. 

The formula for Specific Heat Capacity = \(\frac{Energy Required(Q)}{mass(m)\times \Delta T}\)

The S.I unit for Specific Heat Capacity is JKg-1K-1, whereas, the SI unit for heat capacity is J.K-1.

Specific Heat and Temperature

Specific Heat and Temperature

Example: To one kilogram of water, 4190 J thermal energy is added so that its temperature increases by one degree Kelvin. What is the specific heat capacity of water?

Solution: The specific heat capacity is the amount of heat energy required to raise the temperature of a system with a mass of m by \(\Delta T\) so applying its formula we get:

\(C = \frac{Q}{m \Delta T}\)

\(=\frac{4190 J}{(1 kg)(1K)}\)

= 4190 J/kg.K


Specific Heat Table

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The specific heat capacities of some important substances at atmospheric pressure are listed in a tabular form below:

Materials Specific Heat Capacity (J/kg K)
Water 4186
Ice 2090
Steam 2010
Aluminium 900
iron 448
Glass 837
Copper 387
Mercury 138
Gold 1

Also Check: Kinetic Energy


Things to Remember

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  • The amount of heat that is required to raise the temperature of a gram of a substance by 1 degree Celsius is known as specific heat capacity.
  • The formula of Specific Heat Capacity: c=Q/(mΔT)
  • The unit of Specific heat capacity is: JK-1.
  • Water has a specific heat of c = 4.186J/goC.
  • Water absorbs heat but without a sudden rise in its temperature. Thus, it helps us in controlling our body temperature.
  • Water has such high specific heat due to hydrogen bonding between its atoms.

Also Check:

Previous Year Questions

  1. Two Identical Bodies Are Made of A Material [NEET 2016]
  2. Steam at 100C is passed into 20g of Water [KCET 2014]
  3. Hammer Of Mass 200 Kg Strikes A Steel Block Of M [DUET 2019]
  4. Hydrogen, Helium and Other Ideal Diatomic Gas [NEET 2019]
  5. Describe the temperature vs time graph. [JEE MAIN 2019]
  6. Cp – Cv relation for diatomic gases. [AMUEEE1999]
  7. Find the value of ϒ for diatomic gases. [NEET 2019]
  8. What is calorie? [BHU UET 2010]
  9. What fraction of heat energy is converted to work? [KCET 2020]
  10. Heat evolved in neutralisation of HF. [UPSEE 2018]
  11. Determine ratio of specific heats at constant volume. [AMUEEE 1998]
  12. Temperature of the sink in a carnot engine. [UPSEE 2019]
  13. Temperature of surrounding when Cu ball is heated. [AMUEEE 1998]
  14. Determine the entropy change in the body. [BITSAT 2012]
  15. Determine the temperature of the star. [BITSAT 2013]
  16. Detemining blackbody wavelength. [NEET 1989]
  17. Relation between the wavelength and temperature of black body. [KEAM 2004]
  18. Determine the thermal conductivity of the metal. [AP EAPCET]
  19. Determine the rate of heat radiated. [NEET]
  20. Determine the rate of heat transfer across the rod cross-section. [NEET 2009]

Sample Questions

Ques. How can you figure out how much specific heat capacity you have? (1 mark)

Ans. The amount of heat energy required to raise one gram of a product by one degree Celsius is known as specific heat capacity. The specific heat of water is 4.2 joules per gram per degree Celsius or 1 calorie per gram per degree Celsius.

Ques. What is the value for specific heat capacity for water? (1 mark)

Ans. Water has a specific heat capacity of 4.186J/goC.

Ques. What is the formula to calculate specific heat capacity? (1 mark)

Ans. The formula used to calculate the specific heat capacity of various elements is: 

c = Q/m.ΔT

Ques. What is the International System of Units (SI) for specific heat capacity? (1 mark)

Ans. The amount of heat required in joules to elevate 1 gram of a substance by 1 Kelvin is known as specific heat efficiency (symbol:c) in SI units. It can also be represented as J/K.kg.

Ques. What's the difference between heat capacity and specific heat capacity? (2 marks) 

Ans. The amount of heat required to raise a substance's temperature by one degree Celsius is known as specific heat capacity. 

Similarly, heat capacity is the ratio between the amount of energy delivered to a substance and the increase in temperature that results.

Ques. Water has a higher specific heat capacity than metal. Why? (2 marks)

Ans. Water has a higher specific heat capacity due to the presence of hydrogen bonding in its molecules. This is because the specific heat efficiency of the metal spoon is substantially lower than that of the soup liquid.

Ques. If we have 2 kg of water. How much heat capacity the water has, if the water’s specific heat is 4180 J/kgoC. (2 marks)

Ans. c = 4180 J/kgoC

m = 2kg

C = mc

= 2*(4180)

= 8360 J/oC

Ques. A cube of lead, 500 gm in volume, is heated from a temperature of 25oC to 75oC. If lead’s specific heat is given as 0.129 J/goC, calculate the energy that is required to heat the lead. (3 marks)

Ans. m = 500 gm

c = 0.129 J/goC

ΔT = (75-25)oC

= 50oC

We know that, Q = cmΔT

= (500)(0.129)(50)

= 3225 J

Ques. A metal ball of 25 grams is heated at a temperature of 200oC with 2330 J of energy. Find out the specific heat of the metal ball. (3 marks)

 Ans. m = 25 gms

ΔT = 200oC

Q = 2330 J

Putting these values in Q = cmΔT

2330 J = (25 g)c(200oC)

2330 J = (5000goC)c

When we divide both the sides by 5000 goC

2330 J/5000 goC = c

c = 0.466 J/goC

Also Read:

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                      CBSE CLASS XII Previous Year Papers

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