Content Curator | Updated On - May 12, 2024
TS EAMCET 2024 Question Paper May 10 Shift 2 with Answer Key PDF is available here for download. JNTU, Hyderabad on behalf of TSCHE conducted TS EAMCET on May 10 from 9 AM to 12 PM. TS EAMCET 2024 Question Paper consists of 160 questions carrying 1 mark each. TS EAMCET 2024 Question Paper May 10 Shift 2 PDF for MPC includes three subjects, Physics, Chemistry and Mathematics. The Physics and Chemistry section of the paper includes 40 questions each while the Mathematics section includes a total of 80 questions.
TS EAMCET 2024 Question Paper with Answer Key May 10 Shift 2 PDF
| TS EAMCET 2024 Question Paper PDF | TS EAMCET 2024 Answer Key PDF |
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Also Check:
TS EAMCET Previous Year Question Papers
| TS EAMCET 2023 Question Paper | TS EAMCET 2022 Question Paper |
| TS EAMCET 2021 Question Paper | TS EAMCET 2020 Question Paper |
| TS EAMCET 2019 Question Paper | TS EAMCET 2018 Question Paper |
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TS EAMCET Questions
1. If i=√-1 then
\[Arg\left[ \frac{(1+i)^{2025}}{1+i^{2022}} \right] =\]
If i=√-1 then
\[Arg\left[ \frac{(1+i)^{2025}}{1+i^{2022}} \right] =\]\(\frac{-π}{4}\)
\(\frac{π}{4}\)
\(\frac{3π}{4}\)
\(\frac{-3π}{4}\)
2. The velocity of a particle having a magnitude of 10 ms-1 in the direction of 60° with positive X-axis is
The velocity of a particle having a magnitude of 10 ms-1 in the direction of 60° with positive X-axis is
5i - 5√3j
5√3i - 5j
5√3i + 5j
5i + 5√3j
3. Which one of the following has the same number of atoms as are in 6g of H2O
Which one of the following has the same number of atoms as are in 6g of H2O
0.4G He
22g CO2
1g H2
12g CO
4. The roots of the equation x4 + x3 - 4x2 + x + 1 = 0 are diminished by h so that the transformed equation does not contain x2 term. If the values of such h are α and β, then 12(α - β)2 =
The roots of the equation x4 + x3 - 4x2 + x + 1 = 0 are diminished by h so that the transformed equation does not contain x2 term. If the values of such h are α and β, then 12(α - β)2 =
35
25
105
115
5. The number of diagonals of a polygon is 35. If A, B are two distinct vertices of this polygon, then the number of all those triangles formed by joining three vertices of the polygon having AB as one of its sides is:
The number of diagonals of a polygon is 35. If A, B are two distinct vertices of this polygon, then the number of all those triangles formed by joining three vertices of the polygon having AB as one of its sides is:
1
8
10
12
6. If 2i - j + 3k, -12i - j - 3k, -i + 2j -4k and λi + 2j - k are the position vectors of four coplanar points, then λ =
If 2i - j + 3k, -12i - j - 3k, -i + 2j -4k and λi + 2j - k are the position vectors of four coplanar points, then λ =
9
-2
8
6
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