Question

The velocity of a particle having a magnitude of 10 ms^-1 in the direction of 60° with positive X-axis is

• A. 5i - 5√3j
• B. 5√3i - 5j
• C. 5√3i + 5j
• D. 5i + 5√3j

Answer 1

The Correct Option is D

The correct option is: (D): 5i + 5√3j .

The given velocity vector can be represented as a combination of its components along the X-axis and Y-axis. The velocity's X-component (Vx) is given by the magnitude (10 m/s) multiplied by the cosine of the angle (60°), and the Y-component (Vy) is given by the magnitude multiplied by the sine of the angle.

Vx = 10 m/s * cos(60°) = 10 * 0.5 = 5 m/s Vy = 10 m/s * sin(60°) = 10 * (√3 / 2) = 5√3 m/s

So, the velocity vector is 5i + 5√3j, which corresponds to 5 m/s in the positive X-direction and 5√3 m/s in the positive Y-direction.