- Question Paper 2024
- Question Paper
- Question Paper 2022
- Question Paper 2021
- Question Paper 2020
- Question Paper 2019
- Question Paper 2018
- Question Paper 2017
- Question Paper 2016
- Practice Papers
Content Writer | Updated On - Jul 15, 2024
KCET 2023 question paper with solution is available for download. Candidates can check and download code-wise question papers for Mathematics, Biology, Physics, Chemistry and Kannada language here. Each question had one mark with no negative marking.
KCET 2023 Question Paper with Answers PDF
Paper | Exam Date | Code | Question Paper with Solutions |
---|---|---|---|
Biology | May 20, 2023 | Code B4 | Check here |
Code C1 | Check here | ||
Code D2 | Check here | ||
Mathematics | May 20, 2023 | Code A1 | Check here |
Code A2 | Check here | ||
Code A3 | Check here | ||
Code A4 | Check here | ||
Code B1 | Check here | ||
Code B3 | Check here | ||
Code C2 | Check here | ||
Code C3 | Check here | ||
Code C4 | Check here | ||
Code D1 | Check here | ||
Code D2 | Check here | ||
Physics | May 21, 2023 | Code A3 | Check here |
Chemistry | May 21, 2023 | - | Check Here |
Kannada Language | May 22, 2023 | - | To be Updated |
KCET 2023 Questions
1. A cubical Gaussian surface has side of length a = 10 cm. Electric field lines are parallel to x-axis as shown. The magnitudes of electric fields through surfaces ABCD and EFGH are 6kNC-1 and 9kNC-1 respectively. Then the total charge enclosed by the cube is
[Take ε0 = 9 × 10-12 Fm-1]
[Take ε0 = 9 × 10-12 Fm-1]
- 1.35 nC
- -1.35 nC
- 0.27 nC
- -0.27 nC
2. The modulus of the complex number \(\frac{(1+i)^2(1+3i)}{(2-6i)(2-2i)}\) is
- \(\frac{1}{\sqrt2}\)
- \(\frac{4}{\sqrt2}\)
- \(\frac{\sqrt2}{4}\)
- \(\frac{2}{\sqrt2}\)
3. The value of \(\begin{vmatrix} \sin^2 14 \degree & \sin^2 66\degree & \tan 135\degree \\ \sin^2 66\degree & \tan 135\degree & \sin^2 14 \degree \\ \tan 135\degree & \sin^2 14 \degree & \sin^2 66\degree \end{vmatrix}\)
- 1
- -1
- 2
- 0
4. In the Young’s double slit experiment, the intensity of light passing through each of the two double slits is 2 × 10-2 Wm-2. The screen-slit distance is very large in comparison with slit-slit distance. The fringe width is β. The distance between the central maximum and a point P on the screen is \(\frac{\beta}{3}\). Then the total light intensity at that point is
- 4 × 10-2 Wm-2
- 2 × 10-2 Wm-2
- 16 × 10-2 Wm-2
- 8 × 10-2 Wm-2
5. A stretched wire of a material whose Young's modulus Y = 2 × 1011 Nm-2 has Poisson's ratio of 0.25. Its lateral strain εl = 10-3. The elastic energy density of the wire is
- 1 × 105 Jm-3
- 4 × 105 Jm-3
- 8 × 105 Jm-3
- 16 × 105 Jm-3
*The article might have information for the previous academic years, which will be updated soon subject to the notification issued by the University/College.
Comments