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Content Curator | Updated On - May 24, 2024
AP ECET 2024 Question Paper PDF is available for download here. Jawaharlal Nehru Technological University, Anantapur (JNTUA) conducted AP ECET on May 8 in two shifts. AP ECET question paper carries a weightage of 200 marks. Candidates are required to answer 200 questions in a duration of 3 hours. Candidates appearing for AP ECET exam can download and practice the previous year question paper for a better understanding of the exam pattern and test their exam prep level.
AP ECET 2024 Question Paper PDF
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AP ECET Previous Year Question Paper with Answer Key PDF
AP ECET 2024 Questions
1. Let $M$ and $m$ respectively denote the maximum and the minimum values of $[f(\theta)]^{2}$, where $f(\theta)=\sqrt{a^{2} \cos ^{2} \theta+b^{2} \sin ^{2} \theta}$
$+\sqrt{a^{2} \sin ^{2} \theta+b^{2} \cos ^{2} \theta}$. Then $M-m=$
- $a^2 + b^2$
- $(a -b)^2$
- $a^2 b^2$
- $(a + b)^2$
2. The half-life periods of a first order reaction at $300\, K$ and $400\, K$ are $50\, s$ and $10\, s$ respectively.
The activation energy of the reaction in $kJ \; mol^{-1}$ is (log 5 = 0.70)
- 4
- 8
- 16.1
- 20.1
3. If $I_{n} = \int \frac{\sin nx}{\sin x} dx $ for $n = 1, 2 , 3,...,$ then $I_6$ =
- $\frac{3}{5} \sin3x + \frac{8}{3} \sin^{5} x -\sin x +c $
- $\frac{2}{5} \sin 5x - \frac{5}{3} \sin^{3} x - 2 \sin x +c $
- $\frac{2}{3} \sin 5x - \frac{8}{3} \sin^{5} x + 4 \sin x +c $
- $\frac{2}{5} \sin 5 x -\frac{8}{3} \sin^{3} x + 4 \sin x +c $
4. A solution is prepared by dissolving $10 \,g$ of a non-volatile solute (molar mass, $'M^{\prime} g mol ^{-1}$ ) in $360\, g$ of water. What is the molar mass in $g\, mol ^{-1}$ of solute if the relative lowering of vapour pressure of solution is $5 \times 10^{-3}$ ?
- 199
- 99.5
- 299
- 149.5
5. A solid copper sphere of density $\rho$, specific heat capacity $C$ and radius $r$ is initially at $200\, K$. It is suspended inside a chamber whose walls are at $0\, K$. The time required (in (is) for the temperature of the sphere to drop to $100 \,K$ is
($\sigma$ is Stefan's constant and all the quantities are in SI units)
- $48 \frac{r\rho C}{\sigma}$
- $\frac{1}{48} \frac{r\rho C}{\sigma}$
- $\frac{27}{7} \frac{r\rho C}{\sigma}$
- $\frac{7}{27} \frac{r\rho C}{\sigma}$
*The article might have information for the previous academic years, which will be updated soon subject to the notification issued by the University/College.
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