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Content Curator | Updated On - May 7, 2024
AP ECET 2022 Question Paper PDF is available for download. Jawaharlal Nehru Technological University (JNTU), Ananthpur conducted AP ECET on July 20 in two shifts. AP ECET question paper carries a weightage of 200 marks. Candidates are required to answer 200 questions in a duration of 3 hours. Candidates appearing for AP ECET exam can download and practice the previous year question paper for a better understanding of the exam pattern and test their exam prep level.
Also Check:AP ECET 2022 Question Paper PDFs
| AP ECET 2022 Question Paper | Question Paper PDF |
|---|---|
| Agricultural Engineering | Check Here |
| Chemical Engineering | Check Here |
| Civil Engineering | Check Here |
| Computer Science And Engineering | Check Here |
| Electronics And Communication Engineering | Check Here |
| Electrical And Electronics Engineering | Check Here |
| Electronics And Instrumentation Engineering | Check Here |
| Mechanical Engineering | Check Here |
| Metallurgical Engineering | Check Here |
| Mining Engineering | Check Here |
| Pharmacy | Check Here |
AP ECET Previous Year Question Paper with Answer Key PDF
AP ECET 2022 Questions
1. Let $M$ and $m$ respectively denote the maximum and the minimum values of $[f(\theta)]^{2}$, where $f(\theta)=\sqrt{a^{2} \cos ^{2} \theta+b^{2} \sin ^{2} \theta}$
$+\sqrt{a^{2} \sin ^{2} \theta+b^{2} \cos ^{2} \theta}$. Then $M-m=$
Let $M$ and $m$ respectively denote the maximum and the minimum values of $[f(\theta)]^{2}$, where $f(\theta)=\sqrt{a^{2} \cos ^{2} \theta+b^{2} \sin ^{2} \theta}$
$+\sqrt{a^{2} \sin ^{2} \theta+b^{2} \cos ^{2} \theta}$. Then $M-m=$
- $a^2 + b^2$
- $(a -b)^2$
- $a^2 b^2$
- $(a + b)^2$
2. The half-life periods of a first order reaction at $300\, K$ and $400\, K$ are $50\, s$ and $10\, s$ respectively.
The activation energy of the reaction in $kJ \; mol^{-1}$ is (log 5 = 0.70)
The half-life periods of a first order reaction at $300\, K$ and $400\, K$ are $50\, s$ and $10\, s$ respectively.
The activation energy of the reaction in $kJ \; mol^{-1}$ is (log 5 = 0.70)
- 4
- 8
- 16.1
- 20.1
3. If $I_{n} = \int \frac{\sin nx}{\sin x} dx $ for $n = 1, 2 , 3,...,$ then $I_6$ =
If $I_{n} = \int \frac{\sin nx}{\sin x} dx $ for $n = 1, 2 , 3,...,$ then $I_6$ =
- $\frac{3}{5} \sin3x + \frac{8}{3} \sin^{5} x -\sin x +c $
- $\frac{2}{5} \sin 5x - \frac{5}{3} \sin^{3} x - 2 \sin x +c $
- $\frac{2}{3} \sin 5x - \frac{8}{3} \sin^{5} x + 4 \sin x +c $
- $\frac{2}{5} \sin 5 x -\frac{8}{3} \sin^{3} x + 4 \sin x +c $
4. A solution is prepared by dissolving $10 \,g$ of a non-volatile solute (molar mass, $'M^{\prime} g mol ^{-1}$ ) in $360\, g$ of water. What is the molar mass in $g\, mol ^{-1}$ of solute if the relative lowering of vapour pressure of solution is $5 \times 10^{-3}$ ?
A solution is prepared by dissolving $10 \,g$ of a non-volatile solute (molar mass, $'M^{\prime} g mol ^{-1}$ ) in $360\, g$ of water. What is the molar mass in $g\, mol ^{-1}$ of solute if the relative lowering of vapour pressure of solution is $5 \times 10^{-3}$ ?
- 199
- 99.5
- 299
- 149.5
5. A solid copper sphere of density $\rho$, specific heat capacity $C$ and radius $r$ is initially at $200\, K$. It is suspended inside a chamber whose walls are at $0\, K$. The time required (in (is) for the temperature of the sphere to drop to $100 \,K$ is
($\sigma$ is Stefan's constant and all the quantities are in SI units)
A solid copper sphere of density $\rho$, specific heat capacity $C$ and radius $r$ is initially at $200\, K$. It is suspended inside a chamber whose walls are at $0\, K$. The time required (in (is) for the temperature of the sphere to drop to $100 \,K$ is
($\sigma$ is Stefan's constant and all the quantities are in SI units)
- $48 \frac{r\rho C}{\sigma}$
- $\frac{1}{48} \frac{r\rho C}{\sigma}$
- $\frac{27}{7} \frac{r\rho C}{\sigma}$
- $\frac{7}{27} \frac{r\rho C}{\sigma}$
*The article might have information for the previous academic years, which will be updated soon subject to the notification issued by the University/College.
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