AP ECET 2017 Mining Engineering Question Paper with Answer Key PDF (May 3)

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AP ECET 2017 Mining Engineering Question Paper with Answer Key pdf is available for download. The exam was conducted by Jawaharlal Nehru Technological University, Ananthapur on May 3, 2017 in the Forenoon Session 10 AM to 1 PM. The question paper comprised a total of 200 questions.

AP ECET 2017 Mining Engineering Question Paper with Answer Key PDF

AP ECET 2017 Mining Engineering Question Paper PDF AP ECET 2017 Mining Engineering Answer Key PDF
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AP ECET Questions

  • 1.
    A solid copper sphere of density $\rho$, specific heat capacity $C$ and radius $r$ is initially at $200\, K$. It is suspended inside a chamber whose walls are at $0\, K$. The time required (in (is) for the temperature of the sphere to drop to $100 \,K$ is ($\sigma$ is Stefan's constant and all the quantities are in SI units)

      • $48 \frac{r\rho C}{\sigma}$
      • $\frac{1}{48} \frac{r\rho C}{\sigma}$
      • $\frac{27}{7} \frac{r\rho C}{\sigma}$
      • $\frac{7}{27} \frac{r\rho C}{\sigma}$

    • 2.
      Let $A, G, H$ and $S$ respectively denote the arithmetic mean, geometric mean, harmonic mean and the sum of the numbers $a_1 , a_2 , a_3 ....., a_n$ . Then the value of at which the function $f(x) =\displaystyle \sum^n_{k =1} (x -a_k)^2$ has minimum is

        • S
        • H
        • G
        • A

      • 3.
        The half-life periods of a first order reaction at $300\, K$ and $400\, K$ are $50\, s$ and $10\, s$ respectively. The activation energy of the reaction in $kJ \; mol^{-1}$ is (log 5 = 0.70)

          • 4
          • 8
          • 16.1
          • 20.1

        • 4.
          A parallel plate capacitor consists of two circular plates each of radius $2 \,cm$, separated by a distance of $0.1 \,mm$. If the potential difference across the plates is varying at the rate of $5 \times 10^{6} Vs ^{-1}$, then the value of displacement current is

            • 5.56 A
            • 5.56 mA
            • 0.556 mA
            • 2.28 mA

          • 5.
            A solution is prepared by dissolving $10 \,g$ of a non-volatile solute (molar mass, $'M^{\prime} g mol ^{-1}$ ) in $360\, g$ of water. What is the molar mass in $g\, mol ^{-1}$ of solute if the relative lowering of vapour pressure of solution is $5 \times 10^{-3}$ ?

              • 199
              • 99.5
              • 299
              • 149.5

            • 6.
              If $I_{n} = \int \frac{\sin nx}{\sin x} dx $ for $n = 1, 2 , 3,...,$ then $I_6$ =

                • $\frac{3}{5} \sin3x + \frac{8}{3} \sin^{5} x -\sin x +c $
                • $\frac{2}{5} \sin 5x - \frac{5}{3} \sin^{3} x - 2 \sin x +c $
                • $\frac{2}{3} \sin 5x - \frac{8}{3} \sin^{5} x + 4 \sin x +c $
                • $\frac{2}{5} \sin 5 x -\frac{8}{3} \sin^{3} x + 4 \sin x +c $

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