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TS EAMCET 2024 Question Paper May 9 Shift 1: Download MPC Question Paper with Solutions PDF
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Sonal Vaid

Content Curator | Updated On - May 12, 2024

TS EAMCET 2024 Question Paper May 9 Shift 1 with Answer Key PDF will be available here for download. JNTU, Hyderabad on behalf of TSCHE is going to conduct TS EAMCET on May 9 from 9 AM to 12 PM. TS EAMCET 2024 Question Paper consists of 160 questions carrying 1 mark each. TS EAMCET 2024 Question Paper May 9 Shift 1 PDF for MPC includes three subjects, Physics, Chemistry and Mathematics. The Physics and Chemistry section of the paper includes 40 questions each while the Mathematics section includes a total of 80 questions.

TS EAMCET 2024 Question Paper with Answer Key May 9 Shift 1 PDF

TS EAMCET 2024 Question Paper PDF TS EAMCET 2024 Answer Key PDF
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TS EAMCET Questions

1.

If i=√-1 then 

\[Arg\left[ \frac{(1+i)^{2025}}{1+i^{2022}} \right] =\]

    • \(\frac{-π}{4}\)

    • \(\frac{π}{4}\)

    • \(\frac{3π}{4}\)

    • \(\frac{-3π}{4}\)

    2.

    Which one of the following has the same number of atoms as are in 6g of H2O

      • 0.4G He

      • 22g CO2

      • 1g H2

      • 12g CO

      3.

      The locus of z such that  \(\frac{|z-i|}{|z+i|}\)= 2, where z = x+iy. is

        • 3x2 + 3y2 +10y + 3

        • 3x2 - 3y2 - 10y - 3 = 0

        • 3x2 + 3y2 + 10y + 3 = 0

        • x2 + y2 - 5y + 3 = 0

        4.

        The roots of the equation x4 + x3 - 4x2 + x + 1 = 0 are diminished by h so that the transformed equation does not contain x2 term. If the values of such h are α and β, then 12(α - β)2 =

          • 35

          • 25

          • 105

          • 115

          5.

          The number of significant figures in the measurement of a length 0.079000 m is: 

            • 7

            • 2

            • 5

            • 4

            6.

            The velocity of a particle having a magnitude of 10 ms-1 in the direction of 60° with positive X-axis is

              • 5i - 5√3j 

              • 5√3i - 5j

              • 5√3i + 5j 

              • 5i + 5√3j 

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