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TS EAMCET 2020 Agriculture and Medical Question paper with answer key pdf conducted on September 29 in Forenoon Session 9 AM to 12 PM is available for download. The exam was successfully organized by Jawaharlal Nehru Technological University, Hyderabad (JNTUH). The question paper comprised a total of 160 questions divided among 4 sections.
TS EAMCET 2020 Agriculture and Medical Question Paper with Answer Key PDFs Forenoon Session
TS EAMCET 2020 Agriculture and Medical Question Paper PDF | TS EAMCET 2020 Agriculture and Medical Answer Key PDF |
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TS EAMCET Questions
1. If i=√-1 then
\[Arg\left[ \frac{(1+i)^{2025}}{1+i^{2022}} \right] =\]
If i=√-1 then
\[Arg\left[ \frac{(1+i)^{2025}}{1+i^{2022}} \right] =\]\(\frac{-π}{4}\)
\(\frac{π}{4}\)
\(\frac{3π}{4}\)
\(\frac{-3π}{4}\)
2. The energy of second orbit of hydrogen atom is -5.45x10-19 J. What is the energy of first orbit of Li2+ ion (in J)
-1.962x10-18
-1.962x10-17
-3.924x10-17
-3.924x10-18
3. The number of diagonals of a polygon is 35. If A, B are two distinct vertices of this polygon, then the number of all those triangles formed by joining three vertices of the polygon having AB as one of its sides is:
The number of diagonals of a polygon is 35. If A, B are two distinct vertices of this polygon, then the number of all those triangles formed by joining three vertices of the polygon having AB as one of its sides is:
1
8
10
12
4. If the ratio of densities of two substances is 5:6 and the ratio of their specific heat capacities is 3:5, then the ratio of heat energies required per unit volume so that the two substances can have same temperature rise is:
1:1
1:4
1:2
1:3
5. lim n→∞ \(\frac{1}{n^3} \)
\[\sum_{k=1}^{n} k^{2} = \]
lim n→∞ \(\frac{1}{n^3} \)
\[\sum_{k=1}^{n} k^{2} = \]
x
\(\frac{x}{2}\)
\(\frac{x}{3}\)
\(\frac{x}{4}\)
6. 5 persons entered a lift cabin in the cellar of a 7-floor building apart from cellar. If each of the independently and with equal probability can leave the cabin at any floor out of the 7 floors beginning with the first, then the probability of all the 5 persons leaving the cabin at different floors is
5 persons entered a lift cabin in the cellar of a 7-floor building apart from cellar. If each of the independently and with equal probability can leave the cabin at any floor out of the 7 floors beginning with the first, then the probability of all the 5 persons leaving the cabin at different floors is
\(\frac{360}{2401}\)
\(\frac{5}{54}\)
\(\frac{51}{71}\)
\(\frac{5}{18}\)
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