Concept:
The iodoform test is used to identify compounds containing the methyl ketone group (\(-COCH_3\)) or alcohols that can be oxidized to it. Ethanol is the only primary alcohol that gives a positive iodoform test because it can be oxidized to acetaldehyde.
Procedure:
Add iodine solution and sodium hydroxide (NaOH) to the given alcohol and warm gently.
Observation:
Ethanol: Produces a yellow precipitate of iodoform (\(CHI_3\)) with a characteristic antiseptic smell.
Methanol: Does not produce any yellow precipitate (negative test).
Reason:
Ethanol is oxidized to acetaldehyde (\(CH_3CHO\)), which contains the required methyl carbonyl group and gives the iodoform reaction.
Methanol is oxidized to formaldehyde (\(HCHO\)), which does not contain the methyl group required for the test.
Conclusion:
Thus, ethanol can be distinguished from methanol because ethanol gives a positive iodoform test (yellow precipitate), while methanol does not.