The conductivity of a solution containing 2.08 g of anhydrous barium chloride in 200 mL solution is $6 \times 10^{-3} \, \text{ohm}^{-1} \, \text{cm}^{-1}$. The molar conductivity of the solution (in $\text{ohm}^{-1} \, \text{cm}^{2} \, \text{mol}^{-1}$) is $x \times 10^{2}$. The value of $x$ is
(Atomic mass of Ba = 137, Cl = 35.5)
