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KEAM 2024 Pharmacy Question Paper with Answer Key (June 10)
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Ahana Bhaduri

Content Writer | Updated On - Jun 19, 2024

KEAM 2024 Question Paper (June 10) is available for download here. Office of The Commissioner for Entrance Examinations (CEE Kerala) conducted KEAM Pharmacy exam 2024 in CBT mode on June 10 in afternoon shift from 2 PM to 5 PM. KEAM Pharmacy 2024 Question Paper consists total of 75 questions carrying 4 mark each with negative marking of 1 for each incorrect answer. KEAM 2024 Question Paper includes Physics with 45 questions and Chemistry with 30 questions to be attempted in total of 90 minutes.

KEAM 2024 Question Paper with Answer Key PDF (June 10)

KEAM 2024 Question Paper PDF KEAM 2024 Answer Key PDF
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KEAM Questions

1.

A projectile is thrown at a speed V and at an angle with the horizontal. If the speed at its maximum height is \(\frac{V}{3}\),then the value of tan θ is: 

    • \(\sqrt{3}\)

    • \(\frac{1}{\sqrt{3}}\)

    • 2\(\sqrt{2}\)

    • 3

    • 3\(\sqrt{3}\)

    2.
    The value of a(≠0) for which the equation \(\frac{1}{2}(x-2)^2+1=\sin(\frac{a}{x})\) holds is/are

      • \((4n+1)\pi,n\isin \Z\)
      • \(2(n-1)\pi,n\isin \Z\)
      • \(n\pi,n\isin \N\)
      • \(\frac{n\pi}{2},\isin \N\)
      • 1

      3.
      \(∫\dfrac{x+5}{x^{2}+1}dx=\)

        • \( 3ln|x-1|-2ln|x+1|+C\)

        • \(2ln|x-1|-3ln|x+1|+C\)

        • \(ln|x-2|-ln|x+1|+C\)

        • \( ln|x+2|+ln|x+1|+C\)

        • \(2ln|x-1|+3ln|x-1|+C\)

        4.
        Let α and β be such that α+β=π. If \(\cos\alpha=\frac{1}{\sqrt2}\), then the value of cot (β-α) is

          • 1
          • \(\frac{1}{2}\)
          • \(\frac{1}{4}\)
          • 0

          5.
          An inductor coil with an internal resistance of 50 Ω stores magnetic field energy 180 mJ and dissipates energy as heat at the rate of 200 W when a constant current 9 passed through it. The inductance of the coil will be:

            • 90 mH

            • 120 mH

            • 45 mH

            • 30 mH

            • 60 mH

            6.
            Let \(a,b,c,d \) be an increasing sequence of real numbers,which are in geometric progression .If \(a+d=112\) and \(b+c=48\) ,then the value of \(\dfrac{a+c+8}{b}\) is 

              • \(1\)

              • \(5\)

              • \(4\)

              • \(3\)

              • \(2\)

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