Question

The value of a(≠0) for which the equation \(\frac{1}{2}(x-2)^2+1=\sin(\frac{a}{x})\) holds is/are

• A. \((4n+1)\pi,n\isin \Z\)
• B. \(2(n-1)\pi,n\isin \Z\)
• C. \(n\pi,n\isin \N\)
• D. \(\frac{n\pi}{2},\isin \N\)
• E. 1

Answer 1

The Correct Option is A

The correct option is (A): \((4n+1)\pi,n\isin \Z\)