Content Curator | Updated On - May 12, 2024
TS EAMCET 2024 Question Paper May 7 Shift 1 with Answer Key PDF is available here. JNTU, Hyderabad on behalf of TSCHE conducted TS EAMCET on May 7 from 9 AM to 12 PM. TS EAMCET 2024 Question Paper consists of 160 questions carrying 1 mark each. TS EAMCET 2024 Question Paper May 7 Shift 1 PDF for BiPC includes four subjects, Physics, Chemistry and Biology with Botany & Zoology. Each subject includes 40 questions.
TS EAMCET 2024 Question Paper with Answer Key May 7 Shift 1 PDF
| TS EAMCET 2024 Question Paper PDF | TS EAMCET 2024 Answer Key PDF |
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TS EAMCET Previous Year Question Papers
| TS EAMCET 2023 Question Paper | TS EAMCET 2022 Question Paper |
| TS EAMCET 2021 Question Paper | TS EAMCET 2020 Question Paper |
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TS EAMCET Questions
1. If order and degree of the differential equation corresponding to the family of curves y2 = 4a(x+a)(a is parameter) are m and n respectively, then m+n2 =
If order and degree of the differential equation corresponding to the family of curves y2 = 4a(x+a)(a is parameter) are m and n respectively, then m+n2 =
3
4
5
2
2.
\[\int_{\frac{-\pi}{2}}^{\frac{\pi}{2}} sin^2xcos^2x(sinx+cosx)dx=\]
\[\int_{\frac{-\pi}{2}}^{\frac{\pi}{2}} sin^2xcos^2x(sinx+cosx)dx=\]
\(\frac{2}{3}\)
\(\frac{3}{10}\)
\(\frac{4}{15}\)
\(\frac{5}{18}\)
3. The number of significant figures in the measurement of a length 0.079000 m is:
The number of significant figures in the measurement of a length 0.079000 m is:
7
2
5
4
4. The locus of z such that \(\frac{|z-i|}{|z+i|}\)= 2, where z = x+iy. is
The locus of z such that \(\frac{|z-i|}{|z+i|}\)= 2, where z = x+iy. is
3x2 + 3y2 +10y + 3
3x2 - 3y2 - 10y - 3 = 0
3x2 + 3y2 + 10y + 3 = 0
x2 + y2 - 5y + 3 = 0
5. Which one of the following has the same number of atoms as are in 6g of H2O
Which one of the following has the same number of atoms as are in 6g of H2O
0.4G He
22g CO2
1g H2
12g CO
6. The orthocenter of the triangle whose sides are given by x + y + 10 = 0, x - y - 2 = 0 and 2x + y - 7 = 0 is
The orthocenter of the triangle whose sides are given by x + y + 10 = 0, x - y - 2 = 0 and 2x + y - 7 = 0 is
(-4, -3)
(-4, -6)
(4,6)
(3,6)
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