Content Curator | Updated On - May 9, 2024
TS EAMCET 2023 Question Paper May 14 Shift 1 PDF is available here for download. TS EAMCET 2023 Question Paper consists of 160 questions carrying 1 mark each. TS EAMCET 2023 Question Paper May 14 Shift 1 PDF for MPC includes three subjects, Physics, Chemistry and Mathematics. The Physics and Chemistry section of the paper includes 40 questions each while the Mathematics section includes a total of 80 questions.
TS EAMCET 2023 Question Paper May 14 Shift 1 PDF
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TS EAMCET Questions
1. If the ratio of densities of two substances is 5:6 and the ratio of their specific heat capacities is 3:5, then the ratio of heat energies required per unit volume so that the two substances can have same temperature rise is:
1:1
1:4
1:2
1:3
2. The orthocenter of the triangle whose sides are given by x + y + 10 = 0, x - y - 2 = 0 and 2x + y - 7 = 0 is
The orthocenter of the triangle whose sides are given by x + y + 10 = 0, x - y - 2 = 0 and 2x + y - 7 = 0 is
(-4, -3)
(-4, -6)
(4,6)
(3,6)
3. The number of electrons with (n+1) values equal to 3,4 and 5 in an element with atomic number (z) 24 are respectively (n = principal quantum number and l = azimuthal quantum number)
The number of electrons with (n+1) values equal to 3,4 and 5 in an element with atomic number (z) 24 are respectively (n = principal quantum number and l = azimuthal quantum number)
7,8,5
6,8,6
8,7,5
8,8,5
4. Which one of the following has the same number of atoms as are in 6g of H2O
Which one of the following has the same number of atoms as are in 6g of H2O
0.4G He
22g CO2
1g H2
12g CO
5. The roots of the equation x4 + x3 - 4x2 + x + 1 = 0 are diminished by h so that the transformed equation does not contain x2 term. If the values of such h are α and β, then 12(α - β)2 =
The roots of the equation x4 + x3 - 4x2 + x + 1 = 0 are diminished by h so that the transformed equation does not contain x2 term. If the values of such h are α and β, then 12(α - β)2 =
35
25
105
115
6. 5 persons entered a lift cabin in the cellar of a 7-floor building apart from cellar. If each of the independently and with equal probability can leave the cabin at any floor out of the 7 floors beginning with the first, then the probability of all the 5 persons leaving the cabin at different floors is
5 persons entered a lift cabin in the cellar of a 7-floor building apart from cellar. If each of the independently and with equal probability can leave the cabin at any floor out of the 7 floors beginning with the first, then the probability of all the 5 persons leaving the cabin at different floors is
\(\frac{360}{2401}\)
\(\frac{5}{54}\)
\(\frac{51}{71}\)
\(\frac{5}{18}\)
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