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TS EAMCET 2023 Question Paper May 10 Shift 1 with Answer Key PDF is available here for download. TS EAMCET 2023 Question Paper consisted of 160 questions carrying 1 mark each. TS EAMCET 2023 Question Paper May 10 Shift 1 PDF for BiPC included four subjects, Physics, Chemistry and Biology with Botany & Zoology. Each subject includes 40 questions.
TS EAMCET 2023 Question Paper with Answer Key May 10 Shift 1 PDF
| TS EAMCET 2023 Question Paper PDF | TS EAMCET 2023 Answer Key PDF |
|---|---|
| Download PDF | Download PDF |
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TS EAMCET Previous Year Question Papers
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TS EAMCET Questions
1. The number of significant figures in the measurement of a length 0.079000 m is:
The number of significant figures in the measurement of a length 0.079000 m is:
7
2
5
4
2. The roots of the equation x4 + x3 - 4x2 + x + 1 = 0 are diminished by h so that the transformed equation does not contain x2 term. If the values of such h are α and β, then 12(α - β)2 =
The roots of the equation x4 + x3 - 4x2 + x + 1 = 0 are diminished by h so that the transformed equation does not contain x2 term. If the values of such h are α and β, then 12(α - β)2 =
35
25
105
115
3. If the line x cos α + y sin α = 2√3 is tangent to the ellipse \(\frac{x^2}{16} + \frac{y^2}{8} = 1\) and α is an acute angle then α =
If the line x cos α + y sin α = 2√3 is tangent to the ellipse \(\frac{x^2}{16} + \frac{y^2}{8} = 1\) and α is an acute angle then α =
\(\frac{π}{6}\)
\(\frac{π}{4}\)
\(\frac{π}{3}\)
\(\frac{π}{2}\)
4. The orthocenter of the triangle whose sides are given by x + y + 10 = 0, x - y - 2 = 0 and 2x + y - 7 = 0 is
The orthocenter of the triangle whose sides are given by x + y + 10 = 0, x - y - 2 = 0 and 2x + y - 7 = 0 is
(-4, -3)
(-4, -6)
(4,6)
(3,6)
5. The velocity of a particle having a magnitude of 10 ms-1 in the direction of 60° with positive X-axis is
The velocity of a particle having a magnitude of 10 ms-1 in the direction of 60° with positive X-axis is
5i - 5√3j
5√3i - 5j
5√3i + 5j
5i + 5√3j
6. The number of electrons with (n+1) values equal to 3,4 and 5 in an element with atomic number (z) 24 are respectively (n = principal quantum number and l = azimuthal quantum number)
The number of electrons with (n+1) values equal to 3,4 and 5 in an element with atomic number (z) 24 are respectively (n = principal quantum number and l = azimuthal quantum number)
7,8,5
6,8,6
8,7,5
8,8,5
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