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TS EAMCET 2022 July 31 Shift 2 question paper is now available for download. The exam was conducted from 03:00 PM to 06:00 PM. The question paper had a total of 160 questions. Out of which, 40 questions were asked from each subject in TS EAMCET 2022 July 31 Shift 2 question paper. As per students’ reactions, the question paper was rated moderate in terms of overall difficulty level.
TS EAMCET 2022 July 31 Shift 2 Question Paper
Candidates can download TS EAMCET 2022 question paper along with the solution pdf from the table below.
TS EAMCET 2022 Question Paper | TS EAMCET 2022 Answer Key |
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TS EAMCET Previous Year Question Papers
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TS EAMCET Questions
1. If the line x cos α + y sin α = 2√3 is tangent to the ellipse \(\frac{x^2}{16} + \frac{y^2}{8} = 1\) and α is an acute angle then α =
If the line x cos α + y sin α = 2√3 is tangent to the ellipse \(\frac{x^2}{16} + \frac{y^2}{8} = 1\) and α is an acute angle then α =
\(\frac{π}{6}\)
\(\frac{π}{4}\)
\(\frac{π}{3}\)
\(\frac{π}{2}\)
2. The roots of the equation x4 + x3 - 4x2 + x + 1 = 0 are diminished by h so that the transformed equation does not contain x2 term. If the values of such h are α and β, then 12(α - β)2 =
The roots of the equation x4 + x3 - 4x2 + x + 1 = 0 are diminished by h so that the transformed equation does not contain x2 term. If the values of such h are α and β, then 12(α - β)2 =
35
25
105
115
3. The orthocenter of the triangle whose sides are given by x + y + 10 = 0, x - y - 2 = 0 and 2x + y - 7 = 0 is
The orthocenter of the triangle whose sides are given by x + y + 10 = 0, x - y - 2 = 0 and 2x + y - 7 = 0 is
(-4, -3)
(-4, -6)
(4,6)
(3,6)
4. The number of diagonals of a polygon is 35. If A, B are two distinct vertices of this polygon, then the number of all those triangles formed by joining three vertices of the polygon having AB as one of its sides is:
The number of diagonals of a polygon is 35. If A, B are two distinct vertices of this polygon, then the number of all those triangles formed by joining three vertices of the polygon having AB as one of its sides is:
1
8
10
12
5. If i=√-1 then
\[Arg\left[ \frac{(1+i)^{2025}}{1+i^{2022}} \right] =\]
If i=√-1 then
\[Arg\left[ \frac{(1+i)^{2025}}{1+i^{2022}} \right] =\]\(\frac{-π}{4}\)
\(\frac{π}{4}\)
\(\frac{3π}{4}\)
\(\frac{-3π}{4}\)
6. The number of significant figures in the measurement of a length 0.079000 m is:
The number of significant figures in the measurement of a length 0.079000 m is:
7
2
5
4
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