Content Curator
TS EAMCET 2021 Engineering Question paper with answer key pdf conducted on August 4 in Forenoon Session 9 AM to 12 PM is available for download. The exam was successfully organized by Jawaharlal Nehru Technological University, Hyderabad (JNTUH). The question paper comprised a total of 160 questions divided among 3 sections.
TS EAMCET 2021 Engineering Question Paper with Answer Key PDFs Forenoon Session
| TS EAMCET 2021 Engineering Question Paper PDF | TS EAMCET 2021 Engineering Answer Key PDF |
|---|---|
| Download PDF | Download PDF |
TS EAMCET Previous Year Question Papers
Similar Exam Question Papers:
TS EAMCET Questions
1. The number of electrons with (n+1) values equal to 3,4 and 5 in an element with atomic number (z) 24 are respectively (n = principal quantum number and l = azimuthal quantum number)
The number of electrons with (n+1) values equal to 3,4 and 5 in an element with atomic number (z) 24 are respectively (n = principal quantum number and l = azimuthal quantum number)
7,8,5
6,8,6
8,7,5
8,8,5
2. The locus of z such that \(\frac{|z-i|}{|z+i|}\)= 2, where z = x+iy. is
The locus of z such that \(\frac{|z-i|}{|z+i|}\)= 2, where z = x+iy. is
3x2 + 3y2 +10y + 3
3x2 - 3y2 - 10y - 3 = 0
3x2 + 3y2 + 10y + 3 = 0
x2 + y2 - 5y + 3 = 0
3. The number of significant figures in the measurement of a length 0.079000 m is:
The number of significant figures in the measurement of a length 0.079000 m is:
7
2
5
4
4. The energy of second orbit of hydrogen atom is -5.45x10-19 J. What is the energy of first orbit of Li2+ ion (in J)
-1.962x10-18
-1.962x10-17
-3.924x10-17
-3.924x10-18
5. The number of diagonals of a polygon is 35. If A, B are two distinct vertices of this polygon, then the number of all those triangles formed by joining three vertices of the polygon having AB as one of its sides is:
The number of diagonals of a polygon is 35. If A, B are two distinct vertices of this polygon, then the number of all those triangles formed by joining three vertices of the polygon having AB as one of its sides is:
1
8
10
12
6. The roots of the equation x4 + x3 - 4x2 + x + 1 = 0 are diminished by h so that the transformed equation does not contain x2 term. If the values of such h are α and β, then 12(α - β)2 =
The roots of the equation x4 + x3 - 4x2 + x + 1 = 0 are diminished by h so that the transformed equation does not contain x2 term. If the values of such h are α and β, then 12(α - β)2 =
35
25
105
115
.png?h=160&w=320&mode=stretch)
.jpeg?h=160&w=320&mode=stretch)
.png?h=160&w=320&mode=stretch)
.png?h=160&w=320&mode=stretch)
Comments