Set Theory for CAT

The most important thing about this chapter is the use of Venn diagrams, which are a key part of rational thinking. This is why this part in CAT, XLRI, FMS, CET, etc. is interesting, makes sense, and is important. Since we have to use Venn diagrams to solve most problems, the theory and ideas behind Venn diagrams are given the most attention. Formulas and mathematical theory are not very important on the CAT, but we still need to know the basics of sets and how to use them.


Set

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A set is a group of objects that is well-defined. Members or elements are the objects constituting a set. If a is an element of a set A, then we write a A (and say a belongs to A), which means 'a' is a member of 'A'. If a does not belong to A, then we write a ∉ A. By convention, sets are denoted by capital alphabets, such as A, B, C,..., X, Y, and Z, and set elements are denoted by a, b, c,...., x, y, and z, respectively.

Important Notations of Standard Sets

N: the set of natural numbers

Z+: the set of positive integers

Q+: the set of all positive rational numbers

R+: the set of all positive real numbers

Z : the set of integers

R : the set of real numbers

Q : the set of all rational numbers

C : the set of all complex numbers.

Methods of Representation of Sets

  1. Roster Method

In this method, a set is described by enclosing a comma-separated list of all its elements within braces { } .

Ex: set of even numbers up to 20 is {2,4,6,8,10,12,14,16,18,20}

*order of the element is not important

  1. Set builder Method

A set is described by listing its property in the given manner. The set P (x) is described as P = { x : P (x) holds } or { x | P (x) holds } which is read as ‘the set of all x such that P (x) holds’. The symbol ‘|’ or ‘:’ is read as ‘such that’

  1. The set of perfect squares upto 100 can be written as

P = {x : x is a perfect square and 0 ≤ x ≤ 100, x N } or

P={ x: xN, x = n2, 0 ≤ < 100, nZ}

or P ={x2: x Z}

  1. The set of all the odd natural numbers can be expressed as A = { x : x N , x = 2n − 1, n N }

Types of Sets

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Singleton Set : A set consisting of a single element . Ex- {0} is a singleton set.

Empty Set : A set containing no element at all is called an empty set denoted by φ. Ex- {x:xR, x2 =−8}=φ

Finite Set : If a set has finite number of elements that can be counted or listed. Ex- set of all states in India

Cardinal Number : The number of distinct elements in a finite set is called the ‘cardinal number’ of the sete.g., n ( A) → n is the number of distinct elements in the set A.

Infinite Set : If the number of elements of a set is infinite i.e., which can’t be counted by natural numbers, is called infinite set. Ex- Set of all points on the arc of a circle

Equivalent Sets : Two finite sets A and B are equivalent if their cardinal numbers are same i.e. n ( A) = n (B ) e.g. A={a,e,i,o,u}and B={1,3,5,7,9}

Equal Sets : Two sets A and B are said to be equal, if every element of A is in B and every element of B is in A and it is denoted as A = B. Ex: A = {a,e,i,o,u} and = {e,o,i,a,u} ⇒ B

Subsets : Let A and B be two sets such that every element of A is the element of B, then A is called a subset of B. Denoted by A B

Superset : If A B, we say that B is a superset of A and we write B A. Read it as B is the superset of A.

Proper Subset : If ⊆ B and AB, then A is called a proper subset of B and denoted as A B. Ex- {5,15,25} ⊂ {5,10,15,20,25}

Properties of Subset:

  1. The empty set is a subset of every set
  2. Every set is a subset of itself.
  3. The number of all possible subsets of a set containing n elements is 2n .
  4. The number of all proper subsets of a set containing n elements is (2n − 1).
  5. The set of all subsets of a given set A is called the power set of A, denoted by P (A). Thus, if A has n elements P (A) has 2n

Universal Set : A set that contains all sets in a given context is called the universal set.

Power Set : The collection or family of all the subsets of a set A is called the power set of A and is denoted by P (A).


Venn Diagrams

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Initially, the Swiss mathematician Euler explained the concept of representing sets by points on a closed curve. Later, British mathematician Venn implemented this concept. This is why the entire concept is referred to as Euler-Venn diagrams or Venn diagrams.

Venn diagram


Operations On Sets

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Union of Sets : If A and B be two sets, then the union of A and B is the set of the all those elements which belong either to A or to B or to both A and B. Denoted as A B.

Union of sets

Intersection of Sets : If A and B be two sets then the intersection of A and B is the set of all those elements that belong to both A and B. Denoted by A B.

intersection of set

Disjoint Sets : Two sets A and B are said to be disjoint, if AB=φ. If ABφ then A and B are said to be intersecting or overlapping sets.

disjoint set

Difference of Sets : The difference of set A and set B (written as A B) is the set of all those elements of A which do not belong to B. Thus, A B = {x : x A and x ∉ B}.

difference of set

Symmetric difference of two Sets : The symmetric difference of sets A and B is the set ( A B ) ∪ (B A) and is denoted by A B AB=(AB)∪(BA)={x:x∉AB}.

symmetric difference of two sets

Complement of a Set : If U be the universal set and a set A is such that A U then, the complement of A with respect to U is denoted by A′ or Ac.

complement of sets


Algebraic Laws of Sets

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  1. Idempotent Laws : For any set A, we have
  1.  ∪ A  
  2. (ii) ∩ A

   2. Identity Laws : For any set A, we have

  1. A ∪ φ = A
  2. A U = A
  1. Commutative Laws: For any two sets A and B, we have
  1. ∪ ∪ A
  2. ∩ ∩ A
  1. Associative Laws: If A, B and C are any three sets, then
  1. ( A B ) ∪ C = A ∪ (B C )
  2. ∩ ( B ∩ C) = (∩ ) ∩ C
  1. Distributive Laws: If A, B and C are any three sets , then
  1. ∪ (B C) = (∪ B) ∩ (∪ C)
  1. ∩ (B C) = (∩ B) ∪ (∩ C)
  1. De-Morgan’s Laws : If A and B are any two sets, then
  1. (∪ B)′ = A′ ∩ B
  2. (∩ B)′ = A′ ∪ B

Important Results

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Operations on Numbers

  1. A − B = A ∩ B′
  2. B − A = B ∩ A′
  3. A − B = A ⇔ A ∩ B = φ
  4. (A − B) ∪ B = A ∪ B
  5. (A − B) ∩ B = φ
  6. A ⊆ B ⇔ B′ ⊆ A′
  7. (A − B) ∪ (B − A)=(A ∪ B) − (A ∩ B)

Number of Elements in Sets

If A, B and C are finite sets, and U be the finite universal set then

  1. n (A ∪ B)=n(A) + n(B) − n(A ∩ B)
  2. n ( A ∪ B ) = n ( A) + n (B ) ⇔ A, B are disjoint non-void sets.
  3. n(A − B) = n(A) − n(A ∩ B) i.e., n (A − B) + n (A ∩ B) = n (A)
  4. n ( A ∆ B ) = Number of elements which belong to exactly one of A or B = n ( A)+ n (B ) − 2n ( A ∩ B )
  5. n(A ∪ B ∪ C) = n(A) + n(B)  +n(C) − n ( A ∩ B ) − n (B ∩ C ) − n ( A ∩ C ) + n ( A ∩ B ∩ C )
  6. Number of elements in exactly two of the sets A, B, C = n(A ∩ B)  +n( B ∩ C) + n(C ∩ A) − 3n(A ∩ B ∩C)
  7. number of elements in exactly one of the sets A, B, C = n ( A) + n (B ) + n (C ) − 2n ( A ∩ B ) − 2n (B ∩ C)− 2n (A ∩ C)+ 3n(A ∩ B ∩C)
  8. n(A′ ∪ B′) = n[(A ∩ B)′]=n(U)−n(A ∩ B)
  9. n(A′ ∩ B′) = n[(A ∪ B)′ ]= n(U) − n(A ∪ B)

Venn Diagrams Containing Three Circles

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Venn diagram containing three cycle

Let P, Q, R be three fruits, then

a \(\to \) number of people eating only P

\(\to \) number of people eating only Q

c \(\to \) number of people eating only R

x \(\to \) number of people eating P and Q both but not R

y \(\to \) number of people eating Q and R both but not P z → number of people eating P and R both but not Q k → number of people eating all the three fruits

x + k \(\to \) number of people eating P and Q both

y + k \(\to \) number of people eating Q and R both

z + k \(\to \) number of people eating P and R both

a + x + k + z \(\to \) number of people eating P

b + x + k + y \(\to \) number of people eating Q

c + y + k + z \(\to \) number of people eating R

a + x + b \(\to \) number of people eating P or Q but not R

b + y + c \(\to \) number of people eating Q or R but not P

c + z + a \(\to \) number of people eating P or R but not Q.

a + b + c \(\to \) number of people eating only one fruit

x + y + z \(\to \) number of people eating only two fruits

k \(\to \) number of people eating all of three fruits

(a + b + c) + (x + y + z) + (k ) \(\to \) number of people eating atleast one fruit

(z)+(\(\to \) number of people eating atleast two fruits

(c)+(x+ z) + (k\(\to \) total number of people eating fruit..

Finding the Values of Components

P + Q + R = (a + x + k + z) + (b + x + k + y) + (c + y + k + z)

P + Q+ R = (a + b + c) + 2(x + y + z) + 3k

P + Q + R = α + 2β + 3γ

where α = a + b + c,  β = x + y + z, γ = k

Again. (x + k)+(y + k)+(z + k) = (x+ y + z) + 3k = β + 3γ

(α +2β +3γ) −(β +3γ)

α +β (α +β + γ ) − (α +β) = γ

* ‘And’ means intersection, ‘or’ means union


Previous year CAT questions

Ques 1: In a class of 100 students, 73 like coffee, 80 like tea and 52 like lemonade. It may be possible that some students do not like any of these three drinks. Then the difference between the maximum and minimum possible number of students who like all the three drinks is __ (CAT 2022 Slot 1)

  1. 52
  2. 47
  3. 48
  4. 53

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Ans: (B)

Maximum number of students who can drink all three drinks = 52

Student liking exactly one drink = x

Student liking exactly two drink = y

Student liking exactly three drink = z

Student liking exactly no drink = n

x+2y+3z =73+80+52 =205

If x = z = 0 and y = 100 then x + 2y + 3z = 200

So, c cannot be zero

If we shift one student from y to z then sum will increase by 1

So, to increase the sum by 5, shift 5 students from y to z.

Therefore the least possible value of z = 5

Difference between maximum and minimum possible number of students who like all the drinks = 52 – 5 = 47

Ques 2: Students in a college have to choose at least two subjects from chemistry, mathematics and physics. The number of students choosing all three subjects is 18, choosing mathematics as one of their subjects is 23 and choosing physics as one of their subjects is 25. The smallest possible number of students who could choose chemistry as one of their subjects is __ (CAT 2020 Slot 2)

  1. 21
  2. 20
  3. 19
  4. 22

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Ans: (B)

Let Chemistry = C

Physics = P = 25

Mathematics = M = 23

As students will have to choose atleast two subjects then,

Students choosing single subject is = 0

[maximum students choosing both Mathematics and Physics]

So, Students choosing only physics = 25 -23 = 2

Least number of students who can choose chemistry = 18 +2 = 20

Ques 3: How many of the integers 1, 2, .., 120, are divisible by none of 2, 5 and 7? (CAT 2020 Slot 3)

  1. 42
  2. 41
  3. 40
  4. 43

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Ans: (B)

Out of 120 Numbers,

Integers not divisible by 2, 5 and 7 = 120 - (numbers that are divisible by at least one of 2, 5 and 7)

 n(A U B U C) = n(A) + n(B) + n(C) -n(AB) - n(BC) - n(C A) + n(A B C).

n(x) = number of multiples of x.

n(2 U 5 U 7) = n(2) + n(5) + n(7) – n(25) - n(57) –  n(7 2) + n(2 5 7).

n (2U5U7) = n(2) + n(5) + n(7) - n(10) - n(35) - n(14) + n(70)

 n(2 U5 U7) = 60 + 24 + 17 - 12 - 3 - 8 + 1 = 79.

Integers not divisible by 2, 5 and 7

= 120 - 79 = 41

Therefore, 41 numbers are not divisible by any of 2, 5 and 7

Answer the questions based on the following information.

A and B are two sets (e.g., A = mothers, B = women). The elements that could belong to both the sets (e.g., women who are mothers) is given by the set C = A B. The elements which could belong to either A or B, or both, is indicated by the set D = A B. A set that does not contain any elements is known as a null set, represented by φ (for example, if none of the women in the set B is a mother, then C = A. B is a null set, or C = φ).
 

Let ‘V’ signify the set of all vertebrates; ‘M’ the set of all mammals; ‘D’ dogs, ‘F’ fish; ‘A ’ Alsatian and ‘P’, a dog named Pluto. (CAT 2001)

Ques 4: If P ⋅ A = φ and P ∪ A = D, then which of the following is true?

  1. Pluto and alsatians are dogs
  2.  Pluto is an alsatian
  3. Pluto is not an alsatian
  4. D is a null set

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Ans: (C)

P⋅A=φ;

P∪A=D

P ∩ A = φ means no alsations are Pluto or

 Pluto is not an alsation where dogs are composed of alsation or Pluto or both.

Ques 5: If Z = ( P ⋅ D) ∪ M , then

  1. The elements of Z consist of Pluto, the dog or any other mammal
  2. Z implies any dog or mammal
  3. Z implies Pluto or any dog that is a mammal
  4. Z is a null set

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Ans: (A)

Z =(P⋅D)∪M,

Z =(P∩D)∪M P ∩ D means Pluto, the dog.

P ∩ D ∪ M means pluto, the dog or any other mammal.

Ques 6: If Y = F ⋅(D⋅V), is not a null set, it implies that

  1. all fish are vertebrates
  2. all dogs are vertebrates
  3. some fish are dogs
  4. None of these 

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Ans: (C)

Y = F ∩ (D ∩ V ) is not a null set means some F’s are D’s and some D’s are V ’s. That means some fish are dogs.

Ques 7: Given that X = M ⋅ D is such that X = D, which of the following is true?

  1. All dogs are mammals
  2. X = φ
  3. Some dogs are mammals
  4.  All mammals are dogs

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Ans: (A)

The shaded region is represented by the relationship X = M ⋅ D.

Now, it is given that M ∪ D = D.

Ques 8: Out of two-thirds of the total number of basketball matches, a team has won 17 matches and lost 3 of them. What is the maximum number of matches that the team can lose and still win more than three-fourths of the total number of matches, if it is true that no match can end in a tie?

  1. 4
  2. 6
  3. 5
  4. 3

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Ans: (A)

Number of matches played by the team = (17 + 3) = 20

 \(\frac{2}{3}rd\) of the matches = 20

Total number of matches = (3/2) x 20 = 30.

If the team has to win (3/4) × 30 = 22.5 matches or 23.

As the team has already lost 3 matches,

Maximum loss the team can sustain = (7 − 3) = 4 matches

Answer the questions based on the following information

A survey of 200 people in a community who watched at least one of the three channels BBC, CNN and DD-showed that 80% of the people watched DD, 22% watched BBC and 15% watched CNN. (CAT 1997)

Ques 9: If 5% of people watched DD and CNN, 10% watched DD and BBC, then what percentage of people watched BBC and CNN only?

  1. 2%
  2. 5%
  3. 8.5%
  4. Cannot be determined

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Ans: (A)

The shaded portion represents the area which shows people who do not watch DD channel. Since 80% watch DD, hence 20% do not watch DD. Let those who watch BBC and CNN only be x%, then

venn diagram

12+10-x = 20

x = 2

2% watch BBC and CNN only.

Ques 10:  Referring to the previous question, what percentage of people watched all the three channels?

  1. 3.5%
  2. 0%
  3. 8.5%
  4. Cannot be determined

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Ans: (D)

percentage of those who watch BBC and CNN or those who watch DD only this question cannot be answered.

Ques 11: What is the maximum percentage of people who can watch all the three channels?

  1. 12.5%
  2. 8.5%
  3. 15%
  4. Data insufficient

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venn diagram

Ans: (C)

People who watch all three stations are represented by the shaded area. Now, to figure out the highest number, we have to assume that 0% of people watch two channels and 0% of people only watch CNN.

venn diagram

It is clear that the most people who can watch all three stations are those who have CNN, which has the least number of people who can watch it. So, the correct answer is (c).

Ques 12: In a locality, two-thirds of the people have cable TV, one-fifth have VCR and one-tenth have both. What is the fraction of people having either cable TV or VCR ? (CAT 1996)

  1. 19/30
  2. 2/3
  3. 17/30
  4. 23/30

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Ans: (B)

Fraction of people who watch cable only = \((\frac{2}{3} - \frac{1}{10})= \frac{17}{13}\)

venn diagram

Fraction of people who watch cable only = \((\frac{1}{5} - \frac{1}{10})= \frac{1}{10}\)

Therefore, fraction of people who watch either cable = \((\frac{17}{30}+ \frac{1}{10}) = \frac{2}{3}\)

Answer the questions based on the following information

Ghosh Babu is staying at Ghosh Housing Society, Aghosh Colony, Dighospur, Kolkata. In Ghosh Housing Society, 6 persons read daily. The Ganashakti and4 persons read The Anand Bazar Patrika. In his colony, there is no person who reads both. Total number of persons who read these two newspapers in Aghosh Colony and Dighospur is 52 and 200, respectively. Number of persons who read The Ganashakti in Aghosh Colony and Dighospur is 33 and 121 respectively, while the persons who read The Anand Bazar Patrika in Aghosh Colony and Dighospur are 32 and 117, respectively. ( CAT 1994)

Ques 13: The number of persons in Aghosh Colony who read only one newspaper is __ .

  1. 29
  2. 39
  3. 19
  4. 20

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Ans: (B)

venn diagram

Persons reading Ganashakti only = (33 − 13) = 20

Persons reading Anand Bazar Patrika only= (32 − 13) = 19

Hence, Number of persons reading read only one newspaper = 20 + 19 = 39

Ques 14: The number of persons in Aghosh Colony who read both the newspapers is __ .

  1. 13
  2. 38
  3. 9
  4. 14

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Ans: (A)

venn diagram

Number of persons reading both the papers in Aghosh Colony = 33 + 32 − 52 =13

Ques 15: Number of persons in Dighospur who read only The Ganashakti is __ .

  1. 121
  2. 79
  3. 83
  4. 127

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Ans: (B)

venn diagram

Number of persons who read both the papers in Dighospur = 117 + 121 − 200 = 38

Number of persons who read Ganashakti only = 121 − 38 = 83


How to approach Set theory questions in CAT

  • Students before attempting questions should remember Algebraic law, important results and Venn Diagrams using three variables/ three circles.
  • Analytical skills of segregating one from other will be used in this topic and eventually one can connect with the Algebraic laws of set and Venn Diagrams.
  • Approach with two variables questions and slowly amplify to four variables.

Practicing these type of question will help you solve DILR sets

CAT Related Questions

1.
In September, the incomes of Kamal, Amal and Vimal are in the ratio 8 ∶ 6 ∶ 5. They rent a house together, and Kamal pays 15%, Amal pays 12% and Vimal pays 18% of their respective incomes to cover the total house rent in that month. In October, the house rent remains unchanged while their incomes increase by 10%, 12% and 15%, respectively. In October, the percentage of their total income that will be paid as house rent, is nearest to

    • 14.84
    • 13.26
    • 15.18
    • 12.75

    2.
    ABCD is a rectangle with sides AB = 56 cm and BC = 45 cm, and E is the midpoint of side CD. Then, the length, in cm, of radius of incircle of \(\triangle ADE\) is

        3.
        Let $x$ be a positive real number such that $4 \log_{10} x + 4 \log_{100} x + 8 \log_{1000} x = 13$ , then the greatest integer not exceeding $x$. is

            4.
            An amount of Rs 10000 is deposited in bank A for a certain number of years at a simple interest of 5% per annum. On maturity, the total amount received is deposited in bank B for another 5 years at a simple interest of 6% per annum. If the interests received from bank A and bank B are in the ratio 10 : 13, then the investment period, in years, in bank A is

              • 5
              • 3
              • 6
              • 4

              5.
              In the $XY$-plane, the area, in sq. units, of the region defined by the inequalities $y \ge x + 4$ and $-4 \le x^2 + y^2 + 4(x - y) \le 0$ is

                • \(2\pi\)
                • \(3\pi\)
                • \(\pi\)
                • \(4\pi\)

                6.
                The surface area of a closed rectangular box, which is inscribed in a sphere, is 846 sq cm, and the sum of the lengths of all its edges is 144 cm. The volume, in cubic cm, of the sphere is ?

                  • \(1125\pi\sqrt{2}\)
                  • \(750\pi\)
                  • \(750\pi\sqrt{2}\)
                  • \(1125\pi\)

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