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Question:
The transition metal (M) complex that can have all isomers (geometric, linkage, and ionization) is
The transition metal (M) complex that can have all isomers (geometric, linkage, and ionization) is
Updated On: Oct 1, 2024
- [M(NH3)4Br2]SCN
- [M(NH3)4Cl2]Br
- [M(NH3)4(H2O)2]Cl3
- [M(NH3)4 (H2O)2](SCN)3
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The Correct Option is A
Solution and Explanation
The correct option is (A): [M(NH3)4Br2]SCN
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