Question:

The coefficient of $x^{24}$ in the expansion of $\left(1+x^{2}\right)^{12}\left(1+x^{12}\right)\left(1+x^{24}\right)$ is

Updated On: May 21, 2024
  • ${ }^{12} C_{6}$
  • ${ }^{12} C_{6}+2$
  • ${ }^{12} C_{6}+4$
  • ${ }^{12} C_{6}+6$
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The Correct Option is B

Solution and Explanation

Now, $\left(1+x^{2}\right)^{12}\left(1+x^{12}+x^{24}+x^{36}\right)$
$=\left[1+{ }^{12} C_{1}\left(x^{2}\right)+{ }^{12} C_{2}\left(x^{2}\right)^{2}+{ }^{12} C_{3}\left(x^{2}\right)^{3}\right.$
$+{ }^{12} C_{4}\left(x^{2}\right)^{4}+{ }^{12} C_{5}\left(x^{2}\right)^{5}+{ }^{12} C_{6}\left(x^{2}\right)^{6}$
$\left.+\ldots+{ }^{12} C_{12}\left(x^{2}\right)^{12}\right] \times\left(1+x^{12}+x^{24}+x^{36}\right)$
Coefficient of $x^{24}={ }^{12} C_{6}+{ }^{12} C_{12}+1$
$={ }^{12} C_{6}+2$
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Concepts Used:

Binomial Expansion Formula

The binomial expansion formula involves binomial coefficients which are of the form 

(n/k)(or) nCk and it is calculated using the formula, nCk =n! / [(n - k)! k!]. The binomial expansion formula is also known as the binomial theorem. Here are the binomial expansion formulas.

This binomial expansion formula gives the expansion of (x + y)n where 'n' is a natural number. The expansion of (x + y)n has (n + 1) terms. This formula says:

We have (x + y)n = nC0 xn + nC1 xn-1 . y + nC2 xn-2 . y2 + … + nCn yn

General Term = Tr+1 = nCr xn-r . yr

  • General Term in (1 + x)n is nCr xr
  • In the binomial expansion of (x + y)n , the rth term from end is (n – r + 2)th .