To determine the number of ambidentate ligands among the given species, we first need to understand what constitutes an ambidentate ligand. An ambidentate ligand can coordinate to a metal ion through two different atoms. We will analyze each ligand:
Thus, the ambidentate ligands among the listed are \(\text{NO}_2^{-}\), \(\text{SCN}^{-}\), and \(\text{CN}^{-}\). This gives us a total of 3 ambidentate ligands, which is within the specified range (3,3).
Step 1: Define ambidentate ligands
Ambidentate ligands are ligands that can coordinate to a metal center through two different atoms.
Step 2: Analyze the ligands
Step 3: Count ambidentate ligands
Ambidentate ligands are:
\[ \text{NO}_2^-, \, \text{SCN}^-, \, \text{CN}^-. \] Total number = 3.
Thus, the correct answer: 3.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,