Content Curator | Updated On - May 24, 2024
AP ECET 2024 Electronics and Instrumentation Engineering Question Paper is available for download here. JNTU Anantapur on behalf of APSCHE conducted AP ECET 2024 on May 8 Shift 2. AP ECET 2024 Electronics and Instrumentation Engineering Question Paper consists of 25 questions from Physics and Chemistry each, 50 questions from Mathematics and 100 questions from Electronics and Instrumentation Engineering to be attempted in the duration of 3 hours.
AP ECET 2024 EIE Question Paper with Answer Key PDF
| AP ECET 2024 EIE Question Paper | AP ECET 2024 EIE Answer Key |
|---|---|
| Download PDF | Available Soon |
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AP ECET Questions
1. Number of ways of forming a committee of $6$ members out of $5$ Indians, $5$ Americans and $5$ Australians such that there will be atleast one member from each country in the committee is
Number of ways of forming a committee of $6$ members out of $5$ Indians, $5$ Americans and $5$ Australians such that there will be atleast one member from each country in the committee is
- 3375
- 4375
- 3875
- 4250
2. If $I_{n} = \int \frac{\sin nx}{\sin x} dx $ for $n = 1, 2 , 3,...,$ then $I_6$ =
If $I_{n} = \int \frac{\sin nx}{\sin x} dx $ for $n = 1, 2 , 3,...,$ then $I_6$ =
- $\frac{3}{5} \sin3x + \frac{8}{3} \sin^{5} x -\sin x +c $
- $\frac{2}{5} \sin 5x - \frac{5}{3} \sin^{3} x - 2 \sin x +c $
- $\frac{2}{3} \sin 5x - \frac{8}{3} \sin^{5} x + 4 \sin x +c $
- $\frac{2}{5} \sin 5 x -\frac{8}{3} \sin^{3} x + 4 \sin x +c $
3. A proton and an $\alpha$-particle are simultaneously projected in opposite directions into a region of uniform magnetic field of $2\, mT$ perpendicular to the direction of the field. After some time it is found that the velocity of proton has changed in direction by $90^{\circ}$. Then at this tune, the angle between the velocity vectors of proton and $\alpha$ - particle is
A proton and an $\alpha$-particle are simultaneously projected in opposite directions into a region of uniform magnetic field of $2\, mT$ perpendicular to the direction of the field. After some time it is found that the velocity of proton has changed in direction by $90^{\circ}$. Then at this tune, the angle between the velocity vectors of proton and $\alpha$ - particle is
- $60^{\circ}$
- $90^{\circ}$
- $45^{\circ}$
- $180^{\circ}$
4. The half-life periods of a first order reaction at $300\, K$ and $400\, K$ are $50\, s$ and $10\, s$ respectively.
The activation energy of the reaction in $kJ \; mol^{-1}$ is (log 5 = 0.70)
The half-life periods of a first order reaction at $300\, K$ and $400\, K$ are $50\, s$ and $10\, s$ respectively.
The activation energy of the reaction in $kJ \; mol^{-1}$ is (log 5 = 0.70)
- 4
- 8
- 16.1
- 20.1
5. A solution is prepared by dissolving $10 \,g$ of a non-volatile solute (molar mass, $'M^{\prime} g mol ^{-1}$ ) in $360\, g$ of water. What is the molar mass in $g\, mol ^{-1}$ of solute if the relative lowering of vapour pressure of solution is $5 \times 10^{-3}$ ?
A solution is prepared by dissolving $10 \,g$ of a non-volatile solute (molar mass, $'M^{\prime} g mol ^{-1}$ ) in $360\, g$ of water. What is the molar mass in $g\, mol ^{-1}$ of solute if the relative lowering of vapour pressure of solution is $5 \times 10^{-3}$ ?
- 199
- 99.5
- 299
- 149.5
6. Let $M$ and $m$ respectively denote the maximum and the minimum values of $[f(\theta)]^{2}$, where $f(\theta)=\sqrt{a^{2} \cos ^{2} \theta+b^{2} \sin ^{2} \theta}$
$+\sqrt{a^{2} \sin ^{2} \theta+b^{2} \cos ^{2} \theta}$. Then $M-m=$
Let $M$ and $m$ respectively denote the maximum and the minimum values of $[f(\theta)]^{2}$, where $f(\theta)=\sqrt{a^{2} \cos ^{2} \theta+b^{2} \sin ^{2} \theta}$
$+\sqrt{a^{2} \sin ^{2} \theta+b^{2} \cos ^{2} \theta}$. Then $M-m=$
- $a^2 + b^2$
- $(a -b)^2$
- $a^2 b^2$
- $(a + b)^2$
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