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AP ECET 2017 Computer Science and Engineering Question Paper with Answer Key pdf is available for download. The exam was conducted by Jawaharlal Nehru Technological University, Ananthapur on May 3, 2017 in the Forenoon Session 10 AM to 1 PM. The question paper comprised a total of 200 questions.
AP ECET 2017 Computer Science and Engineering Question Paper with Answer Key PDF
| AP ECET 2017 Computer Science and Engineering Question Paper PDF | AP ECET 2017 Computer Science and Engineering Answer Key PDF |
|---|---|
| Download PDF | Download PDF |
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AP ECET Questions
1. Magnesium is burnt in air to form $A$ and $B$. When $B$ is hydrolysed, $C$ and $D$ are formed. $D$ is the reactant in the manufacture of nitric acid by Ostwald's process. What is $C$
Magnesium is burnt in air to form $A$ and $B$. When $B$ is hydrolysed, $C$ and $D$ are formed. $D$ is the reactant in the manufacture of nitric acid by Ostwald's process. What is $C$
- $\ce{NH_3}$
- $\ce{Mg(OH)_2}$
- $MgO$
- $NO$
2. If $I_{n} = \int \frac{\sin nx}{\sin x} dx $ for $n = 1, 2 , 3,...,$ then $I_6$ =
If $I_{n} = \int \frac{\sin nx}{\sin x} dx $ for $n = 1, 2 , 3,...,$ then $I_6$ =
- $\frac{3}{5} \sin3x + \frac{8}{3} \sin^{5} x -\sin x +c $
- $\frac{2}{5} \sin 5x - \frac{5}{3} \sin^{3} x - 2 \sin x +c $
- $\frac{2}{3} \sin 5x - \frac{8}{3} \sin^{5} x + 4 \sin x +c $
- $\frac{2}{5} \sin 5 x -\frac{8}{3} \sin^{3} x + 4 \sin x +c $
3. If $I(x)=\int x^{2}(\log x)^{2} d x$ and $I( 1)=0$, then $I(x)$
If $I(x)=\int x^{2}(\log x)^{2} d x$ and $I( 1)=0$, then $I(x)$
- $\frac{x^{3}}{18} \left[ 8\left(\log x\right)^{2} -3\log x\right] + \frac{7}{18} $
- $\frac{x^{3}}{27} \left[9\left(\log x\right)^{2} +6 \log x\right] - \frac{2}{27} $
- $\frac{x^{3}}{27} \left[9\left(\log x\right)^{2} - 6 \log x+2\right]- \frac{2}{27} $
- $\frac{x^{3}}{27} \left[9 \left(\log x\right)^{2} -6 \log x +2 \right] - \frac{2}{27}$
4. The half-life periods of a first order reaction at $300\, K$ and $400\, K$ are $50\, s$ and $10\, s$ respectively.
The activation energy of the reaction in $kJ \; mol^{-1}$ is (log 5 = 0.70)
The half-life periods of a first order reaction at $300\, K$ and $400\, K$ are $50\, s$ and $10\, s$ respectively.
The activation energy of the reaction in $kJ \; mol^{-1}$ is (log 5 = 0.70)
- 4
- 8
- 16.1
- 20.1
5. A proton and an $\alpha$-particle are simultaneously projected in opposite directions into a region of uniform magnetic field of $2\, mT$ perpendicular to the direction of the field. After some time it is found that the velocity of proton has changed in direction by $90^{\circ}$. Then at this tune, the angle between the velocity vectors of proton and $\alpha$ - particle is
A proton and an $\alpha$-particle are simultaneously projected in opposite directions into a region of uniform magnetic field of $2\, mT$ perpendicular to the direction of the field. After some time it is found that the velocity of proton has changed in direction by $90^{\circ}$. Then at this tune, the angle between the velocity vectors of proton and $\alpha$ - particle is
- $60^{\circ}$
- $90^{\circ}$
- $45^{\circ}$
- $180^{\circ}$
6. A solution is prepared by dissolving $10 \,g$ of a non-volatile solute (molar mass, $'M^{\prime} g mol ^{-1}$ ) in $360\, g$ of water. What is the molar mass in $g\, mol ^{-1}$ of solute if the relative lowering of vapour pressure of solution is $5 \times 10^{-3}$ ?
A solution is prepared by dissolving $10 \,g$ of a non-volatile solute (molar mass, $'M^{\prime} g mol ^{-1}$ ) in $360\, g$ of water. What is the molar mass in $g\, mol ^{-1}$ of solute if the relative lowering of vapour pressure of solution is $5 \times 10^{-3}$ ?
- 199
- 99.5
- 299
- 149.5
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